2026年计算素养提升六年级数学下册北师大版第42页答案
1. 解方程。
$x - 20\%x = 60$ $\frac{2}{3}:x = \frac{1}{4}:\frac{3}{8}$

答案

第一个方程:
解:
$x - 20\%x = 60$
$80\%x = 60$
$x = 60 ÷ 0.8$
$x = 75$
第二个方程:
解:
$\frac{2}{3}:x = \frac{1}{4}:\frac{3}{8}$
$\frac{1}{4}x = \frac{2}{3}×\frac{3}{8}$
$\frac{1}{4}x = \frac{1}{4}$
$x = \frac{1}{4}÷\frac{1}{4}$
$x = 1$
2. 脱式计算。(能简算的要简算)
$0.25×3.2×1.25$ $\frac{6}{7}×\frac{5}{8}÷\frac{3}{14}$
$29×\frac{17}{131} + \frac{29}{131}×114$ $(\frac{7}{10} - \frac{1}{6} + \frac{2}{3})÷\frac{7}{30}$
$6.3×2.8 + 6.3×7.2$ $10 - 3.47 - 1.53$
$\frac{5}{12}÷\frac{15}{18} - \frac{1}{6} + \frac{3}{4}$ $(4 - 7.5×\frac{4}{15})÷1\frac{1}{9}$
$450 + (8.16 + 6.84)÷0.6$ $\frac{7}{12}÷[(\frac{1}{4} + 1.25)×\frac{8}{9}] - \frac{1}{4}$

答案

$0.25×3.2×1.25$
$=0.25×(0.4×8)×1.25$
$=(0.25×0.4)×(8×1.25)$
$=0.1×10$
$=1$
$\frac{6}{7}×\frac{5}{8}÷\frac{3}{14}$
$=\frac{6}{7}×\frac{5}{8}×\frac{14}{3}$
$=(\frac{6}{7}×\frac{14}{3})×\frac{5}{8}$
$=4×\frac{5}{8}$
$=\frac{5}{2}$
$29×\frac{17}{131} + \frac{29}{131}×114$
$=\frac{29×17}{131} + \frac{29×114}{131}$
$=\frac{29×(17+114)}{131}$
$=\frac{29×131}{131}$
$=29$
$(\frac{7}{10} - \frac{1}{6} + \frac{2}{3})÷\frac{7}{30}$
$=(\frac{7}{10} - \frac{1}{6} + \frac{2}{3})×\frac{30}{7}$
$=\frac{7}{10}×\frac{30}{7} - \frac{1}{6}×\frac{30}{7} + \frac{2}{3}×\frac{30}{7}$
$=3 - \frac{5}{7} + \frac{20}{7}$
$=3 + \frac{15}{7}$
$=\frac{36}{7}$
$6.3×2.8 + 6.3×7.2$
$=6.3×(2.8+7.2)$
$=6.3×10$
$=63$
$10 - 3.47 - 1.53$
$=10 - (3.47+1.53)$
$=10 - 5$
$=5$
$\frac{5}{12}÷\frac{15}{18} - \frac{1}{6} + \frac{3}{4}$
$=\frac{5}{12}×\frac{18}{15} - \frac{1}{6} + \frac{3}{4}$
$=\frac{1}{2} - \frac{1}{6} + \frac{3}{4}$
$=\frac{6}{12} - \frac{2}{12} + \frac{9}{12}$
$=\frac{13}{12}$
$(4 - 7.5×\frac{4}{15})÷1\frac{1}{9}$
$=(4 - 2)÷\frac{10}{9}$
$=2×\frac{9}{10}$
$=\frac{9}{5}$
$450 + (8.16 + 6.84)÷0.6$
$=450 + 15÷0.6$
$=450 + 25$
$=475$
$\frac{7}{12}÷[(\frac{1}{4} + 1.25)×\frac{8}{9}] - \frac{1}{4}$
$=\frac{7}{12}÷[(\frac{1}{4} + \frac{5}{4})×\frac{8}{9}] - \frac{1}{4}$
$=\frac{7}{12}÷[\frac{3}{2}×\frac{8}{9}] - \frac{1}{4}$
$=\frac{7}{12}÷\frac{4}{3} - \frac{1}{4}$
$=\frac{7}{12}×\frac{3}{4} - \frac{1}{4}$
$=\frac{7}{16} - \frac{4}{16}$
$=\frac{3}{16}$