2025年通城学典初中数学运算能手七年级上册苏科版第72页答案
1. $-\frac{2}{3} × \frac{9}{4} = $

答案

$-\frac{3}{2}$

解析

$-\frac{2}{3} × \frac{9}{4} = -\frac{2 × 9}{3 × 4} = -\frac{18}{12} = -\frac{3}{2}$
2. $3\frac{1}{3} × (-0.12) = $

答案

$-\frac{2}{5}$

解析

$3\frac{1}{3}×(-0.12)$
$=\frac{10}{3}×(-\frac{3}{25})$
$=-\frac{10×3}{3×25}$
$=-\frac{2}{5}$
3. $(+18) ÷ (-6) = $

答案

$-3$
4. $\frac{1}{7} ÷ (-7) = $

答案

$-\frac{1}{49}$

解析

$\frac{1}{7} ÷ (-7) = \frac{1}{7} × \left(-\frac{1}{7}\right) = -\frac{1}{49}$
5. $(-\frac{3}{7}) ÷ (-\frac{3}{35}) = $

答案

5

解析

$(-\frac{3}{7}) ÷ (-\frac{3}{35})$
$=(-\frac{3}{7}) × (-\frac{35}{3})$
$=\frac{3}{7} × \frac{35}{3}$
$=5$
6. $35\frac{7}{9} ÷ (-7) = $

答案

$-5\frac{1}{9}$

解析

$35\frac{7}{9} ÷ (-7)$
$=\left(35 + \frac{7}{9}\right)×\left(-\frac{1}{7}\right)$
$=35×\left(-\frac{1}{7}\right) + \frac{7}{9}×\left(-\frac{1}{7}\right)$
$=-5 - \frac{1}{9}$
$=-5\frac{1}{9}$
7. $(-3) × (-4) × (-5) = $

答案

$-60$

解析

$(-3) × (-4) × (-5)$
$=12 × (-5)$
$=-60$
8. $-37 ÷ 4 × \frac{1}{4} = $

答案

$-\frac{37}{16}$

解析

$-37÷4×\frac{1}{4}=-37×\frac{1}{4}×\frac{1}{4}=-\frac{37}{16}$
9. $(-3) ÷ (-1\frac{3}{4}) × 0.75 = $

答案

$\frac{9}{7}$

解析

$(-3) ÷ (-1\frac{3}{4}) × 0.75$
$=(-3) ÷ (-\frac{7}{4}) × \frac{3}{4}$
$=(-3) × (-\frac{4}{7}) × \frac{3}{4}$
$=3 × \frac{4}{7} × \frac{3}{4}$
$=3 × \frac{3}{7}$
$=\frac{9}{7}$
10. $-49 × (-\frac{4}{7}) ÷ (+1\frac{3}{4}) = $

答案

16

解析

$-49×\left(-\frac{4}{7}\right)÷\left(+1\frac{3}{4}\right)$
$=-49×\left(-\frac{4}{7}\right)÷\frac{7}{4}$
$=-49×\left(-\frac{4}{7}\right)×\frac{4}{7}$
$=(-49)×\left(-\frac{4}{7}×\frac{4}{7}\right)$
$=(-49)×\left(-\frac{16}{49}\right)$
$=16$
11. $(-15) × (-17) × (-1001) × 0$

答案

0

解析

$(-15) × (-17) × (-1001) × 0=0$
12. $(-\frac{1}{6} - \frac{3}{20} + \frac{4}{5} - \frac{7}{12}) × (-60)$

答案

6

解析

$(-\frac{1}{6} - \frac{3}{20} + \frac{4}{5} - \frac{7}{12}) × (-60)$
$=-\frac{1}{6}×(-60)-\frac{3}{20}×(-60)+\frac{4}{5}×(-60)-\frac{7}{12}×(-60)$
$=10 + 9 - 48 + 35$
$=6$
13. $(-0.25) × (-\frac{4}{7}) × 4 × (-7)$

答案

$-4$

解析

$(-0.25) × (-\frac{4}{7}) × 4 × (-7)$
$=(-\frac{1}{4}) × (-\frac{4}{7}) × 4 × (-7)$
$=[(-\frac{1}{4})×4]×[(-\frac{4}{7})×(-7)]$
$=(-1)×4$
$=-4$
14. $(-45) ÷ [(-\frac{1}{3}) ÷ (-\frac{2}{5})]$

答案

$-54$

解析

$(-45) ÷ [(-\frac{1}{3}) ÷ (-\frac{2}{5})]$
$=(-45) ÷ [(-\frac{1}{3}) × (-\frac{5}{2})]$
$=(-45) ÷ \frac{5}{6}$
$=(-45) × \frac{6}{5}$
$=-54$
15. $12 ÷ (\frac{1}{6} - \frac{1}{2}) × |\frac{1}{2} - 3|$

答案

$-90$

解析

$12÷\left(\frac{1}{6}-\frac{1}{2}\right)×\left|\frac{1}{2}-3\right|$
$=12÷\left(\frac{1}{6}-\frac{3}{6}\right)×\left|-\frac{5}{2}\right|$
$=12÷\left(-\frac{2}{6}\right)×\frac{5}{2}$
$=12÷\left(-\frac{1}{3}\right)×\frac{5}{2}$
$=12×(-3)×\frac{5}{2}$
$=-36×\frac{5}{2}$
$=-90$
16. $-|-15| ÷ (\frac{1}{3} - 1\frac{1}{2} - 3) ÷ \frac{18}{5}$

答案

1

解析

$-|-15| ÷ (\frac{1}{3} - 1\frac{1}{2} - 3) ÷ \frac{18}{5}$
$=-15 ÷ (\frac{1}{3} - \frac{3}{2} - 3) ÷ \frac{18}{5}$
$=-15 ÷ (\frac{2}{6} - \frac{9}{6} - \frac{18}{6}) ÷ \frac{18}{5}$
$=-15 ÷ (-\frac{25}{6}) ÷ \frac{18}{5}$
$=-15 × (-\frac{6}{25}) × \frac{5}{18}$
$=\frac{90}{25} × \frac{5}{18}$
$=\frac{18}{5} × \frac{5}{18}$
$=1$