$\frac{2}{7}+\frac{4}{7}-\frac{6}{7}=$
$\frac{3}{8}+\frac{1}{5}+\frac{5}{8}=$
$\frac{1}{4}+\frac{5}{12}+\frac{1}{3}=$
$\frac{5}{6}+\frac{1}{2}+\frac{2}{3}=$
$\frac{5}{9}+\frac{2}{3}-\frac{4}{9}=$
$\frac{17}{20}+\frac{1}{4}-\frac{7}{20}=$
$\frac{2}{3}-\frac{1}{6}+\frac{1}{3}=$
$1-\frac{1}{14}-\frac{2}{7}=$
$\frac{8}{15}-\frac{1}{5}-\frac{1}{3}=$
$\frac{8}{11}-\frac{2}{3}+\frac{3}{11}=$
$\frac{4}{13}+\frac{3}{8}-\frac{4}{13}=$
$\frac{4}{5}-\frac{3}{8}-\frac{1}{4}=$
$\frac{1}{2}+\frac{2}{5}+\frac{3}{10}=$
$\frac{7}{8}+\frac{5}{16}-\frac{7}{8}=$
$\frac{3}{4}-\frac{1}{3}-\frac{3}{8}=$
$\frac{2}{5}-\frac{2}{15}-\frac{2}{15}=$
$\frac{1}{3}+\frac{5}{9}-\frac{1}{9}=$
$\frac{4}{9}+\frac{5}{9}-\frac{1}{2}=$

$\frac{2}{7}+\frac{4}{7}-\frac{6}{7}=\frac{6}{7}-\frac{6}{7}=0$
$\frac{3}{8}+\frac{1}{5}+\frac{5}{8}=(\frac{3}{8}+\frac{5}{8})+\frac{1}{5}=1+\frac{1}{5}=1\frac{1}{5}$
$\frac{1}{4}+\frac{5}{12}+\frac{1}{3}=\frac{3}{12}+\frac{5}{12}+\frac{4}{12}=\frac{12}{12}=1$
$\frac{5}{6}+\frac{1}{2}+\frac{2}{3}=\frac{5}{6}+\frac{3}{6}+\frac{4}{6}=\frac{12}{6}=2$
$\frac{5}{9}+\frac{2}{3}-\frac{4}{9}=(\frac{5}{9}-\frac{4}{9})+\frac{6}{9}=\frac{1}{9}+\frac{6}{9}=\frac{7}{9}$
$\frac{17}{20}+\frac{1}{4}-\frac{7}{20}=(\frac{17}{20}-\frac{7}{20})+\frac{5}{20}=\frac{10}{20}+\frac{5}{20}=\frac{15}{20}=\frac{3}{4}$
$\frac{2}{3}-\frac{1}{6}+\frac{1}{3}=(\frac{2}{3}+\frac{1}{3})-\frac{1}{6}=1-\frac{1}{6}=\frac{5}{6}$
$1-\frac{1}{14}-\frac{2}{7}=\frac{14}{14}-\frac{1}{14}-\frac{4}{14}=\frac{9}{14}$
$\frac{8}{15}-\frac{1}{5}-\frac{1}{3}=\frac{8}{15}-\frac{3}{15}-\frac{5}{15}=0$
$\frac{8}{11}-\frac{2}{3}+\frac{3}{11}=(\frac{8}{11}+\frac{3}{11})-\frac{2}{3}=1-\frac{2}{3}=\frac{1}{3}$
$\frac{4}{13}+\frac{3}{8}-\frac{4}{13}=(\frac{4}{13}-\frac{4}{13})+\frac{3}{8}=0+\frac{3}{8}=\frac{3}{8}$
$\frac{4}{5}-\frac{3}{8}-\frac{1}{4}=\frac{32}{40}-\frac{15}{40}-\frac{10}{40}=\frac{7}{40}$
$\frac{1}{2}+\frac{2}{5}+\frac{3}{10}=\frac{5}{10}+\frac{4}{10}+\frac{3}{10}=\frac{12}{10}=\frac{6}{5}$
$\frac{7}{8}+\frac{5}{16}-\frac{7}{8}=(\frac{7}{8}-\frac{7}{8})+\frac{5}{16}=0+\frac{5}{16}=\frac{5}{16}$
$\frac{3}{4}-\frac{1}{3}-\frac{3}{8}=\frac{18}{24}-\frac{8}{24}-\frac{9}{24}=\frac{1}{24}$
$\frac{2}{5}-\frac{2}{15}-\frac{2}{15}=\frac{6}{15}-\frac{2}{15}-\frac{2}{15}=\frac{2}{15}$
$\frac{1}{3}+\frac{5}{9}-\frac{1}{9}=\frac{3}{9}+\frac{5}{9}-\frac{1}{9}=\frac{7}{9}$
$\frac{4}{9}+\frac{5}{9}-\frac{1}{2}=1-\frac{1}{2}=\frac{1}{2}$

