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1. 直接写出得数。
$32×\frac{1}{72}=$ $\frac{1}{64}×56=$ $\frac{1}{3}×15.3=$
$\frac{3}{5}×\frac{3}{7}=$ $11×\frac{6}{121}=$ $\frac{4}{5}×\frac{7}{4}=$
$\frac{4}{9}×1\frac{3}{5}=$ $\frac{9}{6}×\frac{5}{6}=$ $\frac{7}{8}×\frac{8}{7}=$
$\frac{1}{25}×\frac{3}{8}=$ $\frac{5}{6}×\frac{1}{12}=$ $\frac{3}{5}×0.25=$
$0.2×\frac{2}{5}=$ $\frac{1}{8}×0.375=$ $12×\frac{5}{24}=$
$32×\frac{1}{72}=$ $\frac{1}{64}×56=$ $\frac{1}{3}×15.3=$
$\frac{3}{5}×\frac{3}{7}=$ $11×\frac{6}{121}=$ $\frac{4}{5}×\frac{7}{4}=$
$\frac{4}{9}×1\frac{3}{5}=$ $\frac{9}{6}×\frac{5}{6}=$ $\frac{7}{8}×\frac{8}{7}=$
$\frac{1}{25}×\frac{3}{8}=$ $\frac{5}{6}×\frac{1}{12}=$ $\frac{3}{5}×0.25=$
$0.2×\frac{2}{5}=$ $\frac{1}{8}×0.375=$ $12×\frac{5}{24}=$
答案
$32×\frac{1}{72}=\frac{32÷8}{72÷8}=\frac{4}{9}$
$\frac{1}{64}×56=\frac{56÷8}{64÷8}=\frac{7}{8}$
$\frac{1}{3}×15.3=15.3÷3=5.1$
$\frac{3}{5}×\frac{3}{7}=\frac{3×3}{5×7}=\frac{9}{35}$
$11×\frac{6}{121}=\frac{11×6}{121}=\frac{6}{11}$
$\frac{4}{5}×\frac{7}{4}=\frac{4×7}{5×4}=\frac{7}{5}$
$\frac{4}{9}×1\frac{3}{5}=\frac{4}{9}×\frac{8}{5}=\frac{4×8}{9×5}=\frac{32}{45}$
$\frac{9}{6}×\frac{5}{6}=\frac{9×5}{6×6}=\frac{45÷9}{36÷9}=\frac{5}{4}$
$\frac{7}{8}×\frac{8}{7}=1$
$\frac{1}{25}×\frac{3}{8}=\frac{1×3}{25×8}=\frac{3}{200}$
$\frac{5}{6}×\frac{1}{12}=\frac{5×1}{6×12}=\frac{5}{72}$
$\frac{3}{5}×0.25=\frac{3}{5}×\frac{1}{4}=\frac{3}{20}$
$0.2×\frac{2}{5}=\frac{1}{5}×\frac{2}{5}=\frac{2}{25}$
$\frac{1}{8}×0.375=\frac{1}{8}×\frac{3}{8}=\frac{3}{64}$
$12×\frac{5}{24}=\frac{12×5}{24}=\frac{5}{2}$
$\frac{1}{64}×56=\frac{56÷8}{64÷8}=\frac{7}{8}$
$\frac{1}{3}×15.3=15.3÷3=5.1$
$\frac{3}{5}×\frac{3}{7}=\frac{3×3}{5×7}=\frac{9}{35}$
$11×\frac{6}{121}=\frac{11×6}{121}=\frac{6}{11}$
$\frac{4}{5}×\frac{7}{4}=\frac{4×7}{5×4}=\frac{7}{5}$
$\frac{4}{9}×1\frac{3}{5}=\frac{4}{9}×\frac{8}{5}=\frac{4×8}{9×5}=\frac{32}{45}$
$\frac{9}{6}×\frac{5}{6}=\frac{9×5}{6×6}=\frac{45÷9}{36÷9}=\frac{5}{4}$
$\frac{7}{8}×\frac{8}{7}=1$
$\frac{1}{25}×\frac{3}{8}=\frac{1×3}{25×8}=\frac{3}{200}$
$\frac{5}{6}×\frac{1}{12}=\frac{5×1}{6×12}=\frac{5}{72}$
$\frac{3}{5}×0.25=\frac{3}{5}×\frac{1}{4}=\frac{3}{20}$
$0.2×\frac{2}{5}=\frac{1}{5}×\frac{2}{5}=\frac{2}{25}$
