2026年补充习题江苏七年级数学上册苏科版第44页答案
6. 计算:
(1) $-1.25 + \frac{3}{4} - \frac{5}{12} - \frac{3}{8}$;
(2) $-12 × 4 - (-6) × 5$;
(3) $-10 + 8 ÷ (-2)^3 - 4 × (-2)$;
(4) $1 ÷ (-1)^2 + 0 ÷ 5 -5 × |-1|$;
(5) $-2^2 × 3^2 - (-4) × 2$;
(6) $(-105) × [ (-\frac{1}{3}) + (+\frac{1}{5}) - (-\frac{1}{7}) ]$;
(7) $(-1)^{2001} - (-1)^{2000}$;
(8) $( \frac{1}{2} - \frac{3}{4} - \frac{5}{8} ) ÷ ( -\frac{5}{8} )$。

答案

解:
(1)
$\begin{aligned}原式&=-\frac{5}{4}+\frac{3}{4}-\frac{5}{12}-\frac{3}{8}\\&=-\frac{1}{2}-\frac{5}{12}-\frac{3}{8}\\&=-\frac{12}{24}-\frac{10}{24}-\frac{9}{24}\\&=-\frac{31}{24}\end{aligned}$
(2)
$\begin{aligned}原式&=-48 + 30\\&=-18\end{aligned}$
(3)
$\begin{aligned}原式&=-10 + 8÷(-8) - 4×(-2)\\&=-10 -1 +8\\&=-3\end{aligned}$
(4)
$\begin{aligned}原式&=1÷1 + 0÷5 -5×1\\&=1+0-5\\&=-4\end{aligned}$
(5)
$\begin{aligned}原式&=-4×9 + 8\\&=-36+8\\&=-28\end{aligned}$
(6)
$\begin{aligned}原式&=(-105)×(-\frac{1}{3})+(-105)×\frac{1}{5}-(-105)×(-\frac{1}{7})\\&=35 -21 -15\\&=-1\end{aligned}$
(7)
$\begin{aligned}原式&=-1 -1\\&=-2\end{aligned}$
(8)
$\begin{aligned}原式&=(\frac{1}{2}-\frac{3}{4}-\frac{5}{8})×(-\frac{8}{5})\\&=\frac{1}{2}×(-\frac{8}{5})-\frac{3}{4}×(-\frac{8}{5})-\frac{5}{8}×(-\frac{8}{5})\\&=-\frac{4}{5}+\frac{6}{5}+1\\&=\frac{7}{5}\end{aligned}$