1.解下列方程:
(1)$\frac{3}{x-1}=\frac{4}{x}$;
(2)$\frac{x}{2x-5}+\frac{5}{5-2x}=1$;
(3)$\frac{1}{x-2}+3=\frac{1-x}{2-x}$;
(4)$\frac{2x+9}{3x-9}=\frac{4x-7}{x-3}+2$;
(5)$\frac{2}{1-x^2}=\frac{3}{1+x}$;
(6)$\frac{1}{x-1}$
$\frac{x-2}{x+1}-1$;
(7)$\frac{2x}{x-1}+\frac{2}{x+2}=2$;
(8)$\frac{2}{x+1}=\frac{6}{x^2-1}-\frac{3}{x-1}$。
(1)$\frac{3}{x-1}=\frac{4}{x}$;
(2)$\frac{x}{2x-5}+\frac{5}{5-2x}=1$;
(3)$\frac{1}{x-2}+3=\frac{1-x}{2-x}$;
(4)$\frac{2x+9}{3x-9}=\frac{4x-7}{x-3}+2$;
(5)$\frac{2}{1-x^2}=\frac{3}{1+x}$;
(6)$\frac{1}{x-1}$
(7)$\frac{2x}{x-1}+\frac{2}{x+2}=2$;
(8)$\frac{2}{x+1}=\frac{6}{x^2-1}-\frac{3}{x-1}$。
答案
(1)方程两边同乘以$x(x-1)$得,
$3x=4x-4$,
$\therefore x=4$,
经检验,$x=4$是原分式方程的解;
(2)方程两边同乘以$(2x-5)$得,
$x-5=2x-5$,
$\therefore x=0$,
经检验,当$x=0$时,$2x-5≠0$,
$\therefore x=0$是原分式方程的解;
(3)方程两边同乘以$(x-2)$得
$1+3(x-2)=x-1$,
$\therefore x=2$,
检验:当$x=2$时,$x-2=0$,
$\therefore$原分式方程无解;
(4)方程两边同乘以$(3x-9)$得
$2x+9=3(4x-7)+2(3x-9)$,
$\therefore x=3$,
检验:当$x=3$时,$3x-9=0$,
$\therefore$原分式方程无解;
(5)方程两边同乘以$(1-x^2)$得
$2=3(1-x)$,
$\therefore x=\frac{1}{3}$,
检验:当$x=\frac{1}{3}$时,$1-x^2≠0$,
$\therefore$原分式方程的解为$x=\frac{1}{3}$;
(6)方程两边同乘以$(x^2-1)$得
$x+1=(x-2)(x-1)-(x^2-1)$,
$\therefore 4x=2$,
$x=\frac{1}{2}$,
检验:当$x=\frac{1}{2}$时,$x^2-1≠0$,
$\therefore$原分式方程的解为$x=\frac{1}{2}$;
(7)方程两边同乘以$(x-1)(x+2)$得
$2x(x+2)+2(x-1)=2(x-1)(x+2)$,
$\therefore 2x=-1$,
$x=-\frac{1}{2}$,
检验:当$x=-\frac{1}{2}$时,$(x-1)(x+2)≠0$,
$\therefore$原分式方程的解为$x=-\frac{1}{2}$;
(8)方程两边同乘以$(x^2-1)$得
$2(x-1)=6-3(x+1)$,
$\therefore x=1$,
检验:当$x=1$时,$x^2-1=0$,
$\therefore$原分式方程的无解。
$3x=4x-4$,
$\therefore x=4$,
经检验,$x=4$是原分式方程的解;
(2)方程两边同乘以$(2x-5)$得,
$x-5=2x-5$,
$\therefore x=0$,
经检验,当$x=0$时,$2x-5≠0$,
$\therefore x=0$是原分式方程的解;
(3)方程两边同乘以$(x-2)$得
$1+3(x-2)=x-1$,
$\therefore x=2$,
检验:当$x=2$时,$x-2=0$,
$\therefore$原分式方程无解;
(4)方程两边同乘以$(3x-9)$得
$2x+9=3(4x-7)+2(3x-9)$,
$\therefore x=3$,
检验:当$x=3$时,$3x-9=0$,
$\therefore$原分式方程无解;
(5)方程两边同乘以$(1-x^2)$得
$2=3(1-x)$,
$\therefore x=\frac{1}{3}$,
检验:当$x=\frac{1}{3}$时,$1-x^2≠0$,
$\therefore$原分式方程的解为$x=\frac{1}{3}$;
(6)方程两边同乘以$(x^2-1)$得
$x+1=(x-2)(x-1)-(x^2-1)$,
$\therefore 4x=2$,
$x=\frac{1}{2}$,
检验:当$x=\frac{1}{2}$时,$x^2-1≠0$,
$\therefore$原分式方程的解为$x=\frac{1}{2}$;
(7)方程两边同乘以$(x-1)(x+2)$得
$2x(x+2)+2(x-1)=2(x-1)(x+2)$,
$\therefore 2x=-1$,
$x=-\frac{1}{2}$,
检验:当$x=-\frac{1}{2}$时,$(x-1)(x+2)≠0$,
$\therefore$原分式方程的解为$x=-\frac{1}{2}$;
(8)方程两边同乘以$(x^2-1)$得
$2(x-1)=6-3(x+1)$,
$\therefore x=1$,
检验:当$x=1$时,$x^2-1=0$,
$\therefore$原分式方程的无解。
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