$\frac{1}{8}×0.375=\frac{1}{8}×\frac{3}{8}=\frac{3}{64}$
$12×\frac{5}{24}=\frac{12×5}{24}=\frac{5}{2}$
2. 解方程。
$\frac{3}{7}x=1$ $0.3x-0.3=0.7$ $2x+\frac{3}{4}=\frac{7}{4}$
$\frac{3}{7}x=1$ $0.3x-0.3=0.7$ $2x+\frac{3}{4}=\frac{7}{4}$
答案
解：$\frac{3}{7}x=1$
$x=1÷\frac{3}{7}$
$x=1×\frac{7}{3}$
$x=\frac{7}{3}$
解：$0.3x - 0.3 = 0.7$
$0.3x = 0.7 + 0.3$
$0.3x = 1$
$x = 1÷0.3$
$x = \frac{10}{3}$
解：$2x + \frac{3}{4} = \frac{7}{4}$
$2x = \frac{7}{4} - \frac{3}{4}$
$2x = 1$
$x = 1÷2$
$x = \frac{1}{2}$
$x=1÷\frac{3}{7}$
$x=1×\frac{7}{3}$
$x=\frac{7}{3}$
解：$0.3x - 0.3 = 0.7$
$0.3x = 0.7 + 0.3$
$0.3x = 1$
$x = 1÷0.3$
$x = \frac{10}{3}$
解：$2x + \frac{3}{4} = \frac{7}{4}$
$2x = \frac{7}{4} - \frac{3}{4}$
$2x = 1$
$x = 1÷2$
$x = \frac{1}{2}$
3. 脱式计算。
$\frac{5}{144}×12$ $\frac{10}{17}×\frac{1}{7}+\frac{6}{7}×\frac{10}{17}$ $\frac{5}{4}-(\frac{5}{8}-\frac{3}{8})$
$3-\frac{7}{23}-\frac{16}{23}$ $1-\frac{3}{4}×\frac{2}{7}$ $\frac{11}{12}×\frac{5}{6}-\frac{1}{12}$
$\frac{5}{144}×12$ $\frac{10}{17}×\frac{1}{7}+\frac{6}{7}×\frac{10}{17}$ $\frac{5}{4}-(\frac{5}{8}-\frac{3}{8})$
$3-\frac{7}{23}-\frac{16}{23}$ $1-\frac{3}{4}×\frac{2}{7}$ $\frac{11}{12}×\frac{5}{6}-\frac{1}{12}$
答案
$\frac{5}{144}×12$
$=\frac{5×12}{144}$
$=\frac{5}{12}$
$\frac{10}{17}×\frac{1}{7}+\frac{6}{7}×\frac{10}{17}$
$=\frac{10}{17}×(\frac{1}{7}+\frac{6}{7})$
$=\frac{10}{17}×1$
$=\frac{10}{17}$
$\frac{5}{4}-(\frac{5}{8}-\frac{3}{8})$
$=\frac{5}{4}-\frac{2}{8}$
$=\frac{5}{4}-\frac{1}{4}$
$=1$
$3-\frac{7}{23}-\frac{16}{23}$
$=3-(\frac{7}{23}+\frac{16}{23})$
$=3-1$
$=2$
$1-\frac{3}{4}×\frac{2}{7}$
$=1-\frac{6}{28}$
$=1-\frac{3}{14}$
$=\frac{11}{14}$
$\frac{11}{12}×\frac{5}{6}-\frac{1}{12}$
$=\frac{55}{72}-\frac{6}{72}$
$=\frac{49}{72}$
$=\frac{5×12}{144}$
$=\frac{5}{12}$
$\frac{10}{17}×\frac{1}{7}+\frac{6}{7}×\frac{10}{17}$
$=\frac{10}{17}×(\frac{1}{7}+\frac{6}{7})$
$=\frac{10}{17}×1$
$=\frac{10}{17}$
$\frac{5}{4}-(\frac{5}{8}-\frac{3}{8})$
$=\frac{5}{4}-\frac{2}{8}$
$=\frac{5}{4}-\frac{1}{4}$
$=1$
$3-\frac{7}{23}-\frac{16}{23}$
$=3-(\frac{7}{23}+\frac{16}{23})$
$=3-1$
$=2$
$1-\frac{3}{4}×\frac{2}{7}$
$=1-\frac{6}{28}$
$=1-\frac{3}{14}$
$=\frac{11}{14}$
$\frac{11}{12}×\frac{5}{6}-\frac{1}{12}$
$=\frac{55}{72}-\frac{6}{72}$
$=\frac{49}{72}$
