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脱式计算。（能简算的要简算）
$1-\dfrac{7}{36}÷ \dfrac{5}{18}-\dfrac{5}{18}$ $\dfrac{3}{8}× \dfrac{3}{5}+\dfrac{3}{8}× \dfrac{2}{5}$
$24× (\dfrac{3}{8}+\dfrac{1}{6}-\dfrac{5}{12})$ $3-\dfrac{3}{2}× \dfrac{10}{21}-\dfrac{2}{7}$
$13× (\dfrac{3}{13}+\dfrac{1}{12})× 12$ $\dfrac{11}{12}÷ (\dfrac{11}{12}+\dfrac{7}{6})$
$5-(\dfrac{6}{7}÷ \dfrac{3}{14}+\dfrac{5}{16})$ $\dfrac{9}{5}-(\dfrac{2}{5}÷ \dfrac{1}{2}+\dfrac{3}{7})$
$\dfrac{7}{12}× \dfrac{5}{9}+\dfrac{5}{12}× \dfrac{2}{9}$ $\dfrac{13}{97}× 94+\dfrac{39}{97}$
$2÷ \dfrac{2}{5}-\dfrac{2}{5}÷ 2$ $\dfrac{2}{3}+\dfrac{1}{3}× \dfrac{4}{5}$
$1-\dfrac{7}{36}÷ \dfrac{5}{18}-\dfrac{5}{18}$ $\dfrac{3}{8}× \dfrac{3}{5}+\dfrac{3}{8}× \dfrac{2}{5}$
$24× (\dfrac{3}{8}+\dfrac{1}{6}-\dfrac{5}{12})$ $3-\dfrac{3}{2}× \dfrac{10}{21}-\dfrac{2}{7}$
$13× (\dfrac{3}{13}+\dfrac{1}{12})× 12$ $\dfrac{11}{12}÷ (\dfrac{11}{12}+\dfrac{7}{6})$
$5-(\dfrac{6}{7}÷ \dfrac{3}{14}+\dfrac{5}{16})$ $\dfrac{9}{5}-(\dfrac{2}{5}÷ \dfrac{1}{2}+\dfrac{3}{7})$
$\dfrac{7}{12}× \dfrac{5}{9}+\dfrac{5}{12}× \dfrac{2}{9}$ $\dfrac{13}{97}× 94+\dfrac{39}{97}$
$2÷ \dfrac{2}{5}-\dfrac{2}{5}÷ 2$ $\dfrac{2}{3}+\dfrac{1}{3}× \dfrac{4}{5}$
答案
$1-\dfrac{7}{36}÷ \dfrac{5}{18}-\dfrac{5}{18}$
$=1-\dfrac{7}{36}×\dfrac{18}{5}-\dfrac{5}{18}$
$=1-\dfrac{7}{10}-\dfrac{5}{18}$
$=\dfrac{3}{10}-\dfrac{5}{18}$
$=\dfrac{27}{90}-\dfrac{25}{90}$
$=\dfrac{1}{45}$
$\dfrac{3}{8}× \dfrac{3}{5}+\dfrac{3}{8}× \dfrac{2}{5}$
$=\dfrac{3}{8}×(\dfrac{3}{5}+\dfrac{2}{5})$
$=\dfrac{3}{8}×1$
$=\dfrac{3}{8}$
$24× (\dfrac{3}{8}+\dfrac{1}{6}-\dfrac{5}{12})$
$=24×\dfrac{3}{8}+24×\dfrac{1}{6}-24×\dfrac{5}{12}$
$=9+4-10$
$=3$
$3-\dfrac{3}{2}× \dfrac{10}{21}-\dfrac{2}{7}$
$=3-\dfrac{5}{7}-\dfrac{2}{7}$
$=3-(\dfrac{5}{7}+\dfrac{2}{7})$
$=3-1$
$=2$
$13× (\dfrac{3}{13}+\dfrac{1}{12})× 12$
$=13×12×\dfrac{3}{13}+13×12×\dfrac{1}{12}$
$=36+13$
$=49$
$\dfrac{11}{12}÷ (\dfrac{11}{12}+\dfrac{7}{6})$
$=\dfrac{11}{12}÷ (\dfrac{11}{12}+\dfrac{14}{12})$
$=\dfrac{11}{12}÷\dfrac{25}{12}$
$=\dfrac{11}{25}$
$5-(\dfrac{6}{7}÷ \dfrac{3}{14}+\dfrac{5}{16})$
$=5-(\dfrac{6}{7}×\dfrac{14}{3}+\dfrac{5}{16})$
$=5-(4+\dfrac{5}{16})$
$=5-4\dfrac{5}{16}$
$=\dfrac{11}{16}$
$\dfrac{9}{5}-(\dfrac{2}{5}÷ \dfrac{1}{2}+\dfrac{3}{7})$
$=\dfrac{9}{5}-(\dfrac{4}{5}+\dfrac{3}{7})$
