登录
一、填空题
1. $(-3)-(-2)×(-3)=$
2. $(-3)+(-2^4)=$
3. $(-3)^2×2÷(-6)=$
4. $-3×2^2÷(-4)=$
5. $(-2)^3+3^2×(-1)=$
6. $(-9^2)÷(-9)^2×(-2)=$
7. $[(-2)^3-2^3]÷(-2)=$
8. $(-3^2)×(-\dfrac{1}{3})÷(-9)=$
1. $(-3)-(-2)×(-3)=$
-9
2. $(-3)+(-2^4)=$
-19
3. $(-3)^2×2÷(-6)=$
-3
4. $-3×2^2÷(-4)=$
3
5. $(-2)^3+3^2×(-1)=$
-17
6. $(-9^2)÷(-9)^2×(-2)=$
2
7. $[(-2)^3-2^3]÷(-2)=$
8
8. $(-3^2)×(-\dfrac{1}{3})÷(-9)=$
$-\dfrac{1}{3}$
答案
1. -9
2. -19
3. -3
4. 3
5. -17
6. 2
7. 8
8. $-\dfrac{1}{3}$
2. -19
3. -3
4. 3
5. -17
6. 2
7. 8
8. $-\dfrac{1}{3}$
二、计算题
9. $-1^3 - (-1)^3 × 3$
10. [山西中考] $\left| -\dfrac{1}{2} \right| × 6 - 3^2 + (-8 + 4)$
11. $4^2 ÷ ( -\dfrac{1}{4} ) + 5^4 ÷ (-5)^3$
12. $(-8) - (-6) × [7 - (-4)^2] ÷ (-2)$
13. $(-1)^5 - (1 - 1\dfrac{7}{8} + 1\dfrac{1}{12}) ÷ (-\dfrac{1}{24})$
14. $-1^4 × \dfrac{3}{2} × (-\dfrac{2}{3}) + [ (-3)^2 - (1 - 2^3) × 2 ]$
15. $-2^3 ÷ (-2)^5 + 2.5 × (-4) - ( -\dfrac{2}{3} )^2 × \dfrac{9}{4}$
16. $1\dfrac{1}{24} - 24 × ( \dfrac{3}{8} + \dfrac{1}{6} - \dfrac{3}{4} ) - \dfrac{8}{5} ÷ ( \dfrac{8}{5} - \dfrac{8}{15} )$
9. $-1^3 - (-1)^3 × 3$
10. [山西中考] $\left| -\dfrac{1}{2} \right| × 6 - 3^2 + (-8 + 4)$
11. $4^2 ÷ ( -\dfrac{1}{4} ) + 5^4 ÷ (-5)^3$
12. $(-8) - (-6) × [7 - (-4)^2] ÷ (-2)$
13. $(-1)^5 - (1 - 1\dfrac{7}{8} + 1\dfrac{1}{12}) ÷ (-\dfrac{1}{24})$
14. $-1^4 × \dfrac{3}{2} × (-\dfrac{2}{3}) + [ (-3)^2 - (1 - 2^3) × 2 ]$
15. $-2^3 ÷ (-2)^5 + 2.5 × (-4) - ( -\dfrac{2}{3} )^2 × \dfrac{9}{4}$
16. $1\dfrac{1}{24} - 24 × ( \dfrac{3}{8} + \dfrac{1}{6} - \dfrac{3}{4} ) - \dfrac{8}{5} ÷ ( \dfrac{8}{5} - \dfrac{8}{15} )$
答案
9. 2
10. -10
11. -69
12. 19
13. 4
14. 24
15. $-10\dfrac{3}{4}$
16. $4\dfrac{13}{24}$
10. -10
11. -69
12. 19
13. 4
14. 24
15. $-10\dfrac{3}{4}$
16. $4\dfrac{13}{24}$
