2025年课课练九年级数学下册苏科版第79页答案
例1 求满足下列各式的锐角$\alpha$:
(1)$2 \sin \alpha -\sqrt{3}=0$; (2)$\cos ( \alpha -25^{ \circ })=\dfrac{\sqrt{2}}{2}$;
(3)$\tan ^{2} \alpha -2\sqrt{3}\tan \alpha +3=0$; (4)$2 \cos ^{2} \alpha -5 \cos \alpha +2=0$.

答案

​解:$ 2sina=\sqrt{3}​$
$​sina=\frac {\sqrt{3}}{2}​$
​所以a=60°​
​解:a-25°=45°​
​a=70°​
​解:$ (tana-\sqrt{3})²= 0​$
$​tana=\sqrt{3}​$
​α=60°​
​解: (2cosa- 1)(cosa-2)= 0​
$​cosα=\frac {1}{2}$或cosa = 2(舍去)​
​所以a=60°​