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1 [2025 浙江台州调研]把$(-\dfrac{3}{4})÷(-\dfrac{2}{3})$转化为乘法是（
A.$(-\dfrac{3}{4})×\dfrac{2}{3}$
B.$(-\dfrac{3}{4})×\dfrac{3}{2}$
C.$(-\dfrac{3}{4})×(-\dfrac{2}{3})$
D.$(-\dfrac{3}{4})×(-\dfrac{3}{2})$
D
）A.$(-\dfrac{3}{4})×\dfrac{2}{3}$
B.$(-\dfrac{3}{4})×\dfrac{3}{2}$
C.$(-\dfrac{3}{4})×(-\dfrac{2}{3})$
D.$(-\dfrac{3}{4})×(-\dfrac{3}{2})$
答案
1.D 【解析】把$(-\dfrac{3}{4})÷(-\dfrac{2}{3})$转化为乘法是$(-\dfrac{3}{4})×(-\dfrac{3}{2})$,故选 D.
$2 -1÷(-5)÷(-\dfrac{1}{5})$的计算结果是（
A.$-1$
B.$-\dfrac{1}{25}$
C.$\dfrac{1}{25}$
D.$1$
A
）A.$-1$
B.$-\dfrac{1}{25}$
C.$\dfrac{1}{25}$
D.$1$
答案
2.A 【解析】$-1÷ (-5)÷ (-\dfrac{1}{5}) = -1× \dfrac{1}{5}×5 = -1$,故选 A.
3[2026江苏苏州期中]下列计算:①$-28÷7=-4$；②$\frac{0.3}{-\frac{1}{2}}=0.6$；③$\frac{-2}{-6}=\frac{1}{3}$；④$(-0.5)÷(-0.25)=2$；⑤$\frac{7}{-63}=\frac{1}{9}$。其中正确的个数是 (
A.1个
B.2个
C.3个
D.4个
C
)A.1个
B.2个
C.3个
D.4个
答案
3.C 【解析】①$-28÷7=-4$,正确; ②$\dfrac{0.3}{-\dfrac{1}{2}}=0.3÷ (-\dfrac{1}{2}) = 0.3×(-2) = -0.6≠0.6$,错误; ③$\dfrac{-2}{-6}=\dfrac{2}{6}=\dfrac{1}{3}$,正确; ④$(-0.5)÷(-0.25) = (-\dfrac{1}{2})÷ (-\dfrac{1}{4}) = \dfrac{1}{2}×4=2$,正确; ⑤$\dfrac{7}{-63}=-\dfrac{1}{9}≠ \dfrac{1}{9}$,错误. 所以正确的有①③④,共 3 个. 故选 C.
4 某同学在计算$-16÷a$时，误将“÷”看成“+”，结果是$-12$，则$-16÷a$的正确结果是
-4
。答案
4.-4 【解析】计算$-16÷ a$ 时,误将“÷”看成“+”,结果得$-12$,即$-16+a=-12$,则 $a=4$,所以$-16÷ a=-16÷4=-4$. 故答案为$-4$.
5 已知$|x|=4$，$|y|=\dfrac{1}{2}$，且$xy＜0$，则$\dfrac{x}{y}$的值等于
-8
。答案
5.-8 【解析】
6[2025浙江绍兴质检]计算：
(1)$(2\dfrac{1}{3})÷(-1\dfrac{1}{6})$；
(2)$0÷(-\dfrac{3}{5})$；
(3)$(-3\dfrac{3}{8})÷(-2.25)$。
(1)$(2\dfrac{1}{3})÷(-1\dfrac{1}{6})$；
(2)$0÷(-\dfrac{3}{5})$；
(3)$(-3\dfrac{3}{8})÷(-2.25)$。
答案
6.【解】(1)$(2\dfrac{1}{3})÷ (-1\dfrac{1}{6}) = -(\dfrac{7}{3}× \dfrac{6}{7}) = -2$.
(2)$0÷ (-\dfrac{3}{5}) = 0$.
(3)$(-3\dfrac{3}{8})÷ (-2.25) = \dfrac{27}{8}× \dfrac{4}{9} = \dfrac{3}{2}$.
(2)$0÷ (-\dfrac{3}{5}) = 0$.
(3)$(-3\dfrac{3}{8})÷ (-2.25) = \dfrac{27}{8}× \dfrac{4}{9} = \dfrac{3}{2}$.
