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1. 填空:
(1)$(-3)^{2}=$
(2)$(-\dfrac{1}{2})^{3}=$
(3)$-2^{5}=$
(4)$(-1)^{99}=$
(5)$-(\dfrac{3}{4})^{2}=$
(6)$-(-\dfrac{2}{3})^{3}=$
(1)$(-3)^{2}=$
9
;(2)$(-\dfrac{1}{2})^{3}=$
$-\dfrac{1}{8}$
;(3)$-2^{5}=$
$-32$
;(4)$(-1)^{99}=$
$-1$
;(5)$-(\dfrac{3}{4})^{2}=$
$-\dfrac{9}{16}$
;(6)$-(-\dfrac{2}{3})^{3}=$
$\dfrac{8}{27}$
.答案
(1)9 (2)$-\dfrac{1}{8}$ (3)$-32$ (4)$-1$ (5)$-\dfrac{9}{16}$ (6)$\dfrac{8}{27}$
2. 计算:
(1) $-\dfrac{2^6}{6}$;
(2) $\left|-\dfrac{1}{3}\right|^3$;
(3) $-2^3 + (-3)^2$;
(4) $-(-3)^2 × (-2)^3$;
(5) $-\dfrac{2}{3} ÷ (-\dfrac{1}{3})^2$;
(6) $(-\dfrac{2}{5})^2 × (-\dfrac{5^2}{4})$.
(1) $-\dfrac{2^6}{6}$;
(2) $\left|-\dfrac{1}{3}\right|^3$;
(3) $-2^3 + (-3)^2$;
(4) $-(-3)^2 × (-2)^3$;
(5) $-\dfrac{2}{3} ÷ (-\dfrac{1}{3})^2$;
(6) $(-\dfrac{2}{5})^2 × (-\dfrac{5^2}{4})$.
答案
(1)$-\dfrac{32}{3}$
(2)$\dfrac{1}{27}$
【错因分析】注意本题先算绝对值再乘方,另外分清
$\left|-\dfrac{1}{3}\right|^{3}$和$(-\dfrac{1}{3})^{3}$.
(3)1 (4)72 (5)-6 (6)-1
(2)$\dfrac{1}{27}$
【错因分析】注意本题先算绝对值再乘方,另外分清
$\left|-\dfrac{1}{3}\right|^{3}$和$(-\dfrac{1}{3})^{3}$.
(3)1 (4)72 (5)-6 (6)-1
3. 计算:
(1) $(-3)^4 - (-3)^3 + (-5)^3$;
(2) $-1^{98} + (-1)^{100} + (-1)^{99}$;
(3) $|-5|^2 × [ - ( \frac{2}{5} )^2 ] ÷ (-2)^4$;
(4) $( \frac{1}{2} )^2 × ( \frac{2}{3} )^3 × ( \frac{3}{4} )^4$.
(1) $(-3)^4 - (-3)^3 + (-5)^3$;
(2) $-1^{98} + (-1)^{100} + (-1)^{99}$;
(3) $|-5|^2 × [ - ( \frac{2}{5} )^2 ] ÷ (-2)^4$;
(4) $( \frac{1}{2} )^2 × ( \frac{2}{3} )^3 × ( \frac{3}{4} )^4$.
答案
(1)-17 (2)-1 (3)$-\dfrac{1}{4}$ (4)$\dfrac{3}{128}$
