2026年暑假计算二十一世纪出版社集团二升三数学第70页答案
1.算一算。
$1-\frac{1}{2}=$
$1-\frac{2}{3}=$
$1-\frac{5}{8}=$
$1-\frac{4}{7}=$
$1-\frac{1}{6}=$
$1-\frac{2}{5}=$
$1-\frac{2}{9}=$
$1-\frac{1}{7}=$
$1-\frac{2}{8}=$
$1-\frac{1}{4}=$
$\frac{7}{8}-\frac{2}{8}=$
$\frac{6}{8}-\frac{3}{8}=$
$\frac{6}{7}-\frac{4}{7}=$
$\frac{3}{7}-\frac{1}{7}=$
$\frac{4}{10}+\frac{5}{10}=$
$\frac{5}{9}-\frac{3}{9}=$
$\frac{3}{9}+\frac{3}{9}=$
$\frac{5}{7}-\frac{2}{7}=$
$\frac{1}{7}+\frac{5}{7}=$
$\frac{4}{10}+\frac{3}{10}=$
$\frac{4}{8}+\frac{3}{8}=$
$\frac{9}{10}-\frac{2}{10}=$
$\frac{7}{9}-\frac{5}{9}=$
$\frac{7}{10}-\frac{5}{10}=$
$\frac{8}{9}-\frac{1}{9}=$
$\frac{3}{6}+\frac{2}{6}=$
$\frac{7}{9}-\frac{6}{9}=$
$\frac{1}{6}+\frac{2}{6}=$
$\frac{2}{9}+\frac{2}{9}=$
$\frac{2}{4}+\frac{1}{4}=$
$\frac{4}{13}-\frac{3}{13}=$
$\frac{5}{13}+\frac{4}{13}=$
$\frac{10}{16}-\frac{7}{16}=$
$\frac{13}{14}-\frac{7}{14}=$
$\frac{12}{15}+\frac{2}{15}=$
$\frac{17}{18}-\frac{5}{18}=$
$\frac{6}{18}+\frac{4}{18}=$
$\frac{7}{12}+\frac{4}{12}=$
$\frac{11}{14}-\frac{8}{14}=$
$\frac{11}{19}+\frac{5}{19}=$

