6. (2023·湘潭)如图,在平面直角坐标系中,O是坐标原点,A是反比例函数$y=\frac{k}{x}(k\neq0)$图像上的一点,过点A分别作$AM\bot x$轴于点M,$AN\bot y$轴于点N,若四边形AMON的面积为2. 则k的值是( )
A. 2 B. -2 C. 1 D. -1

A. 2 B. -2 C. 1 D. -1
答案
A
7. (2023·无锡)如图,一次函数$y=ax+b$的图像与反比例函数$y=\frac{k}{x}$的图像在第一象限内交于点A,B,与x轴交于点C,$AB=BC$. 若$\triangle OAC$的面积为8,则$k=$__________.

答案
$\frac{16}{3}$
8. 如图,$A(a,b)$,$B(-a,-b)$是反比例函数$y=\frac{m}{x}$的图像上的两点,分别过点A,B作y轴的平行线,与反比例函数$y=\frac{n}{x}$的图像交于点C,D,若四边形ACBD的面积是8,则m,n之间的关系是__________.

答案
$n - m = 4$
9. 如图,$\triangle ABC$的顶点A,C落在坐标轴上,且顶点B的坐标为(-5,2),将$\triangle ABC$沿x轴向右平移得到$\triangle A_1B_1C_1$,使得点$B_1$恰好落在函数$y=\frac{6}{x}$的图像上,若线段AC扫过的面积为48,则点$C_1$的坐标为__________.

答案
(8,6)
10. 如图,正方形OABC的面积为9,O为坐标原点,点B在函数$y=\frac{k}{x}(x>0)$的图像上,$P(m,n)$是函数图像上任意一点,过点P分别作x轴,y轴的垂线,垂足为E,F. 设矩形OEPF与正方形OABC不重合的部分(阴影部分)的面积为S.
(1)求k的值;
(2)当$S=\frac{9}{2}$时,求点P的坐标;
(3)写出S关于m的函数表达式.

(1)求k的值;
(2)当$S=\frac{9}{2}$时,求点P的坐标;
(3)写出S关于m的函数表达式.
答案
解:(1) $\because$ 正方形$OABC$的面积为$9$,
$\therefore OA = OC = 3$,$\therefore B(3,3)$.
又$\because$ 点$B(3,3)$在函数$y = \frac{k}{x}(x>0)$的图像上,$\therefore k = 9$.
(2) 分两种情况:① 当点$P$在点$B$的左侧时,
$\because$ 点$P(m,n)$在函数$y = \frac{9}{x}(x>0)$的图像上,$\therefore mn = 9$,
$\therefore S = m(n - 3)=mn - 3m=\frac{9}{2}$,解得$m=\frac{3}{2}$,
$\therefore n = 6$,$\therefore$ 点$P$的坐标是$\left(\frac{3}{2},6\right)$.
② 当点$P$在点$B$的右侧时,
$\because$ 点$P(m,n)$在函数$y = \frac{9}{x}(x>0)$的图像上,$\therefore mn = 9$,
$\therefore S = n(m - 3)=mn - 3n=\frac{9}{2}$,解得$n=\frac{3}{2}$,$\therefore m = 6$,
$\therefore$ 点$P$的坐标是$\left(6,\frac{3}{2}\right)$.
综上所述,点$P$的坐标是$\left(6,\frac{3}{2}\right)$或$\left(\frac{3}{2},6\right)$.
(3) 当$0<m<3$时,点$P$在点$B$的左侧,此时$S = 9 - 3m$;
当$m = 3$时,点$P$与点$B$重合,此时$S = 0$;
当$m>3$时,点$P$在点$B$的右侧,此时$S = 9 - 3n = 9-\frac{27}{m}$.
$\therefore OA = OC = 3$,$\therefore B(3,3)$.
又$\because$ 点$B(3,3)$在函数$y = \frac{k}{x}(x>0)$的图像上,$\therefore k = 9$.
(2) 分两种情况:① 当点$P$在点$B$的左侧时,
$\because$ 点$P(m,n)$在函数$y = \frac{9}{x}(x>0)$的图像上,$\therefore mn = 9$,
$\therefore S = m(n - 3)=mn - 3m=\frac{9}{2}$,解得$m=\frac{3}{2}$,
$\therefore n = 6$,$\therefore$ 点$P$的坐标是$\left(\frac{3}{2},6\right)$.
② 当点$P$在点$B$的右侧时,
$\because$ 点$P(m,n)$在函数$y = \frac{9}{x}(x>0)$的图像上,$\therefore mn = 9$,
$\therefore S = n(m - 3)=mn - 3n=\frac{9}{2}$,解得$n=\frac{3}{2}$,$\therefore m = 6$,
$\therefore$ 点$P$的坐标是$\left(6,\frac{3}{2}\right)$.
综上所述,点$P$的坐标是$\left(6,\frac{3}{2}\right)$或$\left(\frac{3}{2},6\right)$.
(3) 当$0<m<3$时,点$P$在点$B$的左侧,此时$S = 9 - 3m$;
当$m = 3$时,点$P$与点$B$重合,此时$S = 0$;
当$m>3$时,点$P$在点$B$的右侧,此时$S = 9 - 3n = 9-\frac{27}{m}$.
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