Ⅴ. Read and finish the tasks. (读故事，完成下列任务。)
Boya is a good guqin player. He is kind and loves playing the guqin very much. He often plays his music for people around him.
Ziqi is a woodcutter(伐木工). He is quiet and he can't play the guqin. But he likes listening to music.
One day, Boya is playing the guqin in the forest(森林). Ziqi walks by and hears the music. He stops and says, "This music is so beautiful! It makes me think of high mountains(高山)!"
Ziqi listens with care. When Boya changes his music, Ziqi says, "Now it sounds(听起来) like a running river!" Boya is very happy because Ziqi can understand his music. They become best friends and often meet to enjoy the music together.
任务一：根据故事内容，选出伯牙和子期的相同点与不同点。
A. kind B. quiet C. guqin player D. woodcutter E. like music

任务二：根据故事内容排序。
()Boya and Ziqi become best friends.
()Ziqi hears Boya playing the guqin in the forest.
()Ziqi says the music sounds like a running river.
()Boya changes his music.
任务三：根据故事内容，回答问题。
Why is Boya happy when he hears Ziqi's words?

任务一:1. AC 2. BD 3. E
任务二:4 1 3 2
任务三: Because Ziqi can understand his music.

【分析】
首先处理任务一：需从短文中提取伯牙（Boya）和子期（Ziqi）的特征，区分两人的不同点与相同点。伯牙的特点是“善良、古琴演奏者”，对应选项A、C；子期的特点是“安静、伐木工”，对应选项B、D；两人都喜欢音乐，对应相同点E。任务二：按故事发展顺序梳理事件，结合原文逻辑和参考答案确定排序。任务三：从原文中直接提取伯牙开心的原因即可。
【解析】
任务一：1. 由原文“Boya is a good guqin player. He is kind...”可知，伯牙的特征对应A（kind）和C（guqin player），故1选AC；2. 由原文“Ziqi is a woodcutter. He is quiet...”可知，子期的特征对应B（quiet）和D（woodcutter），故2选BD；3. 由原文“loves playing the guqin very much”和“he likes listening to music”可知，两人都喜欢音乐，对应E，故3选E。
任务二：按故事发展顺序：Boya和Ziqi成为朋友（4）→Ziqi听到Boya在森林弹琴（1）→Ziqi说音乐像河流（3）→Boya换音乐（2），故排序为4 1 3 2。
任务三：由原文“Boya is very happy because Ziqi can understand his music.”可知，答案为Because Ziqi can understand his music.
【答案】
任务一:1. AC 2. BD 3. E；任务二:4 1 3 2；任务三: Because Ziqi can understand his music.
【知识点】
阅读理解，故事阅读，信息提取
【点评】
本题为任务型英语阅读题，围绕伯牙与子期的故事设置三类任务，考查学生对短文细节的理解、信息匹配及逻辑排序能力，是初中英语常见的阅读考查题型。
【难度系数】
0.6