1. 化简$-2(3x^2 - \frac{1}{2}xy) - 2xy + 6x^2$的结果是(
A.$9x^2$
B.$3$
C.$-xy$
D.$-3xy$
C
)A.$9x^2$
B.$3$
C.$-xy$
D.$-3xy$
答案
1. C
2. 加上$1+3a$等于$9a^2 - 3a + 9$的代数式为 (
A.$9a^2 + 8$
B.$9a^2 -6a +8$
C.$9a^2 -8$
D.$9a^2 -6a -8$
B
)A.$9a^2 + 8$
B.$9a^2 -6a +8$
C.$9a^2 -8$
D.$9a^2 -6a -8$
答案
2. B
3. (1) 化简:$2(x-y)+3y=\_\_\_\_\_\_$;
(2) 化简:$6x-3(2x+1)=\_\_\_\_\_\_$;
(2) 化简:$6x-3(2x+1)=\_\_\_\_\_\_$;
答案
3. (1) $2x+y$ (2) $-3$
(3)(教材P94例8变式)整式$3a^2 - b^2 - 2ab$与$-b^2 -4ab -3a^2$的差是
$6a^2+2ab$
.答案
(3) $6a^2+2ab$
4. 化简:
(1) $x - (2x - x^3 + 1)$;
(2) $m + (3m - 2) - (2m - 3)$;
(3) $3a^2 - (2a^2 + a) + (a^2 - 3a)$;
(4) $3(4x - 2y) - 4(-y + 8x)$;
(5) $3 - [\dfrac{9}{2}a - 2(a - 6)]$;
(6) $\dfrac{2x - 1}{3} - \dfrac{3x - 5}{2}$;
(1) $x - (2x - x^3 + 1)$;
(2) $m + (3m - 2) - (2m - 3)$;
(3) $3a^2 - (2a^2 + a) + (a^2 - 3a)$;
(4) $3(4x - 2y) - 4(-y + 8x)$;
(5) $3 - [\dfrac{9}{2}a - 2(a - 6)]$;
(6) $\dfrac{2x - 1}{3} - \dfrac{3x - 5}{2}$;
答案
4. (1) $x^3-x-1$ (2) $2m+1$ (3) $2a^2-4a$ (4) $-20x-2y$ (5) $-9-\frac{5}{2}a$ (6) $-\frac{5}{6}x+\frac{13}{6}$
5. 要使多项式$2x^2 - 2(7 + 3x - 2x^2) + mx^2$化简后不含$x$的二次项,则$m$的值是(
A.2
B.0
C.$-2$
D.$-6$
D
)A.2
B.0
C.$-2$
D.$-6$
答案
5. D
6. 若$M=3x^2 -5x +2$,$N=2x^2 -5x +1$,则$M,N$的大小关系是 (
A.$M>N$
B.$M=N$
C.$M<N$
D.以上都有可能
A
)A.$M>N$
B.$M=N$
C.$M<N$
D.以上都有可能
答案
6. A
$A=5x^2y - 3xy^2 + 4xy, B=3xy^2 - 2xy + x^2y, 则A+B=\underline{\hspace{5cm}}$
答案
7. $6x^2y+2xy$
8. (2025·相城区期末)在括号内添加一个单项式,使等式成立:$-a^2b - (\_\_\_\_\_\_)=a^2b.$
答案
8. $-2a^2b$
9. (教材P95练习第2题变式)(2024·德阳)若一个多项式加上$y^2 + 3xy - 4$,结果是$3xy + 2y^2 -5$,则这个多项式为
$y^2-1$
。答案
9. $y^2-1$
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