2026年同步练习册外语教学与研究出版社六年级英语上册外研版山东专版第12页答案
11 Read and finish. 读短文,完成下列各题。
Xiaoming gets 30 yuan as pocket money every week. Here is his plan for four weeks.

(
B
) 1. How much is the storybook?
A. 15 yuan. B. 10 yuan. C. 12 yuan.
(
A
) 2. Who does Xiaoming share his pocket money with in Week 3?
A. His little sister. B. His friend. C. His dad.
(
C
) 3. Why does Xiaoming save all his money in Week 4?
A. To buy a toy car.
B. To share it with his friend.
C. To buy a birthday gift for his dad.
(
C
) 4. In which week does Xiaoming save the most money?
A. Week 2. B. Week 3. C. Week 4.
5. How much pocket money does Xiaoming get in four weeks?
He gets 130 yuan.

答案

1. B 2. A 3. C 4. C 5. He gets 130 yuan.

解析

【分析】
这是一道英语阅读理解题,需根据短文内容逐一解答各小题。解题思路:先明确每个问题的核心,再定位问题对应的短文段落,提取关键信息,最后匹配选项或进行简单计算得出答案。
【解析】
1. 问题询问故事书的价格,定位Week1的内容:“He spends 10 yuan on a storybook”,可知故事书价格为10元,对应选项B。
2. 问题询问Week3分享零花钱的对象,定位Week3的内容:“shares five yuan with his little sister”,可知分享对象是小妹妹,对应选项A。
3. 问题询问Week4存所有钱的原因,定位Week4的内容:“because he wants to buy a birthday gift for his dad”,对应选项C。
4. 问题询问哪周存的钱最多:Week2存20元,Week3存10元,Week4存所有零花钱(每周基础30元,Week2额外加10元,Week4存全部即40元),因此Week4存的最多,对应选项C。
5. 计算四周总零花钱:每周基础30元,Week2额外加10元,总金额=30 + (30+10) +30 +30=130元。
【答案】
1. B 2. A 3. C 4. C 5. He gets 130 yuan.
【知识点】
英语阅读理解、细节提取、数字计算
【点评】
本题为基础英语阅读理解题,侧重考查学生从文本中提取关键信息和简单运算的能力,题目难度较低,适合基础阶段学生练习。
【难度系数】
0.8