2025年通城学典初中数学运算能手七年级上册苏科版第50页答案
1. $(-45)+39+(-55)= $

答案

-61

解析

$(-45)+(-55)+39$
$=-100+39$
$=-61$
2. $198-37-63= $

答案

98

解析

198-37-63=198-(37+63)=198-100=98
3. $1\frac {5}{9}+\frac {3}{5}+2\frac {4}{9}+\frac {2}{5}= $

答案

5

解析

$1\frac{5}{9}+2\frac{4}{9}+\frac{3}{5}+\frac{2}{5}$
$=(1+2)+\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{3}{5}+\frac{2}{5}\right)$
$=3+1+1$
$=5$
4. $99×7.4+7.4= $

答案

740

解析

$99×7.4+7.4$
$=7.4×(99+1)$
$=7.4×100$
$=740$
5. $(\frac {2}{3}-\frac {4}{7})×21= $

答案

2

解析

$(\frac{2}{3} - \frac{4}{7}) × 21$
$= \frac{2}{3} × 21 - \frac{4}{7} × 21$
$= 14 - 12$
$= 2$
6. $(-1800)÷25÷4= $

答案

-18

解析

$(-1800)÷25÷4$
$=(-1800)÷(25×4)$
$=(-1800)÷100$
$=-18$
7. $-8×4×(-0.125)= $

答案

4

解析

$-8×4×(-0.125)$
$=(-8)×(-0.125)×4$
$=1×4$
$=4$
8. $9\frac {8}{9}×(-9)= $

答案

-89

解析

$9\frac{8}{9} × (-9)$
$=\left(10 - \frac{1}{9}\right) × (-9)$
$=10 × (-9) - \frac{1}{9} × (-9)$
$=-90 + 1$
$=-89$
9. $(-6)÷(+0.25)÷(-4)$

答案

6

解析

$(-6)÷(+0.25)÷(-4)$
$=(-6)÷\frac{1}{4}÷(-4)$
$=(-6)×4×(-\frac{1}{4})$
$=(-6)×(-1)$
$=6$
10. $\frac {5}{9}+1\frac {5}{7}+\frac {4}{9}+(-\frac {5}{7})$

答案

2

解析

$\frac{5}{9}+\frac{4}{9}+1\frac{5}{7}+(-\frac{5}{7})$
$=(\frac{5}{9}+\frac{4}{9})+(1\frac{5}{7}-\frac{5}{7})$
$=1 + 1$
$=2$
11. $(-\frac {1}{9}-\frac {1}{6}-\frac {1}{18})×36$

答案

-12

解析

$(-\frac{1}{9}-\frac{1}{6}-\frac{1}{18})×36$
$=-\frac{1}{9}×36 - \frac{1}{6}×36 - \frac{1}{18}×36$
$=-4 - 6 - 2$
$=-12$
12. $-9\frac {22}{23}×(-46)$

答案

458

解析

$-9\frac{22}{23} × (-46)$
$=\left(-10 + \frac{1}{23}\right) × (-46)$
$=(-10) × (-46) + \frac{1}{23} × (-46)$
$=460 - 2$
$=458$
13. $-10\frac {1}{7}÷\frac {1}{14}$

答案

-142

解析

$-10\frac{1}{7}÷\frac{1}{14}$
$=-\frac{71}{7}×14$
$=-71×2$
$=-142$
14. $(-15\frac {2}{3})×\frac {5}{6}-2\frac {1}{3}×\frac {5}{6}+10\frac {1}{3}×\frac {5}{6}$

答案

-115/18

解析

$(-15\frac{2}{3})×\frac{5}{6}-2\frac{1}{3}×\frac{5}{6}+10\frac{1}{3}×\frac{5}{6}$
$=\frac{5}{6}×[(-15\frac{2}{3}) - 2\frac{1}{3} + 10\frac{1}{3}]$
$=\frac{5}{6}×[(-15 - \frac{2}{3}) - (2 + \frac{1}{3}) + (10 + \frac{1}{3})]$
$=\frac{5}{6}×[(-15 - 2 + 10) + (-\frac{2}{3} - \frac{1}{3} + \frac{1}{3})]$
$=\frac{5}{6}×(-7 - \frac{2}{3})$
$=\frac{5}{6}×(-\frac{23}{3})$
$=-\frac{115}{18}$
15. $\frac {4}{5}×(-\frac {5}{13})-(-\frac {3}{5})×(-\frac {5}{13})-\frac {5}{13}×(-1\frac {3}{5})$

答案

1/13

解析

$\begin{aligned}&\frac{4}{5} × \left(-\frac{5}{13}\right) - \left(-\frac{3}{5}\right) × \left(-\frac{5}{13}\right) - \frac{5}{13} × \left(-1\frac{3}{5}\right)\\=&\frac{4}{5} × \left(-\frac{5}{13}\right) - \frac{3}{5} × \frac{5}{13} + \frac{5}{13} × \frac{8}{5}\\=&-\frac{4}{13} - \frac{3}{13} + \frac{8}{13}\\=&\left(-\frac{4}{13} - \frac{3}{13}\right) + \frac{8}{13}\\=&-\frac{7}{13} + \frac{8}{13}\\=&\frac{1}{13}\end{aligned}$