解下列方程:
(1) $\frac{1}{6}(6-3x)=\frac{2}{5}x -3$;
(2) $0.2x - \frac{2}{3}(x+3)= -x +3$;
(3) $\frac{3}{2}(x+1)-3=4 - \frac{7}{2}(x+1)$;
(4) $30\%(2x-1)+20\%(x+5)=30×5\%$;
(5) $\frac{3x-2}{2}-(2-x)=x$;
(6) $\frac{x-3}{3}-\frac{2x-5}{4}=1$;
(7) $\frac{x+1}{2}-1=\frac{2-3x}{3}$;
(8) $6(\frac{1}{2}x -4)+4(3-\frac{2}{5}x)=9(\frac{1}{2}x -1)$。
(1) $\frac{1}{6}(6-3x)=\frac{2}{5}x -3$;
(2) $0.2x - \frac{2}{3}(x+3)= -x +3$;
(3) $\frac{3}{2}(x+1)-3=4 - \frac{7}{2}(x+1)$;
(4) $30\%(2x-1)+20\%(x+5)=30×5\%$;
(5) $\frac{3x-2}{2}-(2-x)=x$;
(6) $\frac{x-3}{3}-\frac{2x-5}{4}=1$;
(7) $\frac{x+1}{2}-1=\frac{2-3x}{3}$;
(8) $6(\frac{1}{2}x -4)+4(3-\frac{2}{5}x)=9(\frac{1}{2}x -1)$。
答案
(1) $x= \frac{40}{9}$
(2) $x= \frac{75}{8}$
(3) $x= \frac{2}{5}$
(4) $x=1$
(5) $x=2$
(6) $x= -\frac{9}{2}$
(7) $x= \frac{7}{9}$
(8) $x= -\frac{30}{31}$
(2) $x= \frac{75}{8}$
(3) $x= \frac{2}{5}$
(4) $x=1$
(5) $x=2$
(6) $x= -\frac{9}{2}$
(7) $x= \frac{7}{9}$
(8) $x= -\frac{30}{31}$
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