1. 计算$(-\frac{b}{2a})^{3}$的结果是(
A.$-\frac{b^{3}}{2a^{3}}$
B.$-\frac{b^{3}}{6a^{3}}$
C.$-\frac{b^{3}}{8a^{3}}$
D.$\frac{b^{3}}{8a^{3}}$
C
)A.$-\frac{b^{3}}{2a^{3}}$
B.$-\frac{b^{3}}{6a^{3}}$
C.$-\frac{b^{3}}{8a^{3}}$
D.$\frac{b^{3}}{8a^{3}}$
答案
1. C
2. 计算:$(\frac{2x}{y})^{2}=$
$\dfrac{4x^{2}}{y^{2}}$
.答案
2. $\dfrac{4x^{2}}{y^{2}}$
3. 计算$\frac{a}{b}·\frac{b}{a^{2}}$的结果为(
A.$\frac{1}{a}$
B.$\frac{1}{b}$
C.$\frac{b}{a}$
D.$\frac{a}{b}$
A
)A.$\frac{1}{a}$
B.$\frac{1}{b}$
C.$\frac{b}{a}$
D.$\frac{a}{b}$
答案
3. A
4. 计算$-\frac{n}{m^{2}}÷\frac{n^{2}}{m^{2}}$的结果是(
A.$-\frac{n}{m}$
B.$-\frac{1}{m}$
C.$-\frac{1}{n}$
D.$-n$
C
)A.$-\frac{n}{m}$
B.$-\frac{1}{m}$
C.$-\frac{1}{n}$
D.$-n$
答案
4. C
5. 计算:$x^{2}y·\frac{z}{xy}=$
$xz$
.答案
5. $xz$
6. 计算$\frac{y^{2}}{6x}÷\frac{y}{3x^{2}}$的结果是
$\dfrac{xy}{2}$
.答案
6. $\dfrac{xy}{2}$
7. 计算:
(1)$\frac{3x}{8y}·\frac{16y^{2}}{27x^{2}}$;
(2)$\frac{a}{6b}·(\frac{3b}{a})^{2}$;
(3)$3xy^{2}÷\frac{6y^{2}}{x}$;
(4)$\frac{x}{5y}÷(-\frac{4x^{2}}{5y^{2}})·\frac{2x^{2}}{y}$.
(1)$\frac{3x}{8y}·\frac{16y^{2}}{27x^{2}}$;
(2)$\frac{a}{6b}·(\frac{3b}{a})^{2}$;
(3)$3xy^{2}÷\frac{6y^{2}}{x}$;
(4)$\frac{x}{5y}÷(-\frac{4x^{2}}{5y^{2}})·\frac{2x^{2}}{y}$.
答案
7. (1)$\dfrac{2y}{9x}$ (2)$\dfrac{3b}{2a}$ (3)$\dfrac{1}{2}x^{2}$ (4)$-\dfrac{x}{2}$
8. 化简$\frac{m^{2}-1}{m}·\frac{1}{m + 1}$的结果为(
A.$\frac{m}{m + 1}$
B.$\frac{m - 1}{m + 1}$
C.$\frac{m - 1}{m}$
D.$\frac{m + 1}{m}$
C
)A.$\frac{m}{m + 1}$
B.$\frac{m - 1}{m + 1}$
C.$\frac{m - 1}{m}$
D.$\frac{m + 1}{m}$
答案
8. C
9. 化简$\frac{m^{2}}{m - 3}÷\frac{2m}{m - 3}$的结果是(
A.2
B.$\frac{m}{2}$
C.$m$
D.$\frac{1}{2}$
B
)A.2
B.$\frac{m}{2}$
C.$m$
D.$\frac{1}{2}$
答案
9. B
10. 计算:$\frac{x^{2}+xy}{xy}·\frac{y^{2}}{x + y}=$
$y$
.答案
10. $y$
11. 计算:$\frac{1}{x - 2}÷\frac{x + 2}{x^{2}-4}=$
1
.答案
11. 1
12. 计算:(1)$\frac{2x - 6}{x^{2}-4x + 4}·\frac{2x - 4}{x - 3}$;
(2)$(2xy - x^{2})÷\frac{x - 2y}{xy}$;
(3)$\frac{2a - 4}{a^{2}-1}÷\frac{2 - a}{a^{2}-2a + 1}$.
(2)$(2xy - x^{2})÷\frac{x - 2y}{xy}$;
(3)$\frac{2a - 4}{a^{2}-1}÷\frac{2 - a}{a^{2}-2a + 1}$.
答案
12. (1)$\dfrac{4}{x - 2}$ (2)$-x^{2}y$ (3)$\dfrac{2 - 2a}{a + 1}$
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