2026年一本暑假计算加应用题五年级数学北师大版第42页答案
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答案

$\frac{24}{25}×13$
$=(1-\frac{1}{25})×13$
$=13-\frac{13}{25}$
$=12\frac{12}{25}$
$\frac{43}{41}×14$
$=(1+\frac{2}{41})×14$
$=14+\frac{28}{41}$
$=14\frac{28}{41}$
$\frac{33}{34}×15$
$=(1-\frac{1}{34})×15$
$=15-\frac{15}{34}$
$=14\frac{19}{34}$
$52×\frac{37}{50}$
$=(50+2)×\frac{37}{50}$
$=50×\frac{37}{50}+2×\frac{37}{50}$
$=37+\frac{37}{25}$
$=38\frac{12}{25}$
$1001×\frac{101}{1002}$
$=(1002-1)×\frac{101}{1002}$
$=1002×\frac{101}{1002}-1×\frac{101}{1002}$
$=101-\frac{101}{1002}$
$=100\frac{901}{1002}$
$199×\frac{89}{99}$
$=(198+1)×\frac{89}{99}$
$=198×\frac{89}{99}+1×\frac{89}{99}$
$=178+\frac{89}{99}$
$=178\frac{89}{99}$
$21\frac{3}{7}×\frac{1}{5}$
$=(20+\frac{10}{7})×\frac{1}{5}$
$=20×\frac{1}{5}+\frac{10}{7}×\frac{1}{5}$
$=4+\frac{2}{7}$
$=4\frac{2}{7}$
$29\frac{1}{5}×\frac{5}{6}$
$=(30-\frac{4}{5})×\frac{5}{6}$
$=30×\frac{5}{6}-\frac{4}{5}×\frac{5}{6}$
$=25-\frac{2}{3}$
$=24\frac{1}{3}$
$34\frac{2}{9}×\frac{9}{11}$
$=(33+\frac{11}{9})×\frac{9}{11}$
$=33×\frac{9}{11}+\frac{11}{9}×\frac{9}{11}$
$=27+1$
$=28$
$72\frac{4}{17}×\frac{17}{24}$
$=(72+\frac{4}{17})×\frac{17}{24}$
$=72×\frac{17}{24}+\frac{4}{17}×\frac{17}{24}$
$=51+\frac{1}{6}$
$=51\frac{1}{6}$
$73\frac{1}{15}×\frac{1}{8}$
$=(72+\frac{16}{15})×\frac{1}{8}$
$=72×\frac{1}{8}+\frac{16}{15}×\frac{1}{8}$
$=9+\frac{2}{15}$
$=9\frac{2}{15}$
$16\frac{6}{13}×\frac{13}{32}$
$=(16+\frac{6}{13})×\frac{13}{32}$
$=16×\frac{13}{32}+\frac{6}{13}×\frac{13}{32}$
$=\frac{13}{2}+\frac{3}{16}$
$=6\frac{11}{16}$