2026年初中运算计算升级卡八年级上册人教版第97页答案
1. 计算:
(1) $\frac{x^2}{(x-2)^2} · \frac{x-2}{x}$;
(2) $\frac{3a^2}{b^4} · \frac{b^3}{6a}$;
(3) $\frac{x-y}{y} · \frac{y}{x(x-y)}$;
(4) $\frac{3xy}{-7m} · \frac{28mn}{9xy^2}$;
(5) $(a-2) · \frac{a^2-4}{a^2-4a+4}$;
(6) $(ab - b^2) ÷ \frac{a - b}{ab}$;
(7) $\frac{y}{6x^2} ÷ \frac{y^2}{4x}$;
(8) $\frac{a-1}{2a+4} ÷ \frac{a^2 -1}{a^2 -4}$;
(9) $\frac{2a+2b}{3ab} ÷ \frac{a^2 -b^2}{9a^2b}$;
(10) $\frac{a-1}{a} ÷ \frac{a-1}{a^2}$;
(11) $\frac{x^2 -5x +6}{x^2 +3x +2} ÷ \frac{x-2}{x+1}$;
(12) $\frac{9x^2y^2}{4a^3} ÷ \frac{3xy^2}{2ab}$;
(13) $\frac{x^2 -2x +1}{x^2 -1} ÷ \frac{x-1}{x^2 +x}$;
(14) $\frac{25 -x^2}{x^2 +6x +9} ÷ \frac{x-5}{2x+6} · \frac{x+3}{x+5}$;
(15) $\frac{a^2 -4}{a^2 +2a -8} ÷ (a^2 -4) · \frac{a^2 -4a +4}{a-2}$;
(16) $( \frac{b}{a} )^3 · \frac{a}{b} ÷ ( \frac{b}{a} )^2$;

答案

(1) $\frac{x}{x-2}$
(2) $\frac{a}{2b}$
(3) $\frac{1}{x}$
(4) $-\frac{4n}{3y}$
(5) $a+2$
(6) $ab^2$
(7) $\frac{2}{3xy}$
(8) $\frac{a-2}{2a+2}$
(9) $\frac{6a}{a-b}$
(10) $a$
(11) $\frac{x-3}{x+2}$
(12) $\frac{3bx}{2a^2}$
(13) $x$
(14) $-2$
(15) $\frac{1}{a+4}$
(16) $1$