2026年学霸计算达人六年级数学上册北师大版第115页答案
1. 直接写出得数。
$\frac{7}{13}÷3=$
$\frac{1}{8}+\frac{1}{16}=$
$\frac{7}{25}×50=$
$\frac{1}{2}-\frac{3}{14}=$
$\frac{7}{32}÷\frac{7}{16}=$
$\frac{7}{10}+\frac{8}{5}=$
$\frac{11}{8}×\frac{4}{55}=$
$\frac{7}{10}-\frac{1}{10}=$
$\frac{15}{22}÷\frac{25}{22}=$
$\frac{1}{16}+\frac{3}{4}=$
$\frac{7}{25}×\frac{25}{9}=$
$\frac{4}{3}-\frac{2}{9}=$
$\frac{1}{3}÷\frac{1}{5}=$
$\frac{1}{3}+\frac{8}{9}=$
$48\%×\frac{1}{8}=$
$\frac{22}{15}-\frac{4}{3}=$
$\frac{35}{99}÷\frac{35}{11}=$
$\frac{13}{4}+\frac{3}{4}=$
$\frac{5}{12}×4=$
$6\frac{3}{10}-6.3=$
$1÷\frac{14}{9}=$
$\frac{1}{2}+\frac{3}{8}=$
$\frac{7}{11}×4.4=$
$\frac{1}{2}-\frac{1}{14}=$
$10÷\frac{5}{9}=$
$\frac{2}{3}+\frac{5}{6}=$
$4.8×\frac{5}{8}=$
$\frac{5}{7}-\frac{1}{3}=$
$\frac{3}{8}÷\frac{11}{8}=$
$\frac{1}{9}+\frac{5}{7}=$
$\frac{3}{10}×3=$
$1-\frac{5}{7}=$
$\frac{8}{9}÷\frac{2}{3}=$
$\frac{3}{8}+\frac{5}{16}=$
$54×\frac{2}{9}=$
$\frac{5}{9}-\frac{1}{3}=$
$\frac{12}{11}÷6=$
$\frac{9}{14}+\frac{4}{7}=$
$\frac{13}{9}×\frac{27}{26}=$
$2-\frac{5}{3}=$

答案

1. $\frac{7}{39}$ $\frac{3}{16}$ $14$ $\frac{2}{7}$
$\frac{1}{2}$ $\frac{23}{10}$ $\frac{1}{10}$ $\frac{3}{5}$
$\frac{3}{5}$ $\frac{13}{16}$ $\frac{7}{9}$ $\frac{10}{9}$
$\frac{5}{3}$ $\frac{11}{9}$ $\frac{3}{50}$ $\frac{2}{15}$
$\frac{1}{9}$ $4$ $\frac{5}{3}$ $0$
$\frac{9}{14}$ $\frac{7}{8}$ $\frac{14}{5}$ $\frac{3}{7}$
$18$ $\frac{3}{2}$ $3$ $\frac{8}{21}$
$\frac{3}{11}$ $\frac{52}{63}$ $\frac{9}{10}$ $\frac{2}{7}$
$\frac{4}{3}$ $\frac{11}{16}$ $12$ $\frac{2}{9}$
$\frac{2}{11}$ $\frac{17}{14}$ $\frac{3}{2}$ $\frac{1}{3}$
2. 计算下面各题。
$\frac{3}{7}×\frac{5}{4}+\frac{3}{7}×\frac{3}{4}$
$\frac{14}{19}×\frac{2}{7}×19$
$\frac{5}{18}×[ ( \frac{7}{9}-\frac{1}{3} )÷\frac{1}{27} ]$
$[ \frac{3}{4}-( \frac{3}{7}-\frac{1}{4} ) ]÷\frac{16}{21}$
$\frac{9}{4}×( \frac{5}{8}÷\frac{27}{32} )$
$( \frac{5}{12}-\frac{3}{8}+\frac{1}{4} )×48$
$\frac{7}{8}×\frac{3}{4}+\frac{1}{8}×\frac{7}{4}$
$\frac{36}{41}÷\frac{4}{3}÷\frac{9}{4}$
$\frac{1}{7}×\frac{3}{4}+\frac{13}{7}×\frac{3}{4}-0.75$
$( \frac{2}{7}+\frac{1}{5} )×7×5$
$5+\frac{12}{13}×( 2.5-\frac{1}{3} )$
$\frac{10}{9}÷[ \frac{5}{12}×( \frac{6}{5}-\frac{2}{3} ) ]$
$\frac{7}{8}+\frac{1}{8}÷\frac{3}{4}$
$7÷\frac{13}{24}÷\frac{12}{13}$
$( 1-\frac{2}{5}-\frac{1}{6} )÷\frac{1}{30}$
$\frac{3}{8}+( 2\frac{1}{15}-\frac{3}{8} )$
$18÷\frac{3}{7}÷\frac{14}{3}$
$19×\frac{5}{8}+19×\frac{3}{8}$
$\frac{5}{6}×\frac{2}{7}÷\frac{5}{12}$
$\frac{3}{8}÷\frac{1}{10}×\frac{7}{5}$
$36÷( \frac{1}{3}×\frac{1}{4} )$

答案

2. $\frac{6}{7}$ $4$ $\frac{10}{3}$
$\frac{3}{4}$ $\frac{5}{3}$ $14$
$\frac{7}{8}$ $\frac{12}{41}$ $\frac{3}{4}$
$17$ $7$ $5$
$\frac{25}{24}$ $14$ $13$
$\frac{31}{15}$ $9$ $19$
$\frac{4}{7}$ $\frac{21}{4}$ $432$