2026年一本暑假计算加应用题五年级数学北师大版第6页答案
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答案

$\frac{1}{3}+\frac{2}{3}=1$
$\frac{3}{4}-\frac{1}{2}=\frac{1}{4}$
$1-\frac{9}{11}=\frac{2}{11}$
$\frac{1}{3}+\frac{1}{4}=\frac{7}{12}$
$\frac{9}{5}-1=\frac{4}{5}$
$\frac{5}{6}-\frac{1}{3}=\frac{1}{2}$
$\frac{1}{7}-\frac{1}{8}=\frac{1}{56}$
$\frac{1}{5}+\frac{1}{3}=\frac{8}{15}$
$\frac{7}{9}+\frac{2}{9}=1$
$4-\frac{3}{4}=3\frac{1}{4}$
$\frac{3}{4}-0.25=\frac{1}{2}$
$\frac{7}{13}-\frac{3}{13}=\frac{4}{13}$
$\frac{5}{6}-\frac{1}{6}=\frac{2}{3}$
$2-\frac{1}{7}=1\frac{6}{7}$
$0.6+\frac{1}{4}=\frac{17}{20}$
$\frac{2}{3}-0.5=\frac{1}{6}$
$\frac{8}{7}-1=\frac{1}{7}$
$1.4+\frac{3}{5}=2$
$\frac{4}{7}-\frac{1}{3}=\frac{5}{21}$
$3-2\frac{1}{6}=\frac{5}{6}$
2.计算下面各题,能简算的要简算。(每题3★)
$\frac{19}{13} - (\frac{6}{13} + \frac{3}{8})$
$5.22 + \frac{4}{9} + 7.78 + \frac{5}{9}$
$\frac{11}{8} + \frac{2}{3} - \frac{5}{6}$
$\frac{2}{7} + (\frac{3}{4} + \frac{5}{7})$
$0.75 + \frac{10}{17} + \frac{1}{4}$
$8.26 + \frac{15}{11} - \frac{4}{11}$

答案

2.$\frac{5}{8}$ 14 $\frac{29}{24}$ $1\frac{3}{4}$ $1\frac{10}{17}$ 9.26
3.解方程。(每题3★)
$\frac{5}{8}+x=\frac{3}{4}$
$x-\frac{4}{5}=1.2$
$0.6+x=\frac{12}{5}$

答案

3.$x=\frac{1}{8}$ $x=2$ $x=1.8$