在○里填上“＞”“＜”或“=”
$1-(\frac{1}{6}+\frac{1}{3})$○$\frac{1}{2}$
$\frac{5}{6}-(\frac{1}{24}+\frac{12}{12})$○$\frac{1}{2}$
$\frac{17}{36}-(\frac{17}{36}-\frac{1}{9})$○$\frac{1}{2}$
$\frac{1}{2}-(\frac{3}{4}-\frac{3}{8})$○$\frac{1}{2}$
$\frac{1}{2}+(\frac{1}{4}-\frac{1}{6})$○$\frac{1}{2}$
$1-(\frac{11}{20}+\frac{1}{4})$○$\frac{1}{2}$
$\frac{1}{2}-(\frac{1}{2}-\frac{1}{3})$○$\frac{1}{2}$
$\frac{7}{8}-(\frac{5}{12}+\frac{1}{6})$○$\frac{1}{2}$

1. $1-(\frac{1}{6}+\frac{1}{3})=1-(\frac{1}{6}+\frac{2}{6})=1-\frac{3}{6}=\frac{1}{2}$，$\frac{1}{2}=\frac{1}{2}$，故填“=”。
2. $\frac{5}{6}-(\frac{1}{24}+\frac{12}{12})=\frac{5}{6}-(1+\frac{1}{24})=\frac{20}{24}-\frac{25}{24}=-\frac{5}{24}$，$-\frac{5}{24}＜\frac{1}{2}$，故填“＜”。
3. $\frac{17}{36}-(\frac{17}{36}-\frac{1}{9})=\frac{17}{36}-\frac{17}{36}+\frac{1}{9}=\frac{1}{9}$，$\frac{1}{9}＜\frac{1}{2}$，故填“＜”。
4. $\frac{1}{2}-(\frac{3}{4}-\frac{3}{8})=\frac{1}{2}-(\frac{6}{8}-\frac{3}{8})=\frac{4}{8}-\frac{3}{8}=\frac{1}{8}$，$\frac{1}{8}＜\frac{1}{2}$，故填“＜”。
5. $\frac{1}{2}+(\frac{1}{4}-\frac{1}{6})=\frac{1}{2}+(\frac{3}{12}-\frac{2}{12})=\frac{6}{12}+\frac{1}{12}=\frac{7}{12}$，$\frac{7}{12}＞\frac{1}{2}$，故填“＞”。
6. $1-(\frac{11}{20}+\frac{1}{4})=1-(\frac{11}{20}+\frac{5}{20})=1-\frac{16}{20}=\frac{4}{20}=\frac{1}{5}$，$\frac{1}{5}＜\frac{1}{2}$，故填“＜”。
7. $\frac{1}{2}-(\frac{1}{2}-\frac{1}{3})=\frac{1}{2}-\frac{1}{2}+\frac{1}{3}=\frac{1}{3}$，$\frac{1}{3}＜\frac{1}{2}$，故填“＜”。
8. $\frac{7}{8}-(\frac{5}{12}+\frac{1}{6})=\frac{7}{8}-(\frac{5}{12}+\frac{2}{12})=\frac{21}{24}-\frac{14}{24}=\frac{7}{24}$，$\frac{7}{24}＜\frac{1}{2}$，故填“＜”。