1. 口算。(建议用时3分钟)
$\frac{2}{13}×6=$
$\frac{1}{4}×8=$
$4×\frac{5}{16}=$
$\frac{1}{20}×10=$
$\frac{3}{10}×5=$
$3×\frac{4}{5}=$
$4×\frac{1}{7}=$
$9×\frac{2}{27}=$
$\frac{5}{12}×6=$
$\frac{7}{10}×2=$
$\frac{2}{3}×7=$
$8×\frac{3}{40}=$
$15×\frac{3}{5}=$
$\frac{8}{15}×3=$
$24×\frac{5}{8}=$
$\frac{3}{7}×21=$
$16×\frac{3}{8}=$
$\frac{7}{9}×27=$
$\frac{5}{6}×24=$
$\frac{11}{13}×39=$
$\frac{2}{13}×6=$
$\frac{1}{4}×8=$
$4×\frac{5}{16}=$
$\frac{1}{20}×10=$
$\frac{3}{10}×5=$
$3×\frac{4}{5}=$
$4×\frac{1}{7}=$
$9×\frac{2}{27}=$
$\frac{5}{12}×6=$
$\frac{7}{10}×2=$
$\frac{2}{3}×7=$
$8×\frac{3}{40}=$
$15×\frac{3}{5}=$
$\frac{8}{15}×3=$
$24×\frac{5}{8}=$
$\frac{3}{7}×21=$
$16×\frac{3}{8}=$
$\frac{7}{9}×27=$
$\frac{5}{6}×24=$
$\frac{11}{13}×39=$
答案
1. $\frac{12}{13}$
$2$
$\frac{5}{4}$
$\frac{1}{2}$
$\frac{3}{2}$
$\frac{12}{5}$
$\frac{4}{7}$
$\frac{2}{3}$
$\frac{5}{2}$
$\frac{7}{5}$
$\frac{14}{3}$
$\frac{3}{5}$
$9$
$\frac{8}{5}$
$15$
$9$
$6$
$21$
$20$
$33$
$2$
$\frac{5}{4}$
$\frac{1}{2}$
$\frac{3}{2}$
$\frac{12}{5}$
$\frac{4}{7}$
$\frac{2}{3}$
$\frac{5}{2}$
$\frac{7}{5}$
$\frac{14}{3}$
$\frac{3}{5}$
$9$
$\frac{8}{5}$
$15$
$9$
$6$
$21$
$20$
$33$
2. 下面的计算对吗?对的画“√”,错的画“×”并改正。(建议用时2分钟)
$\frac{7}{12}×8=\frac{7}{\cancel{12}}_{\displaystyle 3}×\frac{2}{\cancel{8}}=\frac{7}{6}$(
$\frac{9}{10}×6=\frac{\overset{3}{\cancel{9}}}{10}×\frac{\overset{2}{\cancel{6}}}{}=\frac{6}{10}=\frac{3}{5}$(
$\frac{7}{12}×8=\frac{7}{\cancel{12}}_{\displaystyle 3}×\frac{2}{\cancel{8}}=\frac{7}{6}$(
×
)$\frac{9}{10}×6=\frac{\overset{3}{\cancel{9}}}{10}×\frac{\overset{2}{\cancel{6}}}{}=\frac{6}{10}=\frac{3}{5}$(
×
)答案
2. × $\frac{14}{3}$ × $\frac{27}{5}$
3. 计算下面各题。(建议用时2分钟)
$\frac{2}{45}×18$
$\frac{49}{110}×55$
$\frac{7}{50}×125$
$\frac{2}{45}×18$
$\frac{49}{110}×55$
$\frac{7}{50}×125$
答案
3. $\frac{4}{5}$ $\frac{49}{2}$ $\frac{35}{2}$
4. 解决问题。(建议用时3分钟)
为了保证身体健康,一般人每天食用油摄入量应为$\frac{1}{40}$ kg 至$\frac{3}{100}$ kg。按此标准,一人一年(按365天计算)最多摄入多少千克食用油?
为了保证身体健康,一般人每天食用油摄入量应为$\frac{1}{40}$ kg 至$\frac{3}{100}$ kg。按此标准,一人一年(按365天计算)最多摄入多少千克食用油?
答案
4. $\frac{3}{100}×365=\frac{219}{20}$(kg)
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