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1. 口算。（建议用时2分钟）
0.9 - 0.09 =
50 ÷ 2.5 =
3.6 × 2 =
4.6 + 6.4 =
7.7 ÷ 3.5 =
2.01 × 0.2 =
14.8 ÷ 8 =
0.65 × 70 =
3.2 + 0.83 =
5.25 ÷ 0.25 =
0.12 × 60 =
12.6 ÷ 0.03 =
116 ÷ 0.4 =
0.8 × 0.05 =
8.71 ÷ 0.1 =
0.5 × 2.2 =
0.26 × 0.3 =
8.08 ÷ 0.4 =
0.13 × 0.5 =
5.04 ÷ 0.3 =
6.3 ÷ 0.9 =
3.4 - 0.6 =
12.6 ÷ 0.3 =
3.8 × 0.3 =
0.9 - 0.09 =
50 ÷ 2.5 =
3.6 × 2 =
4.6 + 6.4 =
7.7 ÷ 3.5 =
2.01 × 0.2 =
14.8 ÷ 8 =
0.65 × 70 =
3.2 + 0.83 =
5.25 ÷ 0.25 =
0.12 × 60 =
12.6 ÷ 0.03 =
116 ÷ 0.4 =
0.8 × 0.05 =
8.71 ÷ 0.1 =
0.5 × 2.2 =
0.26 × 0.3 =
8.08 ÷ 0.4 =
0.13 × 0.5 =
5.04 ÷ 0.3 =
6.3 ÷ 0.9 =
3.4 - 0.6 =
12.6 ÷ 0.3 =
3.8 × 0.3 =
答案
1. 0.81
20
7.2
11
2.2
0.402
1.85
45.5
4.03
21
7.2
420
290
0.04
87.1
1.1
0.078
20.2
0.065
16.8
7
2.8
42
1.14
20
7.2
11
2.2
0.402
1.85
45.5
4.03
21
7.2
420
290
0.04
87.1
1.1
0.078
20.2
0.065
16.8
7
2.8
42
1.14
2. 用竖式计算。(建议用时3分钟)
0.34÷2.5=
6.05×5.2=
23÷3.3=
(得数用循环小数表示)
0.34÷2.5=
6.05×5.2=
23÷3.3=
(得数用循环小数表示)
答案
2. 0.136
31.46
$6.\dot{9}\dot{6}$
31.46
$6.\dot{9}\dot{6}$
3. 计算下面各题，怎样简便就怎样计算。（建议用时3分钟）
8.4×1.01
3－2.25÷1.5×0.7
(31－2.8)÷(1.8＋0.6)
8.4×1.01
3－2.25÷1.5×0.7
(31－2.8)÷(1.8＋0.6)
答案
3. 8.484
1.95
11.75
1.95
11.75
4. 解决问题。(建议用时2分钟)
下表是五(1)班同学摸球试验的结果。(盒子里有三种颜色的球,共摸100次,每次摸后放回)
(1) 推测盒子里(
(2) 如果再摸一次,那么摸到(
(3) 盒子里一共有10个球,估计红球有(
下表是五(1)班同学摸球试验的结果。(盒子里有三种颜色的球,共摸100次,每次摸后放回)
(1) 推测盒子里(
红
)球最多,(蓝
)球最少。(2) 如果再摸一次,那么摸到(
红
)球的可能性最大。(3) 盒子里一共有10个球,估计红球有(
6
)个,黄球有(3
)个,蓝球有(1
)个。答案
4. (1) 红 蓝 (2) 红 (3) 6 3 1
