9.(2024·如皋月考)若5个有理数之积为正数,则这5个因数中负因数的个数可能是 (
A.2
B.4
C.2或4
D.2或4或没有
D
)A.2
B.4
C.2或4
D.2或4或没有
答案
9.D
10.(2024·锡山区月考)有理数$a,b$在数轴上的位置如图所示,则下列判断正确的是 (

A.$a+b>0$
B.$a<-1$
C.$a-b>0$
D.$ab>0$
A
)A.$a+b>0$
B.$a<-1$
C.$a-b>0$
D.$ab>0$
答案
10.A
11.(2024·灌南县月考)绝对值小于3的所有整数的积是
0
.答案
11.0
12. 从$-3,-2,-1,4,5$中取3个不同的数相乘,可得到的最大的乘积记作$a$,最小的乘积记作$b$,则$b-a=$
-90
.答案
12.-90
13. (1) 已知$|a|=5,-b=8,ab<0$,则$a+b$的值为
(2) 已知$|a|=7,|b|=5$,且$a+b>0$,则$ab=$
(3) 若$|a|=3,|b|=5,ab<0$,则$a-b$的值为
-3
;(2) 已知$|a|=7,|b|=5$,且$a+b>0$,则$ab=$
35或-35
;(3) 若$|a|=3,|b|=5,ab<0$,则$a-b$的值为
-8或8
.答案
13.(1)-3 (2)35或-35 (3)-8或8
14.(海州区期中)如图是计算机某计算程序,若开始输入一个数$-\dfrac{5}{3}$,则最后输出的结果是

-7
.答案
14.-7
15.计算:
(1)$-0.75×(-0.4)×1\dfrac{2}{3}$;
(2)$0.6×(-\dfrac{3}{4})×(-\dfrac{5}{6})×(-2\dfrac{2}{3})$;
(3)$(-\dfrac{2}{9})×(-4\dfrac{1}{2})$;
(4)$8×(-2\dfrac{4}{5})×(-2.5)×(-\dfrac{3}{7})$;
(5)$(-4\dfrac{1}{20})×1.25×(-8)$;
(6)$\dfrac{5}{6}×(-2.4)×\dfrac{3}{5}$。
(1)$-0.75×(-0.4)×1\dfrac{2}{3}$;
(2)$0.6×(-\dfrac{3}{4})×(-\dfrac{5}{6})×(-2\dfrac{2}{3})$;
(3)$(-\dfrac{2}{9})×(-4\dfrac{1}{2})$;
(4)$8×(-2\dfrac{4}{5})×(-2.5)×(-\dfrac{3}{7})$;
(5)$(-4\dfrac{1}{20})×1.25×(-8)$;
(6)$\dfrac{5}{6}×(-2.4)×\dfrac{3}{5}$。
答案
15.解:(1)原式$=\dfrac{3}{4}×\dfrac{2}{5}×\dfrac{5}{3}=\dfrac{1}{2}.$
(2)原式$=\dfrac{3}{5}×(-\dfrac{3}{4})×(-\dfrac{5}{6})×(-\dfrac{8}{3})=-(\dfrac{3}{5}×\dfrac{3}{4}×\dfrac{5}{6}×\dfrac{8}{3})=-1.$
(3)原式$=(-\dfrac{2}{9})×(-\dfrac{9}{2})=\dfrac{2}{9}×\dfrac{9}{2}=1.$
(4)原式$=-(8×\dfrac{14}{5}×\dfrac{5}{2}×\dfrac{3}{7})=-24.$
(5)原式$=(-\dfrac{81}{20})×\dfrac{5}{4}×(-8)=\dfrac{81}{20}×\dfrac{5}{4}×8=\dfrac{81}{2}.$
(6)原式$=\dfrac{5}{6}×(-\dfrac{12}{5})×\dfrac{3}{5}=-(\dfrac{5}{6}×\dfrac{12}{5}×\dfrac{3}{5})=-\dfrac{6}{5}.$
(2)原式$=\dfrac{3}{5}×(-\dfrac{3}{4})×(-\dfrac{5}{6})×(-\dfrac{8}{3})=-(\dfrac{3}{5}×\dfrac{3}{4}×\dfrac{5}{6}×\dfrac{8}{3})=-1.$
(3)原式$=(-\dfrac{2}{9})×(-\dfrac{9}{2})=\dfrac{2}{9}×\dfrac{9}{2}=1.$
(4)原式$=-(8×\dfrac{14}{5}×\dfrac{5}{2}×\dfrac{3}{7})=-24.$
(5)原式$=(-\dfrac{81}{20})×\dfrac{5}{4}×(-8)=\dfrac{81}{20}×\dfrac{5}{4}×8=\dfrac{81}{2}.$
(6)原式$=\dfrac{5}{6}×(-\dfrac{12}{5})×\dfrac{3}{5}=-(\dfrac{5}{6}×\dfrac{12}{5}×\dfrac{3}{5})=-\dfrac{6}{5}.$
16. 若定义一种新的运算“$*$”,规定 $a*b=4ab$,如 $2*3=4×2×3=24$.
求:(1)$3*(-4)$的值;
(2)$(-2)*(6*3)$的值.
求:(1)$3*(-4)$的值;
(2)$(-2)*(6*3)$的值.
答案
16.解:(1)$3 * (-4)=4×3×(-4)=-48.$
(2)$(-2) * (6 * 3)=(-2) * (4×6×3)=(-2) * 72=4×(-2)×72=-576.$
(2)$(-2) * (6 * 3)=(-2) * (4×6×3)=(-2) * 72=4×(-2)×72=-576.$
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