把下面的十进制数改写成二进制数。
$(39)_{10}$
$=(32)_{10}+(4)_{10}+(2)_{10}+(1)_{10}$
$=(\_\_\_\_\_\_×\_\_\_\_\_\_×\_\_\_\_\_\_×\_\_\_\_\_\_×\_\_\_\_\_\_)_{10}+(\_\_\_\_\_\_×\_\_\_\_\_\_)_{10}+(\_\_\_\_\_\_)_{10}+(1)_{10}$
$=(\_\_\_\_\_\_)_{2}+(\_\_\_\_\_\_)_{2}+(\_\_\_\_\_\_)_{2}+(\_\_\_\_\_\_)_{2}$
$=(\_\_\_\_\_\_)_{2}$
$(97)_{10}$
$=(64)_{10}+(\_\_\_\_\_\_)_{10}+(\_\_\_\_\_\_)_{10}$
$=(\_\_\_\_\_\_)_{2}+(\_\_\_\_\_\_)_{2}+(\_\_\_\_\_\_)_{2}$
$=(\_\_\_\_\_\_)_{2}$

$(39)_{10}$
$=(32)_{10}+(4)_{10}+(2)_{10}+(1)_{10}$
$=(2×2×2×2×2)_{10}+(2×2)_{10}+(2)_{10}+(1)_{10}$
$=(100000)_{2}+(100)_{2}+(10)_{2}+(1)_{2}$
$=(100111)_{2}$
$(97)_{10}$
$=(64)_{10}+(32)_{10}+(1)_{10}$
$=(1000000)_{2}+(100000)_{2}+(1)_{2}$
$=(1100001)_{2}$

例3 十二进制是以12为基数的计数进位制度，满12进1，记作符号（$\boldsymbol{}$）$_{12}$。计数符号：0，1，2，3，4，5，6，7，8，9，A，B（A代表10，B代表11）。你能将十二进制数$(1A)_{12}$改写成十进制数吗？

1×12 + 10 = 22
答：改写成的十进制数是22。