Ⅳ.句型合并:用括号内的关系代词将两个句子合并为一个含定语从句的复合句。
1. The band is very popular. They won the music competition last year. (that)
→
2. The girl is my deskmate. She is playing the guitar on the stage. (who)
→
3. The painting is very valuable. It was painted by a famous artist. (which)
→
4. The story is funny. It tells us about a clever cat. (that)
→
5. The doctor is very experienced. He treated my grandma last week. (who)
→
1. The band is very popular. They won the music competition last year. (that)
→
The band that won the music competition last year is very popular.
2. The girl is my deskmate. She is playing the guitar on the stage. (who)
→
The girl who is playing the guitar on the stage is my deskmate.
3. The painting is very valuable. It was painted by a famous artist. (which)
→
The painting which was painted by a famous artist is very valuable.
4. The story is funny. It tells us about a clever cat. (that)
→
The story that tells us about a clever cat is funny.
5. The doctor is very experienced. He treated my grandma last week. (who)
→
The doctor who treated my grandma last week is very experienced.
答案
1. The band that won the music competition last year is very popular.
2. The girl who is playing the guitar on the stage is my deskmate.
3. The painting which was painted by a famous artist is very valuable.
4. The story that tells us about a clever cat is funny.
5. The doctor who treated my grandma last week is very experienced.
2. The girl who is playing the guitar on the stage is my deskmate.
3. The painting which was painted by a famous artist is very valuable.
4. The story that tells us about a clever cat is funny.
5. The doctor who treated my grandma last week is very experienced.
解析
【分析】
这类句型合并题的解题思路为:1. 确定两个句子中共同描述的名词(即先行词);2. 根据先行词指代的人/物,结合括号内的关系代词(that可指人或物,who指人,which指物);3. 将第二个句子转化为定语从句,紧跟在先行词后,调整语序形成通顺的复合句。
【解析】
1. 先行词为the band(物),选用关系代词that,将第二个句子转化为定语从句置于先行词后,得到:The band that won the music competition last year is very popular.
2. 先行词为the girl(人),选用关系代词who,将第二个句子转化为定语从句置于先行词后,得到:The girl who is playing the guitar on the stage is my deskmate.
3. 先行词为the painting(物),选用关系代词which,将第二个句子转化为定语从句置于先行词后,得到:The painting which was painted by a famous artist is very valuable.
4. 先行词为the story(物),选用关系代词that,将第二个句子转化为定语从句置于先行词后,得到:The story that tells us about a clever cat is funny.
5. 先行词为the doctor(人),选用关系代词who,将第二个句子转化为定语从句置于先行词后,得到:The doctor who treated my grandma last week is very experienced.
【答案】
1. The band that won the music competition last year is very popular.
2. The girl who is playing the guitar on the stage is my deskmate.
3. The painting which was painted by a famous artist is very valuable.
4. The story that tells us about a clever cat is funny.
5. The doctor who treated my grandma last week is very experienced.
【知识点】
定语从句的构成;关系代词的用法
【点评】
本题考查定语从句的基础应用,核心是掌握先行词与关系代词的匹配规则,属于初中英语语法基础题型,只要理清先行词和定语从句的位置即可完成,是常考的基础考点。
【难度系数】
0.7
这类句型合并题的解题思路为:1. 确定两个句子中共同描述的名词(即先行词);2. 根据先行词指代的人/物,结合括号内的关系代词(that可指人或物,who指人,which指物);3. 将第二个句子转化为定语从句,紧跟在先行词后,调整语序形成通顺的复合句。
【解析】
1. 先行词为the band(物),选用关系代词that,将第二个句子转化为定语从句置于先行词后,得到:The band that won the music competition last year is very popular.
2. 先行词为the girl(人),选用关系代词who,将第二个句子转化为定语从句置于先行词后,得到:The girl who is playing the guitar on the stage is my deskmate.
