解下列方程:
(1) $5x - [1 - (3 + 2x)] = 7$;
(2) $3(x - 6) - 9[2 - 2(2 - x)] = 45$;
(3) $4[2(2x + 1) + 1] = 6x + 1$;
(4) $2[x - (x + 2)] = 5(x - 2)$;
(5) $3[4(4x - 1) - 8] = 3x + 2$;
(6) $5\{7x - 14[x - 2(x - 1) - 1] - 1\} = x - 1$;
(7) $1 - \{1 - [1 - (1 - x) - x] - x\} + x = 2$;
(8) $2\{3[4(5x - 1) - 8] - 20\} - 7 = 1$。
(1) $5x - [1 - (3 + 2x)] = 7$;
(2) $3(x - 6) - 9[2 - 2(2 - x)] = 45$;
(3) $4[2(2x + 1) + 1] = 6x + 1$;
(4) $2[x - (x + 2)] = 5(x - 2)$;
(5) $3[4(4x - 1) - 8] = 3x + 2$;
(6) $5\{7x - 14[x - 2(x - 1) - 1] - 1\} = x - 1$;
(7) $1 - \{1 - [1 - (1 - x) - x] - x\} + x = 2$;
(8) $2\{3[4(5x - 1) - 8] - 20\} - 7 = 1$。
答案
(1)$x=\dfrac{5}{7}$
(2)$x=-3$
(3)$x=-\dfrac{11}{10}$
(4)$x=\dfrac{6}{5}$
(5)$x=\dfrac{38}{45}$
(6)$x=\dfrac{37}{52}$
(7)$x=1$
(8)$x=1$
(2)$x=-3$
(3)$x=-\dfrac{11}{10}$
(4)$x=\dfrac{6}{5}$
(5)$x=\dfrac{38}{45}$
(6)$x=\dfrac{37}{52}$
(7)$x=1$
(8)$x=1$
登录