2026年初中运算计算升级卡七年级数学上册人教版第25页答案
5. 计算:
(1) $-2÷8×(-12)$;
(2) $-2^2 - (-3)^3×(-\frac{1}{9})+1$;
(3) $-7 -2÷(-\frac{1}{2})+3$;
(4) $(-3^4)×\frac{4}{9}+(-16)$;
(5) $(\frac{1}{4}+\frac{1}{6}-\frac{1}{2})×(-12)$;
(6) $-1^4 + (-2)^2 - |2-5| +6×(\frac{1}{2}-\frac{1}{3})$;
(7) $-2^2×(-9)+16÷(-2)^3 - |-4×5|$;
(8) $-2^2×(-3)÷(-\frac{2}{3})^2 -20×(\frac{3}{4}-\frac{4}{5}+\frac{7}{10})$;
(9) $-1^2 + |-2-1|÷6×(\frac{1}{3}-\frac{1}{2})$;
(10) $26 - (\frac{7}{9}-\frac{11}{12}+\frac{1}{18})×(-6)^2$;
(11) $-17.21+(-33.8)-(-8)+42$;
(12) $(-48)÷8 - (-15)×(-6)$;
(13) $-1^{2020} - [(-4)×(3^2 -2^3)]÷\frac{4}{5}$;
(14) $-14 + |3-5| -8÷(-2)×\frac{1}{2}$;
(15) $-4^2 +1\frac{5}{6}÷\left|-\frac{11}{3}\right|×(\frac{1}{2}-2)^2$;
(16) $\left|-6\frac{3}{8}-2\frac{1}{2}\right| + (-8\frac{7}{8}) + \left|-3-\frac{1}{2}\right|$;
(17) $(-2^2)+(-3)×(-1)^6 - (-2)$;
(18) $-3^2 +3×(-1)^{2019} - (\frac{3}{8}+\frac{1}{6}-\frac{3}{4})×(-2)^3$;
(19) $(-2008\frac{5}{6})+(-2009\frac{2}{3})+4018\frac{2}{3}+(-1\frac{1}{2})$;
(20) $2×(-\frac{4}{9})+1.53×\frac{4}{9}-9.47×(-\frac{4}{9})-(\frac{7}{9}-\frac{5}{6}+\frac{1}{4}-\frac{1}{18})×72$;

答案

5.(1)3 (2)-6 (3)0 (4)-52 (5)1 (6)1 (7)14 (8)14 (9)$-1\dfrac{1}{12}$ (10)29 (11)-1.01 (12)-96 (13)4 (14)-10 (15)$-14\dfrac{7}{8}$ (16)$3\dfrac{1}{2}$ (17)-5 (18)$-13\dfrac{2}{3}$ (19)$-\dfrac{4}{3}$ (20)-6