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一、填空题
1. $3\sqrt{2} - 10\sqrt{2} × (-3) =$
2. $(-12) - (-12) ÷ \sqrt{(-6)^2} =$
3. $\sqrt[3]{27} × (-5) - (-25) ÷ 5 =$
4. $(-5) - (-5) × \sqrt[3]{\dfrac{1}{125}} =$
5. $8 × \sqrt[3]{-\dfrac{27}{64}} × (-4) +5 =$
6. $36.9 × (-\dfrac{1}{5}) -73.1 ÷ \sqrt[3]{125} =$
1. $3\sqrt{2} - 10\sqrt{2} × (-3) =$
$33\sqrt{2}$
2. $(-12) - (-12) ÷ \sqrt{(-6)^2} =$
$-10$
3. $\sqrt[3]{27} × (-5) - (-25) ÷ 5 =$
$-10$
4. $(-5) - (-5) × \sqrt[3]{\dfrac{1}{125}} =$
$-4$
5. $8 × \sqrt[3]{-\dfrac{27}{64}} × (-4) +5 =$
$29$
6. $36.9 × (-\dfrac{1}{5}) -73.1 ÷ \sqrt[3]{125} =$
$-22$
答案
1. $33\sqrt{2}$
2. $-10$
3. $-10$
4. $-4$
5. $29$
6. $-22$
2. $-10$
3. $-10$
4. $-4$
5. $29$
6. $-22$
二、计算题
7. $(-\sqrt{36}) × (-3) + 2 × (-4)$
8. $(-23) ÷ (-3) × \sqrt{\frac{1}{9}}$
9. $-1^{25} + \sqrt{9} + \sqrt[3]{2\frac{10}{27}}$
10. $1 - (-99\frac{6}{7}) × 14 ÷ \sqrt[3]{-8}$
11. $(\sqrt{2} - 1)^0 + |-3| - \sqrt[3]{27} - (-1)^{2026}$
12. $\sqrt[3]{-64} + \sqrt{16} × \sqrt{\frac{9}{4}} ÷ (-\sqrt{2})^2$
13. 一题多解 $\sqrt{(-25)^2} × 36 - (-36) × \sqrt[3]{27} + 36 × (-\sqrt[3]{-8}) + (-36) × |-\sqrt{100}|$
7. $(-\sqrt{36}) × (-3) + 2 × (-4)$
8. $(-23) ÷ (-3) × \sqrt{\frac{1}{9}}$
9. $-1^{25} + \sqrt{9} + \sqrt[3]{2\frac{10}{27}}$
10. $1 - (-99\frac{6}{7}) × 14 ÷ \sqrt[3]{-8}$
11. $(\sqrt{2} - 1)^0 + |-3| - \sqrt[3]{27} - (-1)^{2026}$
12. $\sqrt[3]{-64} + \sqrt{16} × \sqrt{\frac{9}{4}} ÷ (-\sqrt{2})^2$
13. 一题多解 $\sqrt{(-25)^2} × 36 - (-36) × \sqrt[3]{27} + 36 × (-\sqrt[3]{-8}) + (-36) × |-\sqrt{100}|$
答案
7. 10
8. $\dfrac{23}{9}$
9. $\dfrac{10}{3}$
10. $-698$
11. 0
12. $-1$
13. 解法一 原式 = 25×36+36×3+36×2-36×10 = 900+108+72-360 = 720.
解法二 原式 = 25×36+36×3+36×2-36×10 = 36×(25+3+2-10) = 36×20 = 720.
8. $\dfrac{23}{9}$
9. $\dfrac{10}{3}$
10. $-698$
11. 0
12. $-1$
13. 解法一 原式 = 25×36+36×3+36×2-36×10 = 900+108+72-360 = 720.
解法二 原式 = 25×36+36×3+36×2-36×10 = 36×(25+3+2-10) = 36×20 = 720.
