1. 直接写出得数。
$0.36÷0.3=$
$4.5-0.45=$
$6.5+6.5=$
$7.8×8.9×0=$
$\frac{2}{3}+\frac{1}{2}=$
$0.08×5=$
$0.05×1.2=$
$3÷\frac{1}{3}×3=$
$0.99÷3=$
$0.13×0.4=$
$61.8÷6=$
$8.4×9+8.4=$
$15÷\frac{5}{3}=$
$6÷\frac{24}{25}=$
$\frac{5}{6}-\frac{1}{8}=$
$12÷(\frac{1}{3}-\frac{1}{4})=$
$\frac{1}{9}×3.6=$
$\frac{3}{8}+\frac{1}{7}=$
$\frac{4}{11}×2\frac{3}{4}=$
$1.32÷0.25÷4=$
$\frac{11}{18}×6=$
$\frac{3}{14}÷\frac{3}{7}=$
$18÷2\frac{4}{7}=$
$(7.4-2.4)×3.14=$
$0.36÷0.3=$
$4.5-0.45=$
$6.5+6.5=$
$7.8×8.9×0=$
$\frac{2}{3}+\frac{1}{2}=$
$0.08×5=$
$0.05×1.2=$
$3÷\frac{1}{3}×3=$
$0.99÷3=$
$0.13×0.4=$
$61.8÷6=$
$8.4×9+8.4=$
$15÷\frac{5}{3}=$
$6÷\frac{24}{25}=$
$\frac{5}{6}-\frac{1}{8}=$
$12÷(\frac{1}{3}-\frac{1}{4})=$
$\frac{1}{9}×3.6=$
$\frac{3}{8}+\frac{1}{7}=$
$\frac{4}{11}×2\frac{3}{4}=$
$1.32÷0.25÷4=$
$\frac{11}{18}×6=$
$\frac{3}{14}÷\frac{3}{7}=$
$18÷2\frac{4}{7}=$
$(7.4-2.4)×3.14=$
答案
1.2 4.05 13 0
$\frac{7}{6}$ 0.4 0.06 27
0.33 0.052 10.3 84
9 $\frac{25}{4}$ $\frac{17}{24}$ 144
0.4 $\frac{29}{56}$ 1 1.32
$\frac{11}{3}$ $\frac{1}{2}$ 7 15.7
$\frac{7}{6}$ 0.4 0.06 27
0.33 0.052 10.3 84
9 $\frac{25}{4}$ $\frac{17}{24}$ 144
0.4 $\frac{29}{56}$ 1 1.32
$\frac{11}{3}$ $\frac{1}{2}$ 7 15.7
2. 用竖式计算。
28.67 ÷ 9.4 =
8.04 × 1.84 ≈
(得数保留一位小数)
7.257 ÷ 3.54 =
28.67 ÷ 9.4 =
8.04 × 1.84 ≈
(得数保留一位小数)
7.257 ÷ 3.54 =
答案
3.05 14.8 2.05
竖式略
竖式略
3. 计算下面各题,怎样算简便就怎样算。
17.46+18.2-7.46+2.8
3.61×9.9+3.61×0.1
1.2×[(5/6 + 3/2)÷4/3]
17.46+18.2-7.46+2.8
3.61×9.9+3.61×0.1
1.2×[(5/6 + 3/2)÷4/3]
答案
31 36.1 2.1
计算:$\frac{1}{3} - \frac{1}{12} - \frac{1}{20} - \frac{1}{30} - \frac{1}{42} - \frac{1}{56} - \frac{1}{8}$。
答案
原式$=\frac{1}{3} - \frac{1}{3×4} - \frac{1}{4×5} - \frac{1}{5×6}$
$-\frac{1}{6×7} - \frac{1}{7×8} - \frac{1}{8} =\frac{1}{3}-$
$(\frac{1}{3}-\frac{1}{4}) - (\frac{1}{4}-\frac{1}{5}) -$
$(\frac{1}{5}-\frac{1}{6}) - (\frac{1}{6}-\frac{1}{7}) -$
$(\frac{1}{7}-\frac{1}{8})-\frac{1}{8}=\frac{1}{3}-\frac{1}{3}+\frac{1}{4}$
$-\frac{1}{4}+\frac{1}{5}-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}$
$-\frac{1}{7}+\frac{1}{8}-\frac{1}{8}=0$
$-\frac{1}{6×7} - \frac{1}{7×8} - \frac{1}{8} =\frac{1}{3}-$
$(\frac{1}{3}-\frac{1}{4}) - (\frac{1}{4}-\frac{1}{5}) -$
$(\frac{1}{5}-\frac{1}{6}) - (\frac{1}{6}-\frac{1}{7}) -$
$(\frac{1}{7}-\frac{1}{8})-\frac{1}{8}=\frac{1}{3}-\frac{1}{3}+\frac{1}{4}$
$-\frac{1}{4}+\frac{1}{5}-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}$
$-\frac{1}{7}+\frac{1}{8}-\frac{1}{8}=0$
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