2026年通成学典课时作业本八年级数学下册苏科版宿迁专版第83页答案
8. 分式$\dfrac{a}{a^{2} - b^{2}}$,$\dfrac{b}{a^{2} + 2ab + b^{2}}$,$\dfrac{c}{a^{2} - 2ab + b^{2}}$的最简公分母是
$ (a - b)^{2}(a + b)^{2} $
.

答案

8. $ (a - b)^{2}(a + b)^{2} $
9. 已知最简分式$\dfrac{1}{2y^{a}}$与$\dfrac{-1}{bxy}$($a$,$b$是常数,且$b ≠ 0$)的最简公分母为$10xy^{3}$,则$a$的值为
3
,$b$的值为
5或10
.

答案

9. 3 5或10

解析

3;5或10
10. 通分:
(1) $\dfrac{a + b}{(a + 2b)(a - 2b)}$,$\dfrac{a + b}{(2b + a)(2b - a)}$;
(2) $\dfrac{a}{a^{2} - 4a + 4}$,$\dfrac{b}{2a^{2} - 8a + 8}$,$\dfrac{c}{2a - 4}$;

(3) $\dfrac{2m}{9m + 15n}$,$\dfrac{3n}{6m - 10n}$,$\dfrac{2m + 5}{25n^{2} - 9m^{2}}$;
(4) $\dfrac{x}{x - y}$,$\dfrac{y}{x^{2} + 2xy + y^{2}}$,$\dfrac{2}{y^{2} - x^{2}}$.

答案

10. (1) $ \frac{a + b}{(a + 2b)(a - 2b)} $,$ -\frac{a + b}{(a + 2b)(a - 2b)} $ (2) $ \frac{2a}{2(a - 2)^{2}} $,$ \frac{b}{2(a - 2)^{2}} $,$ \frac{c(a - 2)}{2(a - 2)^{2}} $ (3) $ \frac{4m(3m - 5n)}{6(3m + 5n)(3m - 5n)} $,$ \frac{9n(3m + 5n)}{6(3m + 5n)(3m - 5n)} $,$ -\frac{6(2m + 5)}{6(3m + 5n)(3m - 5n)} $ (4) $ \frac{x(x + y)^{2}}{(x - y)(x + y)^{2}} $,$ \frac{y(x - y)}{(x - y)(x + y)^{2}} $,$ -\frac{2(x + y)}{(x - y)(x + y)^{2}} $

解析

解:$\dfrac{x}{x - y}=\dfrac{x(x + y)^{2}}{(x - y)(x + y)^{2}}$,$\dfrac{y}{x^{2} + 2xy + y^{2}}=\dfrac{y(x - y)}{(x - y)(x + y)^{2}}$,$\dfrac{2}{y^{2} - x^{2}}=-\dfrac{2(x + y)}{(x - y)(x + y)^{2}}$
11. 已知分式$\dfrac{1}{3x^{2} - 3}$,$\dfrac{2}{x - 1}$.若$a$是这两个分式的分母的公因式,$b$是这两个分式的最简公分母,且$\dfrac{b}{a} = - 6$,试求这两个分式的值.

答案

11. 根据题意,得 $ a = x - 1 $,$ b = 3(x + 1)(x - 1) $。$ \because \frac{b}{a} = -6 $,$ \therefore \frac{3(x + 1)(x - 1)}{x - 1} = -6 $,即 $ 3(x + 1) = -6 $,解得 $ x = -3 $。$ \therefore \frac{1}{3x^{2} - 3} = \frac{1}{3× (-3)^{2} - 3} = \frac{1}{24} $,$ \frac{2}{x - 1} = \frac{2}{-3 - 1} = -\frac{1}{2} $