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6. 有甲、乙两筐苹果，已知甲筐中有 4.2 kg 苹果，如果从甲筐取出$\frac{3}{7}$给乙筐，那么两筐苹果就一样重。乙筐原来有多少千克苹果？
答案
6. 取出重量：$4.2 × \frac{3}{7} = 1.8(\mathrm{kg})$ 甲筐剩下：$4.2 - 1.8 = 2.4(\mathrm{kg})$
乙筐原来重量：$2.4 - 1.8 = 0.6(\mathrm{kg})$
乙筐原来重量：$2.4 - 1.8 = 0.6(\mathrm{kg})$
(1)$\frac{5}{6} × 7 × \frac{6}{5} = (\quad) × (\quad) × 7 = (\quad)$
答案
1. (1) $\frac{5}{6}$ $\frac{6}{5}$ 7
(2)$\frac{5}{8} × \frac{4}{25} + \frac{3}{8} × \frac{4}{25} = (\_\_\_\_\_\_ + \_\_\_\_\_\_) × (\_\_\_\_\_\_) = (\_\_\_\_\_\_)$
答案
1. (2) $\frac{5}{8}$ $\frac{3}{8}$ $\frac{4}{25}$ $\frac{4}{25}$
2. 计算下面各题。
$\frac{1}{8} × 32 × \frac{5}{2}$
$( \frac{5}{9} + \frac{3}{4} + \frac{7}{12} ) × 36$
$\frac{15}{13} - \frac{1}{3} × \frac{5}{4} - \frac{7}{12}$
$\frac{63}{100} × 101$
$\frac{6}{7} × (7 + 9) × \frac{1}{18}$
$\frac{1}{3} + \frac{2}{3} × \frac{5}{6}$
$\frac{1}{8} × 32 × \frac{5}{2}$
$( \frac{5}{9} + \frac{3}{4} + \frac{7}{12} ) × 36$
$\frac{15}{13} - \frac{1}{3} × \frac{5}{4} - \frac{7}{12}$
$\frac{63}{100} × 101$
$\frac{6}{7} × (7 + 9) × \frac{1}{18}$
$\frac{1}{3} + \frac{2}{3} × \frac{5}{6}$
答案
10 68 $\frac{2}{13}$ $63\frac{63}{100}$ $\frac{16}{21}$ $\frac{8}{9}$
3. 在○里填上 “＞”“＜” 或 “=”。
$\frac{7}{12} × \frac{1}{9} ◯ \frac{1}{9} × \frac{7}{12}$
$\frac{1}{2} × \frac{4}{5} + \frac{6}{5} ◯ \frac{1}{2} × (\frac{4}{5} + \frac{6}{5})$
$15 × \frac{3}{8} × \frac{1}{3} ◯ 15 × (\frac{3}{8} × \frac{1}{3})$
$99 × \frac{7}{100} ◯ 7 - \frac{7}{100}$
$\frac{7}{12} × \frac{1}{9} ◯ \frac{1}{9} × \frac{7}{12}$
$\frac{1}{2} × \frac{4}{5} + \frac{6}{5} ◯ \frac{1}{2} × (\frac{4}{5} + \frac{6}{5})$
$15 × \frac{3}{8} × \frac{1}{3} ◯ 15 × (\frac{3}{8} × \frac{1}{3})$
$99 × \frac{7}{100} ◯ 7 - \frac{7}{100}$
答案
= ＞ = =
