11.如图,半径为单位1的圆从原点沿着数轴无滑动地逆时针滚动一周到达A点,则A点表示的数是

$-2π$
.答案
11.$-2π$
12.若$\sqrt{5}$的整数部分是$a$,小数部分是$b$,则$\sqrt{5}a - b=$______.
答案
12.$\sqrt{5}+2$
13.对于正实数$a,b$做新定义:$a*b = b\sqrt{a} - a + b$,在此定义下,若$9*x = 55$,则$x$的值为________.
答案
13.16
三、解答题
14.把下列各数填入相应的括号里.
$-2,100π,-5 \frac{1}{3},0.8,-|+5.2|,0,0.101\ 001\ 000\ 1···,-(-4 \frac{1}{3}).$
正有理数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ }; 负分数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ };
整数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ }; 无理数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ }.
14.把下列各数填入相应的括号里.
$-2,100π,-5 \frac{1}{3},0.8,-|+5.2|,0,0.101\ 001\ 000\ 1···,-(-4 \frac{1}{3}).$
正有理数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ }; 负分数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ };
整数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ }; 无理数集合:{ $\qquad\qquad\qquad\qquad\qquad\qquad\qquad$ }.
答案
14.正有理数集合:$\{0.8,-(-4\dfrac{1}{3})\}$
整数集合:$\{-2,0\}$
负分数集合:$\{-5\dfrac{1}{3},-|+5.2|\}$
无理数集合:$\{100π,0.101\ 001\ 000\ 1···\}$
整数集合:$\{-2,0\}$
负分数集合:$\{-5\dfrac{1}{3},-|+5.2|\}$
无理数集合:$\{100π,0.101\ 001\ 000\ 1···\}$
15.计算:
(1)$|-2|-\sqrt{4}+3^{2}$;
(2)$\sqrt[3]{8}+|-5|+(-1)^{2025}$.
(3)$|2-\sqrt{5}|+|3-\sqrt{5}|$;
(4)$|\sqrt{2}-\sqrt{3}|+2\sqrt{2}-\sqrt{3}$.
(1)$|-2|-\sqrt{4}+3^{2}$;
(2)$\sqrt[3]{8}+|-5|+(-1)^{2025}$.
(3)$|2-\sqrt{5}|+|3-\sqrt{5}|$;
(4)$|\sqrt{2}-\sqrt{3}|+2\sqrt{2}-\sqrt{3}$.
答案
15.(1)原式$=2-2+9=9$
(2)原式$=2+5-1=6$
(3)原式$=\sqrt{5}-2+3-\sqrt{5}=1$
(4)原式$=\sqrt{3}-\sqrt{2}+2\sqrt{2}-\sqrt{3}=\sqrt{2}$
(2)原式$=2+5-1=6$
(3)原式$=\sqrt{5}-2+3-\sqrt{5}=1$
(4)原式$=\sqrt{3}-\sqrt{2}+2\sqrt{2}-\sqrt{3}=\sqrt{2}$
16.计算:
(1)$-2^{2}+\sqrt{(-1)^{2}}+|\sqrt{2}-2|$;
(2)$\sqrt{81}+\sqrt[3]{-27}÷ 3^{2}+(-1)^{2024}$。
(1)$-2^{2}+\sqrt{(-1)^{2}}+|\sqrt{2}-2|$;
(2)$\sqrt{81}+\sqrt[3]{-27}÷ 3^{2}+(-1)^{2024}$。
答案
16.(1)$-1-\sqrt{2}$
(2)$9\dfrac{2}{3}$
(2)$9\dfrac{2}{3}$
17.解方程:
(1)$(x-3)^2 + 1 = 26$;
(2)$2(x-3)^3 + \frac{1}{4} = 0$.
(1)$(x-3)^2 + 1 = 26$;
(2)$2(x-3)^3 + \frac{1}{4} = 0$.
答案
17.(1)$(x-3)^2=25,x-3=\pm5,\therefore x=8$或$x=-2$.
(2)$(x-3)^3=-\dfrac{1}{8},x-3=-\dfrac{1}{2},\therefore x=\dfrac{5}{2}$.
(2)$(x-3)^3=-\dfrac{1}{8},x-3=-\dfrac{1}{2},\therefore x=\dfrac{5}{2}$.
登录