22.如图,在$△ ABC$中,$AD⊥ BC$于点$D$,$AE$平分$∠ BAC$,$∠ B=72°$,$∠ C=34°$.
(1)求$∠ BAE$的度数.
(2)求$∠ DAE$的度数.

22. (1)$\because ∠B=72°,∠C=34°$,
$\therefore ∠BAC=180°-∠B-∠C=180°-72°-34°=74°$.
$\because AE$平分$∠BAC$,
$\therefore ∠BAE=\frac{1}{2}∠BAC=37°$.
(2)$\because AD⊥BC,∠B=72°$,
$\therefore ∠BAD=90°-∠B=90°-72°=18°$.
$\because ∠BAE=37°$,
$\therefore ∠DAE=∠BAE-∠BAD=37°-18°=19°$.

23.如图1,在△ABC中,∠ABC与∠ACB的平分线交于点I,根据下列条件,求∠BIC的度数.

(1)若∠ABC=60°,∠ACB=70°,则∠BIC=.
(2)若∠ABC+∠ACB=140°,则∠BIC=.
(3)若∠A=50°,则∠BIC=.
(4)若∠A=110°,则∠BIC=.
(5)从上述计算中,我们可以发现:已知∠A,求∠BIC的公式是:∠BIC=.
(6)如图2,若BP,CP分别是∠ABC与∠ACB的外角平分线,交于点P,若已知∠A,则求∠BPC的公式是:∠BPC=.

23.(1)$115°$
(2)$110°$
(3)$115°$
(4)$145°$
(5)$90°+\frac{1}{2}∠A$
(6)$90°-\frac{1}{2}∠A$