2025年通城学典初中数学运算能手七年级上册苏科版第32页答案
1. $(-3)÷ \left(\frac{1}{3}\right)= $

答案

-9

解析

$(-3)÷\left(\frac{1}{3}\right)=(-3)×3=-9$
2. $(-56)× \frac{1}{8}= $

答案

-7
3. $\frac{1}{78}÷ \left(-\frac{1}{13}\right)= $

答案

$-\frac{1}{6}$

解析

$\frac{1}{78}÷\left(-\frac{1}{13}\right)=\frac{1}{78}×(-13)=-\frac{13}{78}=-\frac{1}{6}$
4. $\left(-2\frac{3}{5}\right)× \frac{10}{13}= $

答案

-2

解析

$-2\frac{3}{5} = -\frac{13}{5}$,$-\frac{13}{5}×\frac{10}{13} = -2$
5. $( )÷ (-27)= 5$

答案

-135

解析

设括号里的数为$x$,则$x÷(-27)=5$,$x = 5×(-27)=-135$
-135
6. $126÷ ( )= -21$

答案

-6

解析

设括号内的数为$x$,则$126÷ x=-21$,解得$x=126÷(-21)=-6$。
-6
7. $( )× (-12)= -144$

答案

12
8. $(-13)× ( )= 52$

答案

-4

解析

设括号内的数为$x$,则$(-13)×x = 52$,解得$x = 52÷(-13) = -4$
-4
9. $(-81)÷ \frac{9}{5}× \frac{5}{9}$

答案

-25

解析

$(-81)÷\frac{9}{5}×\frac{5}{9}$
$=(-81)×\frac{5}{9}×\frac{5}{9}$
$=-45×\frac{5}{9}$
$=-25$
10. $(-0.01)× (-0.1)÷ 0.001$

答案

1

解析

$(-0.01)×(-0.1) = 0.001$
$0.001÷0.001 = 1$
1
11. $208÷ \left(-1-\frac{4}{5}\right)× 0$

答案

0

解析

$208÷\left(-1-\frac{4}{5}\right)×0$
$=208÷\left(-\frac{9}{5}\right)×0$
$=0$
12. $\left(0.625-\frac{1}{6}+\frac{7}{12}\right)÷ \left(-\frac{1}{24}\right)$

答案

-25

解析

$\left(0.625 - \frac{1}{6} + \frac{7}{12}\right) ÷ \left(-\frac{1}{24}\right)$
$=\left(\frac{5}{8} - \frac{1}{6} + \frac{7}{12}\right) × (-24)$
$=\frac{5}{8} × (-24) - \frac{1}{6} × (-24) + \frac{7}{12} × (-24)$
$=-15 + 4 - 14$
$=-25$
13. $36.5× (-1.28)+(-63.5)× 1.28$

答案

-128

解析

$36.5×(-1.28)+(-63.5)×1.28$
$=-36.5×1.28-63.5×1.28$
$=1.28×(-36.5-63.5)$
$=1.28×(-100)$
$=-128$
14. $\left(-2\frac{13}{16}\right)÷ \left(\frac{3}{4}× \frac{9}{8}\right)$

答案

$-\frac{10}{3}$

解析

$(-2\frac{13}{16})÷(\frac{3}{4}×\frac{9}{8})$
$=(-\frac{45}{16})÷\frac{27}{32}$
$=(-\frac{45}{16})×\frac{32}{27}$
$=-\frac{45×32}{16×27}$
$=-\frac{1440}{432}$
$=-\frac{10}{3}$
15. $\left(-2\frac{2}{5}\right)× \left[\left(+\frac{5}{6}\right)÷ \left(-\frac{2}{3}\right)\right]$

答案

3

解析

$\begin{aligned}\left(-2\frac{2}{5}\right)× \left[\left(+\frac{5}{6}\right)÷ \left(-\frac{2}{3}\right)\right]&=-\frac{12}{5}×\left[\frac{5}{6}×\left(-\frac{3}{2}\right)\right]\\&=-\frac{12}{5}×\left(-\frac{5}{4}\right)\\&=3\end{aligned}$
16. $7\frac{1}{3}× \left(-\frac{1}{12}\right)÷ \left(\frac{1}{9}÷ \frac{3}{14}\right)$

答案

$-\frac{33}{28}$

解析

$7\frac{1}{3}×\left(-\frac{1}{12}\right)÷\left(\frac{1}{9}÷\frac{3}{14}\right)$
$=\frac{22}{3}×\left(-\frac{1}{12}\right)÷\left(\frac{1}{9}×\frac{14}{3}\right)$
$=\frac{22}{3}×\left(-\frac{1}{12}\right)÷\frac{14}{27}$
$=\frac{22}{3}×\left(-\frac{1}{12}\right)×\frac{27}{14}$
$=-\frac{22×1×27}{3×12×14}$
$=-\frac{22×9}{12×14}$
$=-\frac{198}{168}$
$=-\frac{33}{28}$