$=\dfrac{9}{5}-\dfrac{4}{5}-\dfrac{3}{7}$
$=1-\dfrac{3}{7}$
$=\dfrac{4}{7}$
$\dfrac{7}{12}× \dfrac{5}{9}+\dfrac{5}{12}× \dfrac{2}{9}$
$=\dfrac{5}{12}×\dfrac{7}{9}+\dfrac{5}{12}×\dfrac{2}{9}$
$=\dfrac{5}{12}×(\dfrac{7}{9}+\dfrac{2}{9})$
$=\dfrac{5}{12}×1$
$=\dfrac{5}{12}$
$\dfrac{13}{97}× 94+\dfrac{39}{97}$
$=\dfrac{13}{97}×94+\dfrac{13}{97}×3$
$=\dfrac{13}{97}×(94+3)$
$=\dfrac{13}{97}×97$
$=13$
$2÷ \dfrac{2}{5}-\dfrac{2}{5}÷ 2$
$=2×\dfrac{5}{2}-\dfrac{2}{5}×\dfrac{1}{2}$
$=5-\dfrac{1}{5}$
$=4\dfrac{4}{5}$
$\dfrac{2}{3}+\dfrac{1}{3}× \dfrac{4}{5}$
$=\dfrac{2}{3}+\dfrac{4}{15}$
$=\dfrac{10}{15}+\dfrac{4}{15}$
$=\dfrac{14}{15}$
$=1-\dfrac{7}{36}×\dfrac{18}{5}-\dfrac{5}{18}$
$=1-\dfrac{7}{10}-\dfrac{5}{18}$
$=\dfrac{3}{10}-\dfrac{5}{18}$
$=\dfrac{27}{90}-\dfrac{25}{90}$
$=\dfrac{1}{45}$
$\dfrac{3}{8}× \dfrac{3}{5}+\dfrac{3}{8}× \dfrac{2}{5}$
$=\dfrac{3}{8}×(\dfrac{3}{5}+\dfrac{2}{5})$
$=\dfrac{3}{8}×1$
$=\dfrac{3}{8}$
$24× (\dfrac{3}{8}+\dfrac{1}{6}-\dfrac{5}{12})$
$=24×\dfrac{3}{8}+24×\dfrac{1}{6}-24×\dfrac{5}{12}$
$=9+4-10$
$=3$
$3-\dfrac{3}{2}× \dfrac{10}{21}-\dfrac{2}{7}$
$=3-\dfrac{5}{7}-\dfrac{2}{7}$
$=3-(\dfrac{5}{7}+\dfrac{2}{7})$
$=3-1$
$=2$
$13× (\dfrac{3}{13}+\dfrac{1}{12})× 12$
$=13×12×\dfrac{3}{13}+13×12×\dfrac{1}{12}$
$=36+13$
$=49$
$\dfrac{11}{12}÷ (\dfrac{11}{12}+\dfrac{7}{6})$
$=\dfrac{11}{12}÷ (\dfrac{11}{12}+\dfrac{14}{12})$
$=\dfrac{11}{12}÷\dfrac{25}{12}$
$=\dfrac{11}{25}$
$5-(\dfrac{6}{7}÷ \dfrac{3}{14}+\dfrac{5}{16})$
$=5-(\dfrac{6}{7}×\dfrac{14}{3}+\dfrac{5}{16})$
$=5-(4+\dfrac{5}{16})$
$=5-4\dfrac{5}{16}$
$=\dfrac{11}{16}$
$\dfrac{9}{5}-(\dfrac{2}{5}÷ \dfrac{1}{2}+\dfrac{3}{7})$
$=\dfrac{9}{5}-(\dfrac{4}{5}+\dfrac{3}{7})$
$=\dfrac{9}{5}-\dfrac{4}{5}-\dfrac{3}{7}$
$=1-\dfrac{3}{7}$
$=\dfrac{4}{7}$
$\dfrac{7}{12}× \dfrac{5}{9}+\dfrac{5}{12}× \dfrac{2}{9}$
$=\dfrac{5}{12}×\dfrac{7}{9}+\dfrac{5}{12}×\dfrac{2}{9}$
$=\dfrac{5}{12}×(\dfrac{7}{9}+\dfrac{2}{9})$
$=\dfrac{5}{12}×1$
$=\dfrac{5}{12}$
$\dfrac{13}{97}× 94+\dfrac{39}{97}$
$=\dfrac{13}{97}×94+\dfrac{13}{97}×3$
$=\dfrac{13}{97}×(94+3)$
$=\dfrac{13}{97}×97$
$=13$
$2÷ \dfrac{2}{5}-\dfrac{2}{5}÷ 2$
$=2×\dfrac{5}{2}-\dfrac{2}{5}×\dfrac{1}{2}$
$=5-\dfrac{1}{5}$
$=4\dfrac{4}{5}$
$\dfrac{2}{3}+\dfrac{1}{3}× \dfrac{4}{5}$
$=\dfrac{2}{3}+\dfrac{4}{15}$
$=\dfrac{10}{15}+\dfrac{4}{15}$
$=\dfrac{14}{15}$
