2025年学生基础性作业七年级数学上册人教版第48页答案
5. 化简:
(1) $ -\dfrac{21}{7} $;
(2) $ \dfrac{-40}{-16} $;
(3) $ -\dfrac{14}{-35} $;
(4) $ \dfrac{0}{-26} $.

答案

(1)-3;(2)$\frac{5}{2}$;(3)$\frac{2}{5}$;(4)0.

解析


(1) $-\dfrac{21}{7}=-3$;
(2) $\dfrac{-40}{-16}=\dfrac{40}{16}=\dfrac{5}{2}$;
(3) $-\dfrac{14}{-35}=\dfrac{14}{35}=\dfrac{2}{5}$;
(4) $\dfrac{0}{-26}=0$。
6. 计算:
(1) $ \left(-4\dfrac{2}{7}\right)÷15 $;
(2) $ \left(-\dfrac{12}{25}\right)÷\left(-\dfrac{4}{5}\right) $;
(3) $ 0÷(-0.618) $;
(4) $ (-1)÷6×\left(-\dfrac{1}{6}\right) $;
(5) $ -\dfrac{3}{4}×\left(-2\dfrac{1}{2}\right)÷1\dfrac{1}{2} $;
(6) $ \left(-1\dfrac{5}{12}\right)÷(-4)×\left(-1\dfrac{1}{5}\right) $.

答案

(1)$-\frac{2}{7}$;(2)$\frac{3}{5}$;(3)0;(4)$\frac{1}{36}$;(5)$\frac{5}{4}$;(6)$-\frac{17}{40}$.

解析


(1) $\left(-4\dfrac{2}{7}\right)÷15=-\dfrac{30}{7}×\dfrac{1}{15}=-\dfrac{2}{7}$;
(2) $\left(-\dfrac{12}{25}\right)÷\left(-\dfrac{4}{5}\right)=\dfrac{12}{25}×\dfrac{5}{4}=\dfrac{3}{5}$;
(3) $0÷(-0.618)=0$;
(4) $(-1)÷6×\left(-\dfrac{1}{6}\right)=(-1)×\dfrac{1}{6}×\left(-\dfrac{1}{6}\right)=\dfrac{1}{36}$;
(5) $-\dfrac{3}{4}×\left(-2\dfrac{1}{2}\right)÷1\dfrac{1}{2}=\dfrac{3}{4}×\dfrac{5}{2}×\dfrac{2}{3}=\dfrac{5}{4}$;
(6) $\left(-1\dfrac{5}{12}\right)÷(-4)×\left(-1\dfrac{1}{5}\right)=-\dfrac{17}{12}×\dfrac{1}{4}×\dfrac{6}{5}=-\dfrac{17}{40}$.