答案

$1-\frac{1}{2}=\frac{1}{2}$
$1-\frac{2}{3}=\frac{1}{3}$
$1-\frac{5}{8}=\frac{3}{8}$
$1-\frac{4}{7}=\frac{3}{7}$
$1-\frac{1}{6}=\frac{5}{6}$
$1-\frac{2}{5}=\frac{3}{5}$
$1-\frac{2}{9}=\frac{7}{9}$
$1-\frac{1}{7}=\frac{6}{7}$
$1-\frac{2}{8}=\frac{6}{8}$
$1-\frac{1}{4}=\frac{3}{4}$
$\frac{7}{8}-\frac{2}{8}=\frac{5}{8}$
$\frac{6}{8}-\frac{3}{8}=\frac{3}{8}$
$\frac{6}{7}-\frac{4}{7}=\frac{2}{7}$
$\frac{3}{7}-\frac{1}{7}=\frac{2}{7}$
$\frac{4}{10}+\frac{5}{10}=\frac{9}{10}$
$\frac{5}{9}-\frac{3}{9}=\frac{2}{9}$
$\frac{3}{9}+\frac{3}{9}=\frac{6}{9}$
$\frac{5}{7}-\frac{2}{7}=\frac{3}{7}$
$\frac{1}{7}+\frac{5}{7}=\frac{6}{7}$
$\frac{4}{10}+\frac{3}{10}=\frac{7}{10}$
$\frac{4}{8}+\frac{3}{8}=\frac{7}{8}$
$\frac{9}{10}-\frac{2}{10}=\frac{7}{10}$
$\frac{7}{9}-\frac{5}{9}=\frac{2}{9}$
$\frac{7}{10}-\frac{5}{10}=\frac{2}{10}$
$\frac{8}{9}-\frac{1}{9}=\frac{7}{9}$
$\frac{3}{6}+\frac{2}{6}=\frac{5}{6}$
$\frac{7}{9}-\frac{6}{9}=\frac{1}{9}$
$\frac{1}{6}+\frac{2}{6}=\frac{3}{6}$
$\frac{2}{9}+\frac{2}{9}=\frac{4}{9}$
$\frac{2}{4}+\frac{1}{4}=\frac{3}{4}$
$\frac{4}{13}-\frac{3}{13}=\frac{1}{13}$
$\frac{5}{13}+\frac{4}{13}=\frac{9}{13}$
$\frac{10}{16}-\frac{7}{16}=\frac{3}{16}$
$\frac{13}{14}-\frac{7}{14}=\frac{6}{14}$
$\frac{12}{15}+\frac{2}{15}=\frac{14}{15}$
$\frac{17}{18}-\frac{5}{18}=\frac{12}{18}$
$\frac{6}{18}+\frac{4}{18}=\frac{10}{18}$
$\frac{7}{12}+\frac{4}{12}=\frac{11}{12}$
$\frac{11}{14}-\frac{8}{14}=\frac{3}{14}$
$\frac{11}{19}+\frac{5}{19}=\frac{16}{19}$
2.算一算,比一比。
$\frac{3}{11} - \frac{1}{11} ◯ \frac{4}{11} - \frac{3}{11}$ $\frac{8}{9} - \frac{6}{9} ◯ \frac{3}{10} - \frac{1}{10}$ $\frac{8}{20} - \frac{6}{20} ◯ \frac{12}{20} - \frac{9}{20}$
$\frac{4}{11} + \frac{6}{11} ◯ \frac{6}{13} + \frac{4}{13}$ $\frac{8}{23} - \frac{3}{23} ◯ \frac{10}{22} - \frac{5}{22}$ $\frac{9}{10} - \frac{4}{10} ◯ \frac{2}{10} + \frac{1}{10}$
$\frac{17}{18} - \frac{4}{18} ◯ \frac{8}{18} + \frac{5}{18}$ $\frac{3}{16} + \frac{2}{16} ◯ \frac{10}{16} - \frac{2}{16}$ $\frac{9}{13} - \frac{7}{13} ◯ \frac{8}{12} - \frac{6}{12}$
$\frac{6}{17} - \frac{4}{17} ◯ \frac{5}{20} - \frac{3}{20}$ $\frac{11}{35} - \frac{10}{35} ◯ \frac{8}{35} - \frac{7}{35}$ $\frac{11}{16} + \frac{4}{16} ◯ \frac{16}{16} - \frac{1}{16}$
$\frac{4}{11} + \frac{2}{11} ◯ \frac{10}{13} - \frac{4}{13}$ $\frac{10}{16} + \frac{6}{16} ◯ \frac{7}{16} - \frac{2}{16}$ $\frac{10}{17} - \frac{3}{17} ◯ \frac{8}{17} - \frac{1}{17}$

答案

$\frac{3}{11} - \frac{1}{11} > \frac{4}{11} - \frac{3}{11}$ $\frac{8}{9} - \frac{6}{9} > \frac{3}{10} - \frac{1}{10}$ $\frac{8}{20} - \frac{6}{20} < \frac{12}{20} - \frac{9}{20}$
$\frac{4}{11} + \frac{6}{11} > \frac{6}{13} + \frac{4}{13}$ $\frac{8}{23} - \frac{3}{23} < \frac{10}{22} - \frac{5}{22}$ $\frac{9}{10} - \frac{4}{10} > \frac{2}{10} + \frac{1}{10}$
$\frac{17}{18} - \frac{4}{18} = \frac{8}{18} + \frac{5}{18}$ $\frac{3}{16} + \frac{2}{16} < \frac{10}{16} - \frac{2}{16}$ $\frac{9}{13} - \frac{7}{13} < \frac{8}{12} - \frac{6}{12}$
$\frac{6}{17} - \frac{4}{17} > \frac{5}{20} - \frac{3}{20}$ $\frac{11}{35} - \frac{10}{35} = \frac{8}{35} - \frac{7}{35}$ $\frac{11}{16} + \frac{4}{16} = \frac{16}{16} - \frac{1}{16}$
$\frac{4}{11} + \frac{2}{11} > \frac{10}{13} - \frac{4}{13}$ $\frac{10}{16} + \frac{6}{16} > \frac{7}{16} - \frac{2}{16}$ $\frac{10}{17} - \frac{3}{17} = \frac{8}{17} - \frac{1}{17}$