2026年通城学典初中数学运算能手八年级数学上册北师大版第40页答案
一、填空题
1. $\sqrt{15} ÷ \sqrt{30} × \sqrt{1\dfrac{1}{3}} =$
$\dfrac{\sqrt{6}}{3}$

2. $5 ÷ \sqrt{5} × \dfrac{1}{\sqrt{5}} =$
$1$

3. $\sqrt{27} × \sqrt{50} ÷ 2\sqrt{6} =$
$\dfrac{15}{2}$

4. $3\sqrt{2} × \dfrac{1}{2}\sqrt{6} ÷ \sqrt{8} =$
$\dfrac{3\sqrt{6}}{4}$

5. $\sqrt{1\dfrac{1}{4}} ÷ \sqrt{2\dfrac{1}{2}} × (-2\sqrt{8}) =$
$-4$

6. $\dfrac{3}{2}\sqrt{20} × (-\sqrt{15}) × (-\dfrac{1}{3}\sqrt{27}) =$
$45$

答案

1. $\dfrac{\sqrt{6}}{3}$
2. $1$
3. $\dfrac{15}{2}$
4. $\dfrac{3\sqrt{6}}{4}$
5. $-4$
6. $45$
二、计算题
7. $\sqrt{5} × \sqrt{2} ÷ 3\sqrt{5} × \frac{\sqrt{2}}{2}$
8. $2\sqrt{20} × \frac{1}{4}\sqrt{5} ÷ 4\sqrt{5}$
9. $\sqrt{8} × 4\sqrt{\frac{1}{2}} ÷ (\sqrt{5})^2$
10. $\sqrt{5} ÷ \sqrt{2} × 2\sqrt{2} ÷ 2\sqrt{5}$
11. $3\sqrt{3\frac{1}{2}} × (-\frac{1}{8}\sqrt{1\frac{4}{7}}) ÷ (\frac{1}{2}\sqrt{5\frac{1}{2}})$
12. $9\sqrt{5} × \frac{3}{2}\sqrt{\frac{2}{3}} ÷ \sqrt{\frac{1}{5}}$
13. $\sqrt{3\frac{1}{3}} ÷ \frac{2}{5}\sqrt{2\frac{1}{3}} × 4\sqrt{1\frac{2}{5}}$
14. $(-\sqrt{1\frac{2}{3}}) ÷ \sqrt{2\frac{1}{3}} × (-\sqrt{1\frac{2}{5}})$

答案

7. $\dfrac{1}{3}$
8. $\dfrac{\sqrt{5}}{4}$
9. $\dfrac{8}{5}$
10. $1$
11. $-\dfrac{3}{4}$
12. $\dfrac{45\sqrt{6}}{2}$
13. $10\sqrt{2}$
14. $1$