1. 涂一涂,算一算。
(1)

$ \frac{1}{3} + \frac{1}{9} = \frac{(\space)}{(\space)} + \frac{(\space)}{(\space)} = \frac{(\space)}{(\space)} $
(2)

$ \frac{1}{2} - \frac{1}{3} = \frac{(\space)}{(\space)} - \frac{(\space)}{(\space)} = \frac{(\space)}{(\space)} $
(1)
$ \frac{1}{3} + \frac{1}{9} = \frac{(\space)}{(\space)} + \frac{(\space)}{(\space)} = \frac{(\space)}{(\space)} $
(2)
$ \frac{1}{2} - \frac{1}{3} = \frac{(\space)}{(\space)} - \frac{(\space)}{(\space)} = \frac{(\space)}{(\space)} $
答案
(1)
$\frac{1}{3}+\frac{1}{9}=\frac{(3)}{(9)}+\frac{(1)}{(9)}=\frac{(4)}{(9)}$
(2)
$\frac{1}{2}-\frac{1}{3}=\frac{(3)}{(6)}-\frac{(2)}{(6)}=\frac{(1)}{(6)}$
$\frac{1}{3}+\frac{1}{9}=\frac{(3)}{(9)}+\frac{(1)}{(9)}=\frac{(4)}{(9)}$
(2)
$\frac{1}{2}-\frac{1}{3}=\frac{(3)}{(6)}-\frac{(2)}{(6)}=\frac{(1)}{(6)}$
2. 计算。
$ \frac{1}{5} + \frac{1}{10} = $
$ \frac{8}{15} - \frac{1}{5} = $
$ \frac{2}{3} + \frac{4}{21} = $
$ \frac{7}{9} - \frac{1}{4} = $
$ \frac{1}{2} - \frac{1}{7} = $
$ \frac{5}{8} - \frac{1}{4} = $
$ \frac{1}{2} + \frac{1}{5} = $
$ \frac{1}{3} + \frac{1}{4} = $
$ \frac{1}{5} + \frac{1}{10} = $
$ \frac{8}{15} - \frac{1}{5} = $
$ \frac{2}{3} + \frac{4}{21} = $
$ \frac{7}{9} - \frac{1}{4} = $
$ \frac{1}{2} - \frac{1}{7} = $
$ \frac{5}{8} - \frac{1}{4} = $
$ \frac{1}{2} + \frac{1}{5} = $
$ \frac{1}{3} + \frac{1}{4} = $
答案
$\frac{1}{5} + \frac{1}{10} = \frac{2}{10} + \frac{1}{10} = \frac{3}{10}$
$\frac{8}{15} - \frac{1}{5} = \frac{8}{15} - \frac{3}{15} = \frac{5}{15} = \frac{1}{3}$
$\frac{2}{3} + \frac{4}{21} = \frac{14}{21} + \frac{4}{21} = \frac{18}{21} = \frac{6}{7}$
$\frac{7}{9} - \frac{1}{4} = \frac{28}{36} - \frac{9}{36} = \frac{19}{36}$
$\frac{1}{2} - \frac{1}{7} = \frac{7}{14} - \frac{2}{14} = \frac{5}{14}$
$\frac{5}{8} - \frac{1}{4} = \frac{5}{8} - \frac{2}{8} = \frac{3}{8}$
$\frac{1}{2} + \frac{1}{5} = \frac{5}{10} + \frac{2}{10} = \frac{7}{10}$
$\frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}$
$\frac{8}{15} - \frac{1}{5} = \frac{8}{15} - \frac{3}{15} = \frac{5}{15} = \frac{1}{3}$
$\frac{2}{3} + \frac{4}{21} = \frac{14}{21} + \frac{4}{21} = \frac{18}{21} = \frac{6}{7}$
$\frac{7}{9} - \frac{1}{4} = \frac{28}{36} - \frac{9}{36} = \frac{19}{36}$
$\frac{1}{2} - \frac{1}{7} = \frac{7}{14} - \frac{2}{14} = \frac{5}{14}$
$\frac{5}{8} - \frac{1}{4} = \frac{5}{8} - \frac{2}{8} = \frac{3}{8}$
$\frac{1}{2} + \frac{1}{5} = \frac{5}{10} + \frac{2}{10} = \frac{7}{10}$
$\frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}$
3. 想一想,填一填。
(1)
| $$ \frac{1}{4} + \frac{1}{5} = $$ | $$ \frac{1}{5} + \frac{1}{6} = $$ | $$ \frac{1}{6} + \frac{1}{7} = $$ |
| --- | --- | --- |
| $$ \frac{1}{4} - \frac{1}{5} = $$ | $$ \frac{1}{5} - \frac{1}{6} = $$ | $$ \frac{1}{6} - \frac{1}{7} = $$ |
特点:分子都是,分母的公因数都只有。
规律:用分母的作得数的分母,用分母的作得数的分子。
(2) 利用上面的规律算一算。
$ \frac{1}{7} + \frac{1}{8} = $
$ \frac{1}{8} - \frac{1}{9} = $
$ \frac{1}{10} - \frac{1}{11} = $
$ \frac{1}{3} + \frac{1}{7} = $
(1)
| $$ \frac{1}{4} + \frac{1}{5} = $$ | $$ \frac{1}{5} + \frac{1}{6} = $$ | $$ \frac{1}{6} + \frac{1}{7} = $$ |
| --- | --- | --- |
| $$ \frac{1}{4} - \frac{1}{5} = $$ | $$ \frac{1}{5} - \frac{1}{6} = $$ | $$ \frac{1}{6} - \frac{1}{7} = $$ |
特点:分子都是,分母的公因数都只有。
规律:用分母的作得数的分母,用分母的作得数的分子。
(2) 利用上面的规律算一算。
$ \frac{1}{7} + \frac{1}{8} = $
$ \frac{1}{8} - \frac{1}{9} = $
$ \frac{1}{10} - \frac{1}{11} = $
$ \frac{1}{3} + \frac{1}{7} = $
答案
(1)1;1;积;和或差
(2)$\frac{15}{56}$;$\frac{1}{72}$;$\frac{1}{110}$;$\frac{10}{21}$
(2)$\frac{15}{56}$;$\frac{1}{72}$;$\frac{1}{110}$;$\frac{10}{21}$
4. “六一”儿童节才艺表演设一、二、三等奖,一、二等奖的获奖人数占获奖总人数的$$ \frac{7}{10} $$,一、三等奖的获奖人数占获奖总人数的$$ \frac{3}{5} $$,一、二、三等奖的获奖人数各占获奖总人数的几分之几?
答案
一等奖:$\frac{3}{10}$,二等奖:$\frac{2}{5}$,三等奖:$\frac{3}{10}$。
步骤:
1. 三等奖占比:$1 - \frac{7}{10} = \frac{3}{10}$
2. 一等奖占比:$\frac{3}{5} - \frac{3}{10} = \frac{6}{10} - \frac{3}{10} = \frac{3}{10}$
3. 二等奖占比:$\frac{7}{10} - \frac{3}{10} = \frac{4}{10} = \frac{2}{5}$
步骤:
1. 三等奖占比:$1 - \frac{7}{10} = \frac{3}{10}$
2. 一等奖占比:$\frac{3}{5} - \frac{3}{10} = \frac{6}{10} - \frac{3}{10} = \frac{3}{10}$
3. 二等奖占比:$\frac{7}{10} - \frac{3}{10} = \frac{4}{10} = \frac{2}{5}$
登录