1. 对于方程$2(x - 3) = 5$,去括号正确的是(
A.$2x - 6 = 5$
B.$2x - 6 = 10$
C.$2x - 3 = 5$
D.$x - 6 = 5$
A
).A.$2x - 6 = 5$
B.$2x - 6 = 10$
C.$2x - 3 = 5$
D.$x - 6 = 5$
答案
A
2. 对于方程$2(2x - 1) - (x - 3) = 1$,去括号正确的是(
A.$4x - 1 - x - 3 = 1$
B.$4x - 1 - x + 3 = 1$
C.$4x - 2 - x + 3 = 1$
D.$4x - 2 - x - 3 = 1$
C
).A.$4x - 1 - x - 3 = 1$
B.$4x - 1 - x + 3 = 1$
C.$4x - 2 - x + 3 = 1$
D.$4x - 2 - x - 3 = 1$
答案
C
解析
$2(2x - 1) - (x - 3) = 1$
$4x - 2 - x + 3 = 1$
C
$4x - 2 - x + 3 = 1$
C
3. 方程$3x + 2(1 - x) = 4$的解是(
A.$x = \frac{2}{5}$
B.$x = \frac{6}{5}$
C.$x = 2$
D.$x = 1$
C
).A.$x = \frac{2}{5}$
B.$x = \frac{6}{5}$
C.$x = 2$
D.$x = 1$
答案
C
解析
解:$3x + 2(1 - x) = 4$
$3x + 2 - 2x = 4$
$x + 2 = 4$
$x = 2$
C
$3x + 2 - 2x = 4$
$x + 2 = 4$
$x = 2$
C
4. 解方程$2(x - 1) = x - 6(x - \frac{1}{2})$,步骤如下:
去括号,得$2x - 2 = x - 6x - 3$. ①
移项,得$2x - x + 6x = 2 - 3$. ②
合并同类项,得$7x = -1$. ③
系数化为$1$,得$x = -\frac{1}{7}$. ④
经检验,$x = -\frac{1}{7}$不是原方程的解,说明解题的四个步骤中存在错误,其中开始出错的步骤是(
A.①
B.②
C.③
D.④
去括号,得$2x - 2 = x - 6x - 3$. ①
移项,得$2x - x + 6x = 2 - 3$. ②
合并同类项,得$7x = -1$. ③
系数化为$1$,得$x = -\frac{1}{7}$. ④
经检验,$x = -\frac{1}{7}$不是原方程的解,说明解题的四个步骤中存在错误,其中开始出错的步骤是(
A
).A.①
B.②
C.③
D.④
答案
A
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