6. 计算.
(1)$(4-\sqrt{3})^2 + \frac{\sqrt{24}-\sqrt{6}}{\sqrt{6}}$
(2)$(-\frac{1}{2})^{-2} - |\sqrt{3}-2| + \sqrt{\frac{3}{2}} ÷ \sqrt{\frac{1}{18}}$
(3)$|2-\sqrt{3}| + (-4) × \frac{1}{2} - \sqrt[3]{-\frac{1}{27}}$
(4)$\sqrt[3]{8} + \frac{1}{\sqrt{5}} - (\frac{1}{3})^{-2} + |\sqrt{5}-3|$
(3)$2\sqrt{12} × \frac{\sqrt{3}}{4} ÷ 3\sqrt{2} - (\sqrt{8} - 3\sqrt{\frac{1}{2}})$

解：
(1)
$\begin{aligned}原式&=4^2 - 2×4×\sqrt{3} + (\sqrt{3})^2 + \frac{\sqrt{24}}{\sqrt{6}} - \frac{\sqrt{6}}{\sqrt{6}}\\&=16 - 8\sqrt{3} + 3 + \sqrt{4} - 1\\&=19 - 8\sqrt{3} + 2 - 1\\&=20 - 8\sqrt{3}\end{aligned}$
(2)
$\begin{aligned}原式&=\frac{1}{(-\frac{1}{2})^2} - (2 - \sqrt{3}) + \sqrt{\frac{3}{2} ÷ \frac{1}{18}}\\&=4 - 2 + \sqrt{3} + \sqrt{27}\\&=2 + \sqrt{3} + 3\sqrt{3}\\&=2 + 4\sqrt{3}\end{aligned}$
(3)
$\begin{aligned}原式&=2 - \sqrt{3} + (-2) - (-\frac{1}{3})\\&=2 - \sqrt{3} - 2 + \frac{1}{3}\\&=\frac{1}{3} - \sqrt{3}\end{aligned}$
(4)
$\begin{aligned}原式&=2 + \frac{\sqrt{5}}{5} - \frac{1}{(\frac{1}{3})^2} + 3 - \sqrt{5}\\&=2 + \frac{\sqrt{5}}{5} - 9 + 3 - \sqrt{5}\\&=-4 - \frac{4\sqrt{5}}{5}\end{aligned}$
(5)
$\begin{aligned}原式&=(2×\frac{1}{4}÷3)×\sqrt{12×3÷2} - (2\sqrt{2} - \frac{3\sqrt{2}}{2})\\&=\frac{1}{6}×\sqrt{18} - \frac{\sqrt{2}}{2}\\&=\frac{1}{6}×3\sqrt{2} - \frac{\sqrt{2}}{2}\\&=\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2}\\&=0\end{aligned}$

5. 计算.
(1)$\sqrt{3} × ( \sqrt{3} + \frac{1}{\sqrt{3}} ) - \sqrt[3]{-1} + (\sqrt{3})^2$
(2)$(\sqrt{3} + 1) × (\sqrt{3} - 1) - (\sqrt{3} - 2)^2 + \sqrt{12}$
(4)$\sqrt{(\sqrt{5} - 3)^2} - (\sqrt{5} + 1) × (\sqrt{5} - 1) + \frac{4}{\sqrt{5} - 1}$

(1) 8
(2) $6\sqrt{3}-5$
(4) $-\sqrt{2}$