1. 如图, 在四边形 $ABCD$ 中, $∠ BAD = 110°, ∠ B = ∠ D = 90°$, 在 $BC, CD$ 上分别找一点 $M, N$, 使 $△ AMN$ 的周长最小, 此时 $∠ AMN + ∠ ANM$ 的度数和为( )
A. $110°$
B. $120°$
C. $130°$
D. $140°$


A. $110°$
B. $120°$
C. $130°$
D. $140°$
答案
D
2. 新素养 推理能力 如图,$∠ AOB=120°$,$OP$平分$∠ AOB$. 若$M,N$两点分别在$OA$,$OB$上,且$△ PMN$为等边三角形,则满足上述条件的$△ PMN$有 ( )
A. 1个
B. 2个
C. 3个
D. 无数个
A. 1个
B. 2个
C. 3个
D. 无数个
答案
D
3. 如图,在 $△ ABC$ 中,$AC = BC = 5$,$∠ ACB = 80°$,$O$ 为 $△ ABC$ 内部一点,$∠ OAB = 10°$,$∠ OBA = 30°$,则 $AO$ 的长是______.


答案
5
4. (2025·江苏扬州模拟)如图,四边形ABCD的对角互补,且∠BAC=∠DAC,AB=15,AD=12.过顶点C作CE⊥AB于点E,则$\frac{AE}{BE}$的值为$\underline{\hspace{5cm}}$.
答案
9
5. 如图,在$△ ABC$中,$∠ A=20°$,$AB=AC$,D是边AC上一点,连接BD,$AD=BC$,则$∠ DBA$的度数为______.


(第5题)
(第7题)
(第5题)
(第7题)
答案
10°
6. (2025·江苏泰州模拟)已知在$\mathrm{Rt}△ ABC$中,$∠ ACB=90°$,$∠ A=n°$.当$n$变化时,斜边$AB$上总存在$O,P$两点,使得$OC=CP=\frac{1}{2}AB$($O,P$两点不重合),则$n$的取值范围为$\underline{\hspace{5cm}}$.
答案
30≤n≤60且n≠45
7. 如图,在$△ ABC$中,$AB=8$,$AC=5$,点$D$在$△ ABC$内部,连接$AD$,$BD$,$CD$,$∠ ADB=150°$,$∠ DBC=30°$,$∠ ABC + ∠ ADC=180°$,则$CD$的长为______.
答案
3
8. 如图,在$△ ABC$中,$∠ ABC=45°$,点$D$在边$BC$上,$∠ ADC=60°$,且$BD=\frac{1}{2}CD$.将$△ ACD$以直线$AD$为轴做轴对称变换,得到$△ AC'D$,连接$BC'$.
(1) 求证:$BC' ⊥ BC$;
(2) 求$∠ C$的度数.

(1) 求证:$BC' ⊥ BC$;
(2) 求$∠ C$的度数.
答案
; $(1) $证明:由题意得$\triangle AC'D≌\triangle ACD$∴$∠ADC' = ∠ADC,$$∠AC'D = ∠C,$$C'D = CD$又$∠ADC = 60°,$$∠BDC'+∠ADC'+∠ADC = 180°$∴$∠BDC' = 60°$在边$C'D$上取一点$P,$使$P D = BD,$连接$P B$则$\triangle BDP $是等边三角形∴$BP = BD = P D,$$∠P BD = ∠BP D = 60°$又$BD=\frac 12CD,$∴$BD = \frac 12C'D,$即$P C' = P D = BP$∴$∠BC'P=∠P BC'$又$∠BP D=∠BC'P+∠P BC'$∴$∠BC'P=∠P BC'=\frac 12∠BP D = 30°$即$∠C'BD=∠P BC'+∠P BD = 90°$∴$BC'\perp BC$$(2) $解:过点$A$分别作$BC,$$C'D,$$BC'$的垂线,垂足分别为$E,$$F,$$G$由$(1)$得$∠AC'D = ∠C,$$∠BC'P = 30°,$$∠ADC' = ∠ADC,$$∠C'BD = 90°$∴$DA$平分$∠CDC,$即$AE = AF$又$∠C'BD=∠ABC+∠ABC',$$∠ABC = 45°$∴$∠ABC' = 45°,$即$∠ABC'=∠ABC$∴$AB$平分$∠C'BD,$即$AE = AG$∴$AF = AG$在$Rt\triangle AC'F $和$Rt\triangle AC'G $中$\begin {cases}AG = AF\\AC' = AC'\end {cases}$∴$Rt\triangle AC'F≌ Rt\triangle AC'G(\mathrm {HL})$∴$∠AC'F=∠AC'G$又$∠BC'P+∠AC'F+∠AC'G = 180°$∴$∠AC'F=\frac 12(180°-∠BC'P)=75°,$即$∠C = 75°$
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