1.(2024·江阴期中)代数式$\frac{x + y}{6}$,$\frac{x}{2x}$,$\frac{x - y}{a + b}$,$\frac{x}{\pi}$中分式有( )
A. 4个
B. 3个
C. 2个
D. 1个
A. 4个
B. 3个
C. 2个
D. 1个
答案
C
2.(2023·镇江期末)小明在电脑上1分钟录入汉字50个,小明的爸爸1分钟录入汉字30个.如果小明和爸爸各录入$x$个汉字,那么爸爸比小明多用的分钟数为( )
A. $\frac{x}{50} - \frac{x}{30}$
B. $\frac{x}{30} - \frac{x}{50}$
C. $\frac{30}{x} - \frac{50}{x}$
D. $\frac{50}{x} - \frac{30}{x}$
A. $\frac{x}{50} - \frac{x}{30}$
B. $\frac{x}{30} - \frac{x}{50}$
C. $\frac{30}{x} - \frac{50}{x}$
D. $\frac{50}{x} - \frac{30}{x}$
答案
B
3.若分式$\frac{x + 1}{x - 2}$在实数范围内有意义,则$x$_______.若分式$\frac{|x| - 2}{2 - x}$的值为0,则$x =$_______.
答案
$\neq 2$ $-2$
4.已知$a:b:c = 1:2:3$,则分式$\frac{a + b}{a - b + c}$的值为_______.
答案
$\frac{3}{2}$
5.$x$取何值时,下列分式有意义?
(1)$\frac{2x + 1}{3x + 2}$; (2)$\frac{3}{x^{2} + 1}$; (3)$\frac{3x}{|-x| + 2}$; (4)$\frac{3x + 1}{x^{2} - 9}$.
(1)$\frac{2x + 1}{3x + 2}$; (2)$\frac{3}{x^{2} + 1}$; (3)$\frac{3x}{|-x| + 2}$; (4)$\frac{3x + 1}{x^{2} - 9}$.
答案
解:(1)根据题意,得$3x + 2\neq 0$,
解得$x\neq -\frac{2}{3}$.
(2)根据题意,得$x^{2}+1\neq 0$,
$\because x^{2}+1>0$,
$\therefore x$取全体实数.
(3)根据题意,得$|-x| + 2\neq 0$,即$|x|\neq -2$,
$\because |x|\geq 0$,
$\therefore x$取全体实数.
(4)根据题意,得$x^{2}-9\neq 0$,
解得$x\neq \pm 3$.
解得$x\neq -\frac{2}{3}$.
(2)根据题意,得$x^{2}+1\neq 0$,
$\because x^{2}+1>0$,
$\therefore x$取全体实数.
(3)根据题意,得$|-x| + 2\neq 0$,即$|x|\neq -2$,
$\because |x|\geq 0$,
$\therefore x$取全体实数.
(4)根据题意,得$x^{2}-9\neq 0$,
解得$x\neq \pm 3$.
6.求下列分式的值:
(1)$\frac{5x}{3x^{2} - 2}$,其中$x = \frac{1}{2}$; (2)$\frac{a^{2} - b^{2}}{3a - 6b}$,其中$a = \frac{5}{6}$,$b = \frac{1}{6}$.
(1)$\frac{5x}{3x^{2} - 2}$,其中$x = \frac{1}{2}$; (2)$\frac{a^{2} - b^{2}}{3a - 6b}$,其中$a = \frac{5}{6}$,$b = \frac{1}{6}$.
答案
解:(1)当$x = \frac{1}{2}$时,原式$=\frac{5\times\frac{1}{2}}{3\times(\frac{1}{2})^{2}-2}=-2$.
(2)当$a = \frac{5}{6}$,$b = \frac{1}{6}$时,$a + b = \frac{5}{6}+\frac{1}{6}=1$,$a - b = \frac{5}{6}-\frac{1}{6}=\frac{2}{3}$,$a - 2b = \frac{5}{6}-\frac{2}{6}=\frac{1}{2}$,
$\therefore$原式$=\frac{(a + b)(a - b)}{3(a - 2b)}=\frac{1\times\frac{2}{3}}{3\times\frac{1}{2}}=\frac{4}{9}$.
(2)当$a = \frac{5}{6}$,$b = \frac{1}{6}$时,$a + b = \frac{5}{6}+\frac{1}{6}=1$,$a - b = \frac{5}{6}-\frac{1}{6}=\frac{2}{3}$,$a - 2b = \frac{5}{6}-\frac{2}{6}=\frac{1}{2}$,
$\therefore$原式$=\frac{(a + b)(a - b)}{3(a - 2b)}=\frac{1\times\frac{2}{3}}{3\times\frac{1}{2}}=\frac{4}{9}$.
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