1. 直接写出得数。
16 + 27 =
40 ÷ 8 =
91 - 35 =
7 × 6 ÷ 7 =
13 + 18 =
7 × 2 =
27 + 26 =
4 × 2 × 3 =
4 × 6 =
5 × 9 =
35 + 18 =
74 - 50 - 15 =
36 ÷ 6 =
35 - 17 =
63 ÷ 7 =
16 + 16 + 16 =
43 - 16 =
45 + 36 =
75 - 19 =
4 × 8 - 4 =
72 - 25 =
83 - 29 =
4 × 4 =
2 × 2 + 8 =
54 + 17 =
27 + 47 =
25 ÷ 5 =
24 ÷ 3 ÷ 4 =
9 × 9 =
3 × 6 =
65 - 42 =
42 + 18 - 50 =
16 + 27 =
40 ÷ 8 =
91 - 35 =
7 × 6 ÷ 7 =
13 + 18 =
7 × 2 =
27 + 26 =
4 × 2 × 3 =
4 × 6 =
5 × 9 =
35 + 18 =
74 - 50 - 15 =
36 ÷ 6 =
35 - 17 =
63 ÷ 7 =
16 + 16 + 16 =
43 - 16 =
45 + 36 =
75 - 19 =
4 × 8 - 4 =
72 - 25 =
83 - 29 =
4 × 4 =
2 × 2 + 8 =
54 + 17 =
27 + 47 =
25 ÷ 5 =
24 ÷ 3 ÷ 4 =
9 × 9 =
3 × 6 =
65 - 42 =
42 + 18 - 50 =
答案
1. 43 5 56 6
31 14 53 24
24 45 53 9
6 18 9 48
27 81 56 28
47 54 16 12
71 74 5 2
81 18 23 10
31 14 53 24
24 45 53 9
6 18 9 48
27 81 56 28
47 54 16 12
71 74 5 2
81 18 23 10
2. 算一算,比一比,说出你的发现。
19÷6=
25÷6=
31÷6=
3×6+1=
4×6+1=
5×6+1=
发现①:有余数的除法中,商○除数○余数=被除数(在○里填运算符号)。
发现②:余数相等,商增大1时,被除数增大的量与(
19÷6=
25÷6=
31÷6=
3×6+1=
4×6+1=
5×6+1=
发现①:有余数的除法中,商○除数○余数=被除数(在○里填运算符号)。
发现②:余数相等,商增大1时,被除数增大的量与(
除数
)相等。答案
2. 3……1 4……1 5……1
19 25 31
① × +
② 除数
19 25 31
① × +
② 除数
可可有6面旗子,她在每两面相邻旗子之间摆放2个气球,一共需要(

10
)个气球。(用1个○代表1个气球画一画)答案
10
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