3. 先行词为the painting(物),选用关系代词which,将第二个句子转化为定语从句置于先行词后,得到:The painting which was painted by a famous artist is very valuable.
4. 先行词为the story(物),选用关系代词that,将第二个句子转化为定语从句置于先行词后,得到:The story that tells us about a clever cat is funny.
5. 先行词为the doctor(人),选用关系代词who,将第二个句子转化为定语从句置于先行词后,得到:The doctor who treated my grandma last week is very experienced.
【答案】
1. The band that won the music competition last year is very popular.
2. The girl who is playing the guitar on the stage is my deskmate.
3. The painting which was painted by a famous artist is very valuable.
4. The story that tells us about a clever cat is funny.
5. The doctor who treated my grandma last week is very experienced.
【知识点】
定语从句的构成;关系代词的用法
【点评】
本题考查定语从句的基础应用,核心是掌握先行词与关系代词的匹配规则,属于初中英语语法基础题型,只要理清先行词和定语从句的位置即可完成,是常考的基础考点。
【难度系数】
0.7
Ⅴ.信息匹配题
A. 将音乐家与对应的信息匹配。
Musicians
Profile
(
(
(
(
(
B. 将合适的选项填入句子中。

1. I think pop music is
2. I like rock music because it is
3. My favourite music is classical music because it's
4. The reason why I like folk music is that it is
5. I recommend jazz because it is
6. Country music is popular for being
A. 将音乐家与对应的信息匹配。
Musicians
Profile
(
B
)1. Xian Xinghai A. The composer of The Moonlight Sonata(奏鸣曲)(
C
)2. Nie Er B. The composer of The Yellow River Cantata(大合唱)(
D
)3. Mozart C. The composer of March of the Volunteers(
A
)4. Beethoven D. A famous Austrian composer of the Classical era(
E
)5. Tchaikovsky E. A Russian composer known for Swan LakeB. 将合适的选项填入句子中。
1. I think pop music is
B
2. I like rock music because it is
D
3. My favourite music is classical music because it's
A
4. The reason why I like folk music is that it is
E
5. I recommend jazz because it is
F
6. Country music is popular for being
C
答案
1. 音乐家匹配:1-5 BCDAE
2. 音乐特征连线:1-6 BDAEFC
2. 音乐特征连线:1-6 BDAEFC
解析
【分析】