7 [2025 浙江杭州期中]下列各式中,计算结果为负数的是 (
A.$-3×4÷(-5)$
B.$4÷|-5|×3$
C.$(-4)÷\frac{2}{3}×0$
D.$(-4)÷(-5)×(-3)$
D
)A.$-3×4÷(-5)$
B.$4÷|-5|×3$
C.$(-4)÷\frac{2}{3}×0$
D.$(-4)÷(-5)×(-3)$
答案
7.D 【解析】A 选项,$-3×4÷ (-5) = 2.4＞0$,故此选项不符合题意; B 选项,$4÷ |-5|×3 = 2.4＞0$,故此选项不符合题意; C 选项,$(-4)÷ \dfrac{2}{3}×0 = 0$,故此选项不符合题意; D 选项,$(-4)÷ (-5)× (-3) = -2.4＜0$,故此选项符合题意. 故选 D.
8 计算：$-100÷10×\frac{1}{10}=$
-1
。答案
8.-1 【解析】原式$=-10× \dfrac{1}{10} = -1$,故答案为$-1$.
9 若a的相反数是$5\frac{1}{2}$,b的倒数是$-\frac{4}{11}$,则a与b的商的5倍是
10
。答案
9.10 【解析】因为 $a$ 的相反数是 $5\dfrac{1}{2}$,$b$ 的倒数是 $-\dfrac{4}{11}$,所以 $a=-5\dfrac{1}{2}$,$b=-\dfrac{11}{4}$,所以 $(-5\dfrac{1}{2})÷ (-\dfrac{11}{4})×5 = \dfrac{11}{2}× \dfrac{4}{11}×5 = 10$. 故答案为 10.
10[2025上海闵行区期末]计算：
(1)$(-\dfrac{3}{2})÷\dfrac{2}{3}×(-\dfrac{3}{2})$；
(2)$(-5\dfrac{2}{5})÷(-3.6)×(-1\dfrac{1}{6})$。
(1)$(-\dfrac{3}{2})÷\dfrac{2}{3}×(-\dfrac{3}{2})$；
(2)$(-5\dfrac{2}{5})÷(-3.6)×(-1\dfrac{1}{6})$。
答案
10.【解】(1)$(-\dfrac{3}{2})÷ \dfrac{2}{3}× (-\dfrac{3}{2}) = \dfrac{3}{2}× \dfrac{3}{2}× \dfrac{3}{2} = \dfrac{27}{8}$.
(2)$(-5\dfrac{2}{5})÷ (-3.6)× (-1\dfrac{1}{6}) = (-\dfrac{27}{5})× (-\dfrac{5}{18})× (-\dfrac{7}{6}) = -\dfrac{27}{5}× \dfrac{5}{18}× \dfrac{7}{6} = -\dfrac{7}{4}$.
(2)$(-5\dfrac{2}{5})÷ (-3.6)× (-1\dfrac{1}{6}) = (-\dfrac{27}{5})× (-\dfrac{5}{18})× (-\dfrac{7}{6}) = -\dfrac{27}{5}× \dfrac{5}{18}× \dfrac{7}{6} = -\dfrac{7}{4}$.
11 新考向 开放性试题 [2026 河南驻马店期中]在下面一列数中选出不同的数进行运算,并使运算结果分别符合下列要求.(注:每小问写出一个符合要求的式子及结果)
$0,-\dfrac{2}{5},26,2.4,-7,\dfrac{1}{2},-370,-2\dfrac{1}{2},-24,-0.3.$
(1)选择一个整数和一个分数,使运算结果为整数;
(2)选择一个整数和两个分数,使运算结果为正分数;
(3)选择两个整数和两个分数,仅包含乘除运算,使运算结果为负分数.
$0,-\dfrac{2}{5},26,2.4,-7,\dfrac{1}{2},-370,-2\dfrac{1}{2},-24,-0.3.$
(1)选择一个整数和一个分数,使运算结果为整数;
(2)选择一个整数和两个分数,使运算结果为正分数;
(3)选择两个整数和两个分数,仅包含乘除运算,使运算结果为负分数.
答案
11.【解】(1)$0× \dfrac{1}{2} = 0$. (答案不唯一)
(2)$0+\dfrac{1}{2}+(-\dfrac{2}{5}) = \dfrac{1}{10}$. (答案不唯一)
(3)$26×(-24)× (-\dfrac{2}{5})÷ (-2\dfrac{1}{2}) = -\dfrac{2496}{25}$. (答案不唯一)
(2)$0+\dfrac{1}{2}+(-\dfrac{2}{5}) = \dfrac{1}{10}$. (答案不唯一)
(3)$26×(-24)× (-\dfrac{2}{5})÷ (-2\dfrac{1}{2}) = -\dfrac{2496}{25}$. (答案不唯一)
