2026年实验班提优训练五年级英语上册译林版第127页答案
(
C
)1. Mike is standing in Group One. There are fifteen students in front of him and thirteen students behind him. How many students are there in Group One?

A.Twenty-eight.
B.Twenty-seven.
C.Twenty-nine.

答案

1.C 题意为“迈克站在第一组,在他前面有15个学生,在他后面有13个学生,那么第一组共有多少学生”。根据题目列式:$15+13+1=29$,故选C。
(
A
)2. Mary is eight years old. Her father is four times as old as her. Her grandfather is twice(两倍) as old as her father. How old is her grandfather? He is
sixty-four
.

A.sixty-four
B.forty-eight
C.ninety-six

答案

2.A 该题要理解“Her father is four times as old as her(她爸爸的年龄是她的四倍)”,故爸爸年龄为32。根据“Her grandfather is twice as old as her father(她爷爷的年龄是她爸爸的两倍)”可知,爷爷年龄为64,故选A。
(
C
)3. Lucy goes out for a walk from her home. She walks 4 km east, 3 km south and 4 km west. How far is she from her home now?

A.11 km.
B.4 km.
C.3 km.

答案

3.C 题中“She walks 4 km east, 3 km south and 4 km west”意为“她向东走了4公里,向南走了3公里,向西走了4公里”,画图可知,她离她家有3公里,故选C。
(
B
)4. There are four balls on the table. The blue ball is next to the red ball but not next to the yellow ball. The green ball is not next to the yellow ball or the red ball.
What ball is next to the green ball?

A.The red ball.
B.The blue ball.
C.The red and the blue ball.

答案

4.B 题意为“桌上有四个球,蓝球在红球旁边但不在黄球旁边,绿球既不在黄球旁边,也不在红球旁边,那么什么球在绿球旁边”,理解题意后可知答案为B。
二、读一读,算一算。
1. How can you make 6 out of three 7s?
7
-
7
÷
7=6
2. Ann and Bill have five sweets together. Bill and Clare have four sweets together. Clare and Ann have three sweets together. So Ann has
two/2
sweet(s). Bill has
three/3
sweet(s). Clare has
one/1
sweet (s). Ann, Bill and Clare have
six/6
sweets together.
3. My grandpa gives me 10 dollars to share with my sister and brother. He tells me to take 2 dollars more than my brother and 3 dollars more than my sister. So I keep
five/5
dollars.
4. The letters A, B, C and D stand for four different numbers. The numbers are all positive integers(正整数). What numbers are they?
(1) A=
1
B=
4
C=
6
D=
5

(2) A=
3
B=
6
C=
4
D=
1

答案

1. $7-7÷7=6$
2. two/2,three/3,one/1,six/6
3. five/5
4. (1)$A=1\quad B=4\quad C=6\quad D=5$
(2)$A=3\quad B=6\quad C=4\quad D=1$