本题分为音乐家匹配和音乐特征匹配两部分。首先处理音乐家匹配:需熟记中外著名音乐家的代表作品或身份,冼星海是《黄河大合唱》的创作者,对应选项B;聂耳是《义勇军进行曲》的创作者,对应选项C;莫扎特是奥地利古典时期著名作曲家,对应选项D;贝多芬是《月光奏鸣曲》的创作者,对应选项A;柴可夫斯基是《天鹅湖》的俄国作曲家,对应选项E,因此音乐家匹配结果为1-B、2-C、3-D、4-A、5-E,即BCDAE。接着处理音乐特征匹配:需明确不同音乐类型的典型特点,流行音乐简单易记对应B,摇滚音乐强烈响亮对应D,古典音乐传统优雅对应A,民间音乐充满当地文化对应E,爵士乐柔和安静对应C,乡村音乐活泼自由对应F,因此音乐特征匹配结果为1-B、2-D、3-A、4-E、5-C、6-F,即BDAEFC。
【解析】
一、音乐家匹配步骤:
1. 冼星海(Xian Xinghai)的代表作品是《黄河大合唱》,对应选项B;
2. 聂耳(Nie Er)的代表作品是《义勇军进行曲》,对应选项C;
3. 莫扎特(Mozart)是奥地利古典时期的著名作曲家,对应选项D;
4. 贝多芬(Beethoven)是《月光奏鸣曲》的创作者,对应选项A;
5. 柴可夫斯基(Tchaikovsky)是《天鹅湖》的俄国作曲家,对应选项E;
故音乐家匹配答案为1-B、2-C、3-D、4-A、5-E,即BCDAE。
二、音乐特征匹配步骤:
1. 流行音乐(pop music)的特点是简单易记,对应选项B;
2. 摇滚音乐(rock music)的特点是强烈响亮,对应选项D;
3. 古典音乐(classical music)的特点是传统优雅,对应选项A;
4. 民间音乐(folk music)的特点是充满当地文化,对应选项E;
5. 爵士乐(jazz)的特点是柔和安静,对应选项C;
6. 乡村音乐(country music)的特点是活泼自由,对应选项F;
故音乐特征匹配答案为1-B、2-D、3-A、4-E、5-C、6-F,即BDAEFC。
【答案】
音乐家匹配:1-B、2-C、3-D、4-A、5-E(即BCDAE);音乐特征匹配:1-B、2-D、3-A、4-E、5-C、6-F(即BDAEFC)
【知识点】
音乐常识、中外音乐家、音乐类型特点
【点评】
本题围绕音乐基础常识展开,考查学生对中外著名音乐家及其作品、不同音乐类型特征的掌握情况,属于基础应用类题目,难度适中。
【难度系数】
0.3
本题分为音乐家匹配和音乐特征匹配两部分。首先处理音乐家匹配:需熟记中外著名音乐家的代表作品或身份,冼星海是《黄河大合唱》的创作者,对应选项B;聂耳是《义勇军进行曲》的创作者,对应选项C;莫扎特是奥地利古典时期著名作曲家,对应选项D;贝多芬是《月光奏鸣曲》的创作者,对应选项A;柴可夫斯基是《天鹅湖》的俄国作曲家,对应选项E,因此音乐家匹配结果为1-B、2-C、3-D、4-A、5-E,即BCDAE。接着处理音乐特征匹配:需明确不同音乐类型的典型特点,流行音乐简单易记对应B,摇滚音乐强烈响亮对应D,古典音乐传统优雅对应A,民间音乐充满当地文化对应E,爵士乐柔和安静对应C,乡村音乐活泼自由对应F,因此音乐特征匹配结果为1-B、2-D、3-A、4-E、5-C、6-F,即BDAEFC。
【解析】
一、音乐家匹配步骤:
1. 冼星海(Xian Xinghai)的代表作品是《黄河大合唱》,对应选项B;
2. 聂耳(Nie Er)的代表作品是《义勇军进行曲》,对应选项C;
3. 莫扎特(Mozart)是奥地利古典时期的著名作曲家,对应选项D;
4. 贝多芬(Beethoven)是《月光奏鸣曲》的创作者,对应选项A;
5. 柴可夫斯基(Tchaikovsky)是《天鹅湖》的俄国作曲家,对应选项E;
故音乐家匹配答案为1-B、2-C、3-D、4-A、5-E,即BCDAE。
二、音乐特征匹配步骤:
1. 流行音乐(pop music)的特点是简单易记,对应选项B;
2. 摇滚音乐(rock music)的特点是强烈响亮,对应选项D;
3. 古典音乐(classical music)的特点是传统优雅,对应选项A;
4. 民间音乐(folk music)的特点是充满当地文化,对应选项E;
5. 爵士乐(jazz)的特点是柔和安静,对应选项C;
6. 乡村音乐(country music)的特点是活泼自由,对应选项F;
故音乐特征匹配答案为1-B、2-D、3-A、4-E、5-C、6-F,即BDAEFC。
【答案】
音乐家匹配:1-B、2-C、3-D、4-A、5-E(即BCDAE);音乐特征匹配:1-B、2-D、3-A、4-E、5-C、6-F(即BDAEFC)
【知识点】
音乐常识、中外音乐家、音乐类型特点
【点评】
本题围绕音乐基础常识展开,考查学生对中外著名音乐家及其作品、不同音乐类型特征的掌握情况,属于基础应用类题目,难度适中。
【难度系数】
0.3
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