10. 新定义:对非负数$x$“四舍五入”到个位的值记为$<x>$,即当$n$为非负整数时,若$n-\frac{1}{2}≤x<n+\frac{1}{2}$,则$<x>=n$;反之,当$n$为非负整数时,若$<x>=n$,则$n-\frac{1}{2}≤x<n+\frac{1}{2}$.例如,$<0>=<0.48>=0,<0.64>=<1.499>=1,<2>=2,<3.5>=<4.12>=4$,……试解决下列问题.
(1)填空:①$<π>=$
(2)求满足$<x>=\frac{4}{3}x$的所有非负数$x$的值.
(3)若关于$x$的不等式组$\begin{cases}\frac{2x-4}{3}≤x-1,\\<a>-x>0\end{cases}$的整数解恰有3个,求$a$的取值范围.
(1)填空:①$<π>=$
3
;②若$<2x−1>=3$,则实数$x$的取值范围为$1.75 ≤ x<2.25$
.(2)求满足$<x>=\frac{4}{3}x$的所有非负数$x$的值.
(3)若关于$x$的不等式组$\begin{cases}\frac{2x-4}{3}≤x-1,\\<a>-x>0\end{cases}$的整数解恰有3个,求$a$的取值范围.
答案
(1)①3 ②$1.75 ≤ x<2.25$
(2)$\because x ≥ 0$,$\frac{4}{3}x$为整数,设$\frac{4}{3}x=k$,$k$为整数,
则$x=\frac{3}{4}k$,$\therefore <\frac{3}{4}k>=k$,
$\therefore k-\frac{1}{2} ≤ \frac{3}{4}k<k+\frac{1}{2}$,且$k ≥ 0$,
$\therefore 0 ≤ k ≤ 2$,$\therefore k=0,1,2$,则$x=0$,$\frac{3}{4}$,$\frac{3}{2}$.
(3)解不等式组得$-1 ≤ x<<a>$,
由不等式组的整数解恰有3个,得$1<<a> ≤ 2$,
$\therefore <a>=2$,$\therefore 1.5 ≤ a<2.5$.
(2)$\because x ≥ 0$,$\frac{4}{3}x$为整数,设$\frac{4}{3}x=k$,$k$为整数,
则$x=\frac{3}{4}k$,$\therefore <\frac{3}{4}k>=k$,
$\therefore k-\frac{1}{2} ≤ \frac{3}{4}k<k+\frac{1}{2}$,且$k ≥ 0$,
$\therefore 0 ≤ k ≤ 2$,$\therefore k=0,1,2$,则$x=0$,$\frac{3}{4}$,$\frac{3}{2}$.
(3)解不等式组得$-1 ≤ x<<a>$,
由不等式组的整数解恰有3个,得$1<<a> ≤ 2$,
$\therefore <a>=2$,$\therefore 1.5 ≤ a<2.5$.
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