1. 比较下面各组分数的大小。
(1)$\frac{12}{21}$和$\frac{16}{19}$
(2)$\frac{5}{11}$、$\frac{6}{13}$和$\frac{15}{32}$
(1)$\frac{12}{21}$和$\frac{16}{19}$
(2)$\frac{5}{11}$、$\frac{6}{13}$和$\frac{15}{32}$
答案
(1) $\frac{12}{21}=\frac{48}{84}$,$\frac{16}{19}=\frac{48}{57}$,因为$\frac{48}{84}<\frac{48}{57}$,所以$\frac{12}{21}<\frac{16}{19}$
(2) $\frac{5}{11}=\frac{30}{66}$,$\frac{6}{13}=\frac{30}{65}$,$\frac{15}{32}=\frac{30}{64}$,因为$\frac{30}{66}<\frac{30}{65}<\frac{30}{64}$,所以$\frac{5}{11}<\frac{6}{13}<\frac{15}{32}$
(2) $\frac{5}{11}=\frac{30}{66}$,$\frac{6}{13}=\frac{30}{65}$,$\frac{15}{32}=\frac{30}{64}$,因为$\frac{30}{66}<\frac{30}{65}<\frac{30}{64}$,所以$\frac{5}{11}<\frac{6}{13}<\frac{15}{32}$
2. 把$\frac{1}{5}$、$\frac{8}{41}$、$\frac{12}{61}$、$\frac{6}{31}$和$\frac{24}{121}$按从大到小的顺序排列。
答案
$\frac{1}{5}>\frac{24}{121}>\frac{12}{61}>\frac{8}{41}>\frac{6}{31}$
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