20. 工程队修一条公路,已经修了$\frac{5}{9}\ \mathrm{km}$,还剩下全长的$\frac{5}{9}$。已经修的长度和剩下的长度相比,(
A.已经修的长
B.剩下的长
C.一样长
D.无法判断
B
)。A.已经修的长
B.剩下的长
C.一样长
D.无法判断
答案
20. B
三、计算题。(共32分)
21. 直接写出得数。(每题0.5分,共5分)
$\frac{1}{5}+\frac{1}{7}=$
$\frac{7}{9}+\frac{1}{9}=$
$\frac{2}{5}+0.4=$
$\frac{3}{4}-\frac{4}{7}=$
$\frac{1}{3}+\frac{6}{11}+\frac{2}{3}=$
$15÷17=$
$0.95-\frac{3}{5}=$
$\frac{1}{3}-\frac{1}{8}=$
$\frac{9}{10}-(\quad)=\frac{1}{4}$
$1-\frac{11}{23}-\frac{12}{23}=$
21. 直接写出得数。(每题0.5分,共5分)
$\frac{1}{5}+\frac{1}{7}=$
$\frac{7}{9}+\frac{1}{9}=$
$\frac{2}{5}+0.4=$
$\frac{3}{4}-\frac{4}{7}=$
$\frac{1}{3}+\frac{6}{11}+\frac{2}{3}=$
$15÷17=$
$0.95-\frac{3}{5}=$
$\frac{1}{3}-\frac{1}{8}=$
$\frac{9}{10}-(\quad)=\frac{1}{4}$
$1-\frac{11}{23}-\frac{12}{23}=$
答案
21. $\dfrac{12}{35}$;$\dfrac{8}{9}$;$\dfrac{4}{5}$;$\dfrac{5}{28}$;$1\dfrac{6}{11}$;$\dfrac{15}{17}$;$0.35$;$\dfrac{5}{24}$;$0.65$;$0$
22. 选择合理的方法计算。(每题3分,共18分)
(1)$6.3 - \frac{8}{19} + 3.7 - 2\frac{11}{19}$
(2)$\frac{17}{30} - (\frac{2}{5} + \frac{1}{6})$
(3)$0.75 + \frac{7}{20} - \frac{4}{5}$
(4)$\frac{8}{15} + \frac{3}{10} - \frac{5}{6}$
(5)$3 ÷ 7 + \frac{5}{9} + \frac{4}{7}$
(6)$13 - \frac{3}{8} - \frac{5}{8}$
(1)$6.3 - \frac{8}{19} + 3.7 - 2\frac{11}{19}$
(2)$\frac{17}{30} - (\frac{2}{5} + \frac{1}{6})$
(3)$0.75 + \frac{7}{20} - \frac{4}{5}$
(4)$\frac{8}{15} + \frac{3}{10} - \frac{5}{6}$
(5)$3 ÷ 7 + \frac{5}{9} + \frac{4}{7}$
(6)$13 - \frac{3}{8} - \frac{5}{8}$
答案
22.
(1)$=(6.3+3.7)-(\dfrac{8}{19}+2\dfrac{11}{19})$
$=10-3$
$=7$
(2)$=\dfrac{17}{30}-\dfrac{17}{30}$
$=0$
(3)$=0.75+0.35-0.8$
$=1.1-0.8$
$=0.3$
(4)$=\dfrac{16}{30}+\dfrac{9}{30}-\dfrac{25}{30}$
$=0$
(5)$=\dfrac{3}{7}+\dfrac{5}{9}+\dfrac{4}{7}$
$=\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{9}$
$=1+\dfrac{5}{9}$
$=1\dfrac{5}{9}$
(6)$=13-(\dfrac{3}{8}+\dfrac{5}{8})$
$=13-1$
$=12$
(1)$=(6.3+3.7)-(\dfrac{8}{19}+2\dfrac{11}{19})$
$=10-3$
$=7$
(2)$=\dfrac{17}{30}-\dfrac{17}{30}$
$=0$
(3)$=0.75+0.35-0.8$
$=1.1-0.8$
$=0.3$
(4)$=\dfrac{16}{30}+\dfrac{9}{30}-\dfrac{25}{30}$
$=0$
(5)$=\dfrac{3}{7}+\dfrac{5}{9}+\dfrac{4}{7}$
$=\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{9}$
$=1+\dfrac{5}{9}$
$=1\dfrac{5}{9}$
(6)$=13-(\dfrac{3}{8}+\dfrac{5}{8})$
$=13-1$
$=12$
23. 解方程。(每题3分,共9分)
(1)$x-\frac{2}{7}=\frac{3}{4}$
(2)$\frac{3}{5}+x=\frac{7}{8}-\frac{1}{4}$
(3)$6x+\frac{1}{4}=\frac{25}{4}$
(1)$x-\frac{2}{7}=\frac{3}{4}$
(2)$\frac{3}{5}+x=\frac{7}{8}-\frac{1}{4}$
(3)$6x+\frac{1}{4}=\frac{25}{4}$
答案
23.
(1)$x=\dfrac{29}{28}$
(2)$x=\dfrac{1}{40}$
(3)$x=1$
(1)$x=\dfrac{29}{28}$
(2)$x=\dfrac{1}{40}$
(3)$x=1$
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