1. 口算。(建议用时4分钟)
$0.4 + 40\% =$
$1 - 80\% =$
$4 × 40\% =$
$0.5 × 50\% =$
$8 × 15\% =$
$18\% × 3 =$
$40 × 25\% =$
$6 ÷ 30\% =$
$45\% × 6 =$
$4.5\% × 20 =$
$120 ÷ 50\% =$
$75\% × 6 =$
$\frac{1}{3} - \frac{2}{9} =$
$\frac{8}{9} ÷ \frac{20}{27} =$
$1 - \frac{14}{15} =$
$6 × \frac{1}{3} =$
$\frac{5}{6} ÷ 10 =$
$21 ÷ \frac{3}{7} =$
$\frac{14}{15} × \frac{2}{3} =$
$\frac{15}{19} ÷ \frac{5}{38} =$
$35\% × 5 =$
$\frac{5}{7} + \frac{2}{7} =$
$\frac{5}{3} × 30\% =$
$60 × \frac{1}{12} =$
$0.4 + 40\% =$
$1 - 80\% =$
$4 × 40\% =$
$0.5 × 50\% =$
$8 × 15\% =$
$18\% × 3 =$
$40 × 25\% =$
$6 ÷ 30\% =$
$45\% × 6 =$
$4.5\% × 20 =$
$120 ÷ 50\% =$
$75\% × 6 =$
$\frac{1}{3} - \frac{2}{9} =$
$\frac{8}{9} ÷ \frac{20}{27} =$
$1 - \frac{14}{15} =$
$6 × \frac{1}{3} =$
$\frac{5}{6} ÷ 10 =$
$21 ÷ \frac{3}{7} =$
$\frac{14}{15} × \frac{2}{3} =$
$\frac{15}{19} ÷ \frac{5}{38} =$
$35\% × 5 =$
$\frac{5}{7} + \frac{2}{7} =$
$\frac{5}{3} × 30\% =$
$60 × \frac{1}{12} =$
答案
0.8
0.2
1.6
0.25
1.2
0.54
10
20
2.7
0.9
240
4.5
$\frac{1}{9}$
$\frac{6}{5}$
$\frac{1}{15}$
2
$\frac{1}{12}$
49
$\frac{28}{45}$
6
1.75
1
0.5
5
0.2
1.6
0.25
1.2
0.54
10
20
2.7
0.9
240
4.5
$\frac{1}{9}$
$\frac{6}{5}$
$\frac{1}{15}$
2
$\frac{1}{12}$
49
$\frac{28}{45}$
6
1.75
1
0.5
5
2. 求出下面各题的商。(结果用百分数表示,除不尽的百分号前保留一位小数)(建议用时2分钟)
15÷80
(100−5)÷150
(71+2)÷250
15÷80
(100−5)÷150
(71+2)÷250
答案
18.75%
63.3%
29.2%
63.3%
29.2%
3. 计算下面各题,能用简便算法的就用简便算法。(建议用时2分钟)
$30×(\dfrac{2}{5}+\dfrac{1}{6})$
$\dfrac{13}{12}-(\dfrac{1}{12}+20\%)$
$(\dfrac{1}{3}-\dfrac{1}{4})÷50\%+\dfrac{5}{6}$
$30×(\dfrac{2}{5}+\dfrac{1}{6})$
$\dfrac{13}{12}-(\dfrac{1}{12}+20\%)$
$(\dfrac{1}{3}-\dfrac{1}{4})÷50\%+\dfrac{5}{6}$
答案
17
$\frac{4}{5}$
1
$\frac{4}{5}$
1
4. 解决问题。(建议用时2分钟)
旬邑苹果具有“个大、形正、色艳、质脆、汁丰、甜香、耐贮藏、无污染”八大特点,深受消费者青睐。果鲜商店有40箱旬邑苹果,已经卖出了总箱数的40%,还剩多少箱旬邑苹果?
旬邑苹果具有“个大、形正、色艳、质脆、汁丰、甜香、耐贮藏、无污染”八大特点,深受消费者青睐。果鲜商店有40箱旬邑苹果,已经卖出了总箱数的40%,还剩多少箱旬邑苹果?
答案
$1-40\%=60\%$
$40×60\%=24$(箱)
$40×60\%=24$(箱)
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